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Translate the following balanced equation into words, first without using the word moles, then again with the word moles: \(2 \mathrm{SO}_{2}+\mathrm{O}_{2} \rightarrow 2 \mathrm{SO}_{3}\)

Short Answer

Expert verified
Two molecules of sulfur dioxide react with one molecule of oxygen gas to produce two molecules of sulfur trioxide. Alternatively, two moles of sulfur dioxide react with one mole of oxygen gas to produce two moles of sulfur trioxide.

Step by step solution

01

Translate the equation without using the word "moles"

Two molecules of sulfur dioxide react with one molecule of oxygen gas to produce two molecules of sulfur trioxide.
02

Translate the equation using the word "moles"

Two moles of sulfur dioxide react with one mole of oxygen gas to produce two moles of sulfur trioxide.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is the branch of chemistry that deals with the quantitative relationships of the reactants and products in a chemical reaction. It is like a mathematical recipe for chemistry: just as you'd use a recipe to determine how much flour, sugar, and butter you need to make cookies, stoichiometry lets you calculate precisely how much of each chemical is needed to react completely in a chemical reaction.

For example, consider the reaction mentioned in the exercise:
When it says 'two molecules of sulfur dioxide react with one molecule of oxygen gas to produce two molecules of sulfur trioxide', we are simply reading the 'recipe' provided by the balanced equation. If we incorporate the concept of moles, this translates to a stoichiometric relationship: for every two moles of sulfur dioxide, we need one mole of oxygen gas to produce two moles of sulfur trioxide. This stoichiometric relationship is fundamental to ensuring that a chemical reaction proceeds as intended and is particularly useful when scaling reactions up from the laboratory to industrial production, or when trying to predict the yield of a reaction.
Molecular Reaction
A molecular reaction, at its core, involves the breaking and forming of chemical bonds. This process results in the transformation of substances into different substances. Reactions are described by chemical equations that show the reactants on the left side, the products on the right, and an arrow indicating the direction of the reaction.

The previous exercise mentioned the chemical equation \begin{align*}2 \text{SO}_{2} + \text{O}_{2} &\rightarrow 2 \text{SO}_{3}.\begin{align*}This represents a molecular reaction where two molecules of sulfur dioxide (\text{SO}\(_2\)) and one molecule of oxygen gas (\text{O}\(_2\)) react to form two molecules of sulfur trioxide (\text{SO}\(_3\)). The balancing of the equation reflects the conservation of atoms—no atoms are lost or gained in the reaction, which is a fundamental principle of chemical reactions known as the Law of Conservation of Mass. Understanding how molecules interact in a reaction, their structural changes, and the energy involved is critical for comprehending chemical processes and for the practical application in fields like biochemistry, pharmacology, and materials science.
Mole Concept
The mole concept is a bridge between the microscopic world of atoms and molecules and the macroscopic world we see around us. It allows chemists to count atoms and molecules by weighing them. A mole is defined as the amount of substance that contains as many entities (atoms, molecules, ions, etc.) as there are atoms in 12 grams of pure carbon-12, which is approximately \(6.022 \times 10^{23}\) entities, a number known as Avogadro's number.

In the exercise, the term 'mole' serves to quantify the amount of reactants and products in the chemical equation. When we say 'two moles of sulfur dioxide', it means we have \(2 \times (6.022 \times 10^{23})\) molecules of sulfur dioxide. The mole concept is essential for stoichiometry since it establishes a relationship between mass and number of entities, enabling chemists to measure substances with precision. It is also indispensable in chemical calculations, allowing for the conversion between mass, moles, and number of particles, all of which are crucial for understanding and performing chemical reactions accurately.

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Most popular questions from this chapter

A gaseous mixture containing \(10.079 \mathrm{~g}\) of \(\mathrm{H}_{2}\) and \(7.00\) moles of \(\mathrm{Br}_{2}\) react to form HBr. (a) Write a balanced chemical equation for this reaction. (b) Which reactant is limiting? (c) What is the theoretical yield for this reaction in moles? (d) What is the theoretical yield for this reaction in grams? (e) How many moles of excess reactant are left over at the end of the reaction? (f) How many grams of excess reactant are left over at the end of the reaction?

Consider the unbalanced chemical equation \(\mathrm{CaC}_{2}+\mathrm{CO} \rightarrow \mathrm{C}+\mathrm{CaCO}_{3}\) When the reaction is complete, \(135.4 \mathrm{~g}\) of \(\mathrm{CaCO}_{3}\) produced and \(38.5 \mathrm{~g}\) of \(\mathrm{CaC}_{2}\) is left over. Assuming the reaction had a \(100 \%\) yield, what were the mass of the two reactants at the beginning of the reaction

The hormone estradiol contains carbon, hydrogen, and oxygen and has a molar mass of approximately \(272 \mathrm{~g} / \mathrm{mol}\). When \(1.15 \mathrm{~g}\) of estradiol is subjected to combustion analysis, the results yield \(79.26 \% \mathrm{C}\) and \(8.88 \% \mathrm{H}\). What is its molecular formula?

(a) What is the molar mass of ribose \(\left(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{5}\right)\) ? (b) What is the mass of \(3.87\) moles of ribose? (c) How many ribose molecules are there in \(3.87\) moles? (d) How many oxygen atoms are there in \(3.87\) moles of ribose? (e) What is the mass in grams of the oxygen atoms in part (d)?

Consider the unbalanced chemical equation \(\mathrm{Al}_{2} \mathrm{~S}_{3}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{Al}(\mathrm{OH})_{3}+\mathrm{H}_{2} \mathrm{~S}\) If \(56.0 \mathrm{~g}\) of aluminum sulfide reacts with \(48.2 \mathrm{~g}\) of water, (a) Which is the excess reactant? (b) What mass in grams of the excess reactant remains after the reaction is complete?

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