/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 The bond distance in an \(\mathr... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 5: Problem 61

The bond distance in an \(\mathrm{H}_{2}\) molecule is \(0.74 \AA\). Why isn't it shorter than this? Why isn't it longer than this?

Short Answer

Expert verified
In the H鈧� molecule, the bond distance is 0.74 脜 because it represents the equilibrium distance at which attractive electrostatic forces between the positive nucleus of one atom and the negative electrons of the other atom balance with repulsive forces between positive nuclei and negative electrons. At this distance, the overall potential energy of the system is minimized, resulting in a stable bond. If the bond distance were shorter or longer, the potential energy would increase, making the molecule unstable.

Step by step solution

01

Introducing the concept of bond distance

A bond distance represents the equilibrium distance between the nuclei of two atoms involved in a chemical bond. At this distance, the attractive forces between the positive nucleus of one atom and the negative electrons of the other atom balance with the repulsive forces between the positive nuclei and the negative electrons.
02

Electrostatic attraction forces

Electrostatic attraction forces arise between the positive nucleus of one atom and the electrons of another atom. As the atoms get closer, the electrostatic attraction forces become stronger, resulting in a decrease in the potential energy of the system. Therefore, atoms tend to get closer to each other to minimize their potential energy.
03

Electrostatic repulsion forces

Electrostatic repulsion forces occur between the positive nuclei of both atoms and between the negative electrons. As the atoms get closer, the repulsion forces become stronger, and the potential energy of the system increases.
04

Equilibrium bond distance

The equilibrium bond distance occurs when the attractive forces between the nuclei of two atoms and the electrons balance the repulsive forces between the positive nuclei and the negative electrons. This balance minimizes the overall potential energy of the system, creating a stable bond.
05

Why the bond distance of H鈧� is not shorter

If the bond distance between the two hydrogen atoms were shorter than 0.74 脜, the electrostatic repulsion forces between the positive nuclei of the hydrogen atoms and between their negative electrons would increase. As a result, the potential energy of the system would increase, making H鈧� unstable at this shorter distance.
06

Why the bond distance of H鈧� is not longer

If the bond distance between the two hydrogen atoms were longer than 0.74 脜, the electrostatic attraction forces would become weaker, resulting in an increase in potential energy. This increased potential energy would make the H鈧� molecule unstable at a longer distance. In conclusion, the bond distance in an H鈧� molecule is 0.74 脜 because it represents the equilibrium distance where the attractive and repulsive electrostatic forces balance, resulting in a stable bond with minimized overall potential energy.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Bond
A chemical bond is a lasting attraction between atoms that enables the formation of chemical compounds. These bonds occur due to the electrostatic forces of attraction and repulsion between the involved electrons and nuclei.

Atoms form bonds in such a way as to minimize their potential energy, leading to a more stable configuration. The type of chemical bond formed鈥攂e it ionic, covalent, metallic, or hydrogen bonding鈥攄epends on the elements involved and the conditions under which they combine.

For instance, when two hydrogen atoms bond, they share their electrons to fill up their electron shells, achieving a stable electronic arrangement similar to that of noble gases.
Electrostatic Attraction
Electrostatic attraction is a force that draws positively charged particles, like the nucleus of an atom, towards negatively charged particles, such as electrons. This fundamental force is what keeps electrons in orbit around the nucleus.

As two atoms approach each other, their respective positive and negative charges attract, pulling the atoms closer. This effect is critical in the formation of chemical bonds, as it helps to decrease the potential energy of the system, leading to a more favorable, lower-energy state.
Equilibrium Bond Length
The equilibrium bond length is the ideal distance between the nuclei of two bonded atoms where the forces of attraction and repulsion are perfectly balanced. At this precise point, the chemical bond is the most stable, and the potential energy of the system is at its minimum.

Any deviation from this length鈥攅ither shorter or longer鈥攔esults in increased potential energy and instability. The equilibrium bond length varies for different types of bonds and is characteristic of each particular molecule, as seen in the specific 0.74 脜 length for the hydrogen molecule (H鈧�).
Electrostatic Repulsion
Electrostatic repulsion is the force that pushes apart like-charged particles, such as the positively charged nuclei of two atoms or the negatively charged electrons. When the distance between two atoms decreases, the repulsion between like charges increases.

This increase in repulsion can prevent two atoms from getting too close, as it would result in an increase in the potential energy, leading away from an energetically favorable state. Consequently, there is a balancing act between electrostatic attraction and repulsion to reach the equilibrium bond length.
Potential Energy
Potential energy is the stored energy in a system due to the positioning or structure of its components. In the context of chemical bonds, potential energy refers to the energy due to the electrostatic interactions between atomic particles.

Chemical systems naturally evolve towards configurations with lower potential energy, which are inherently more stable. The bond distance in molecules corresponds to a 'sweet spot' where this energy is minimized, leading to the most stable arrangement and thus defining the equilibrium bond length.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Students commonly confuse ammonia with ammonium. (a) Write the formula and draw dot diagrams for both species, and describe the difference between them. (b) Based on your answer to (a), write the formulas for phosphine and phosphonium, complete with charges if there are any.

The use of chlorofluorocarbons (CFCs) in airconditioning and refrigeration systems has been linked to depletion of the ozone layer of the atmosphere. One of the most widely used CFCs, freon-12, has the formula \(\mathrm{CF}_{2} \mathrm{Cl}_{2}\). It is now being replaced with a compound that has the formula \(\mathrm{CH}_{2} \mathrm{FCH}_{3}\). Draw the dot diagrams for \(\mathrm{CF}_{2} \mathrm{Cl}_{2}\) and \(\mathrm{C} \mathrm{H}_{2} \mathrm{FCH}_{3}\). (Hint: In \(\mathrm{CH}_{2} \mathrm{FCH}_{3}\), the carbons bond to each other, and one of them bonds to fluorine.)

Many acids can be thought of as anions that have an \(\mathrm{H}^{+}\) ion attached to them. Fill in the following table: \begin{tabular}{|l|l|l|l|} \hline Anion & Anion name & Acid formula & Acid name \\ \hline \(\mathrm{F}^{-}\) & & & \\ \hline \(\mathrm{NO}_{3}^{-}\) & & & \\ \hline \(\mathrm{Cl}^{-}\) & & & \\ \hline \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}^{-}\) & & & \\ \hline \(\mathrm{NO}_{2}^{-}\) & & & \\ \hline \end{tabular}

The phosphorus atom in \(\mathrm{PCl}_{3}\) should have a (a) \(\delta^{+}\) charge (b) \(\delta^{-}\) charge (c) \(3+\) charge (d) 3 - charge Explain.

Using only the periodic table, determine which bond in each pair is more ionic: (a) \(\mathrm{H}-\mathrm{F}\) or \(\mathrm{H}-\mathrm{Cl}\) (b) \(\mathrm{O}-\mathrm{F}\) or \(\mathrm{C}-\mathrm{F}\)
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

The Earths Atmosphere

Read Explanation

Inorganic Chemistry

Read Explanation

Organic Chemistry

Read Explanation

Making Measurements

Read Explanation

Chemical Reactions

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.