Chapter 9: Problem 57
Why is the actual yield of a reaction often not equal to the theoretical yield?
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Chapter 9: Problem 57
Why is the actual yield of a reaction often not equal to the theoretical yield?
These are the key concepts you need to understand to accurately answer the question.
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For the reaction \(\mathrm{Ca}_{3} \mathrm{P}_{2}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{PH}_{3}\), (a) Balance the equation. (b) How many grams of \(\mathrm{H}_{2} \mathrm{O}\) would you need to react with \(60.0 \mathrm{~g}\) of \(\mathrm{Ca}_{3} \mathrm{P}_{2} ?\) (c) How many grams of \(\mathrm{PH}_{3}\) could theoretically be produced from the reactant amounts calculated in part (b)?
Saccharin, which is used as an artificial sweetener, is made up of \(45.90 \%\) by mass \(C, 2.75 \%\) by mass \(\mathrm{H}, 26.20 \%\) by mass \(\mathrm{O}, 7.65 \%\) by mass \(\mathrm{N}\), and \(17.50 \%\) by mass \(\mathrm{S}\). If the molar mass of saccharin is \(183.19 \mathrm{~g} / \mathrm{mol}\), what is its molecular formula?
The ingredients for making 1 dozen cupcakes are: 5 tablespoons butter 1 cup sugar 2 eggs 2 cups flour 1 cup milk If you have only 5 eggs but plenty of all of the other ingredients: (a) How many cupcakes can you make? (b) How many cups of sugar do you need to make the number of cupcakes calculated in (a)?
\(5.00 \mathrm{~g}\) of solid sodium (Na) and \(30.0 \mathrm{~g}\) of liquid bromine \(\left(\mathrm{Br}_{2}\right)\) react to form solid \(\mathrm{NaBr}\). (a) Write a balanced chemical equation for this reaction. (b) Which reactant is limiting? (c) What is the theoretical yield for this reaction in grams? (d) How many grams of excess reactant are left over at the end of the reaction? (e) When this reaction is actually performed, \(14.7 \mathrm{~g}\) of \(\mathrm{NaBr}\) is recovered. What is the percent yield of the reaction?
Consider the unbalanced chemical equation \(\mathrm{KCl}+\mathrm{O}_{2} \rightarrow \mathrm{KClO}_{3}\) If you react \(42.6 \mathrm{~g}\) of \(\mathrm{KCl}\) and \(36.5 \mathrm{~g}\) of \(\mathrm{O}_{2}\) and the reaction has a percent yield of \(56.0 \%\), how many grams of \(\mathrm{KClO}_{3}\) are produced?
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