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True or false? The \(\mathrm{O}^{2-}\) and \(\mathrm{F}^{-}\) anions have identical electron configurations. Justify your answer with Bohr diagrams and electron configuration notation.

Short Answer

Expert verified
True. The O虏鈦 and F鈦 anions have identical electron configurations, as both have the electron configuration 1s虏2s虏2p鈦. The Bohr diagrams of both anions also show the same number of electrons in each energy level, with 2 electrons in the first energy level (1s虏) and 8 electrons in the second energy level (2s虏2p鈦).

Step by step solution

01

1. Electron Configuration of O虏鈦 Ion

First, let's find the electron configuration for O虏鈦 ion. An oxygen atom has 8 electrons, and its electron configuration is 1s虏2s虏2p鈦. However, the O虏鈦 ion has gained 2 extra electrons, making it a total of 10 electrons. Therefore, we need to find the electron configuration with 10 electrons. 1s虏2s虏2p鈦 So, the electron configuration of O虏鈦 anion is 1s虏2s虏2p鈦.
02

2. Electron Configuration of F鈦 Ion

Next, let's find the electron configuration for F鈦 ion. A fluorine atom has 9 electrons, so its electron configuration is 1s虏2s虏2p鈦. However, the F鈦 ion has gained 1 extra electron, making it a total of 10 electrons. Therefore, we need to find the electron configuration with 10 electrons. 1s虏2s虏2p鈦 So, the electron configuration of F鈦 anion is 1s虏2s虏2p鈦.
03

3. Comparison of Electron Configurations

Now that we have the electron configurations for both O虏鈦 and F鈦 anions, let's compare them: O虏鈦: 1s虏2s虏2p鈦 F鈦: 1s虏2s虏2p鈦 Both anions have the same electron configuration.
04

4. Bohr Diagrams of O虏鈦 and F鈦 Anions

Next, we will represent the O虏鈦 and F鈦 anions using Bohr diagrams: O虏鈦: In the first energy level, there are 2 electrons (1s虏). In the second energy level, there are 8 electrons (2s虏2p鈦). F鈦: In the first energy level, there are 2 electrons (1s虏). In the second energy level, there are 8 electrons (2s虏2p鈦). Both Bohr diagrams show that the O虏鈦 and F鈦 anions have the same electron configuration with the same number of electrons in each energy level.
05

Conclusion

Since both the electron configuration notation and the Bohr diagrams of O虏鈦 and F鈦 anions are identical, we can conclude that the statement is true: The O虏鈦 and F鈦 anions have identical electron configurations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Anions
Anions are negatively charged ions that form when an atom gains one or more electrons. This gain results in a greater number of electrons compared to protons, leading to a net negative charge. The process usually occurs with non-metal elements.
Anions play a crucial role in chemical reactions and are involved in the formation of ionic bonds by attracting cations, which are positively charged ions.
  • Common examples include chloride (Cl鈦), oxide (O虏鈦), and fluoride (F鈦) ions.
  • Anions are often larger than their neutral atoms because the added electrons increase electron-electron repulsion, expanding the electron cloud.
These ions are essential to many biological and environmental processes, making the understanding of their properties and configurations vital in the study of chemistry.
Bohr Diagrams
Bohr diagrams are a simple representation of an atom's electron configuration, showing how electrons occupy various energy levels or shells around the nucleus. Named after Niels Bohr, these diagrams help in visualizing electron distribution in atoms and ions.
The main idea is to represent electrons as rings around the nucleus. Each ring corresponds to a principal energy level, and electrons fill these rings starting from the innermost level. For example:
  • The first energy level can hold up to 2 electrons.
  • The second energy level can accommodate up to 8 electrons.
Bohr diagrams are especially useful for beginner chemistry students to understand how electrons are organized, and they offer insight into why atoms bond the way they do. Despite being simplified, Bohr diagrams lay the groundwork for more complex quantum models by illustrating basic electron arrangements.
O虏鈦 Ion
The oxide ion (O虏鈦) is formed when an oxygen atom gains two electrons. This gain brings the total to 10 electrons, matching the electron configuration of neon, a noble gas.
Normally, oxygen has an electron configuration of 1s虏2s虏2p鈦. Upon gaining two electrons, its configuration changes to 1s虏2s虏2p鈦. This adjustment results in a full outer shell, making the ion stable. From a Bohr diagram perspective:
  • There are 2 electrons in the first shell.
  • There are 8 electrons in the second shell.
The oxide ion's stable electron arrangement is also reflected in its decreased reactivity compared to a neutral oxygen atom. This full outer shell configuration is a driving factor for oxygen's tendency to form O虏鈦 ions in various compounds.
F鈦 Ion
The fluoride ion (F鈦) forms when a fluorine atom gains one electron to achieve a full outer electron shell. Initially, fluorine has 9 electrons and its electron configuration is 1s虏2s虏2p鈦. By adding one more electron, it achieves the stable configuration 1s虏2s虏2p鈦.
This electron arrangement mirrors that of neon, ensuring stability and minimal reactivity. In a Bohr diagram:
  • The first shell contains 2 electrons.
  • The second shell has 8 electrons.
This stable configuration contributes to the fluoride ion's inert nature in chemical reactions, and it illustrates why halogens like fluorine tend to gain one electron to form anions, completing their octets and achieving stability.

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Most popular questions from this chapter

What are the wavelength in nanometers and energy in joules of the light emitted when a hydrogen electron originally in the \(n=6\) shell relaxes to the ground state? \(\left[1 \mathrm{eV}=1.602 \times 10^{-19} \mathrm{~J}\right]\)

How many valence electrons does each of these atoms have? (a) \(1 s^{2} 2 s^{2} 2 p^{3}\) (b) \(1 s^{2} 2 s^{1}\) (c) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{7}\) (d) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}\) (e) \(1 s^{2}\)

What is the formula for the maximum number of electrons in each shell of the Bohr atom? How many electrons are allowed in the \(n=2\) shell? The \(n=6\) shell?

When a hydrogen atom is excited in a flame, a line of blue-violet light is emitted. This happens when an electron makes a transition between the \(n=5\) and the \(n=2\) orbit of the atom. If the energy of this light is \(2.9 \mathrm{eVs}\) and the energy of an electron in the \(n=2\) hydrogen orbit is \(11.2 \mathrm{eVs}\), what must be the energy of the \(n=5\) orbit?

A student has written what he thinks are some ground-state electron configurations. Which ones have something wrong with them? What is wrong? (a) \(1 s^{2} 2 p^{6} 3 s^{1}\) (b) \(1 s^{2} 2 s^{6} 3 s^{2} 3 p^{6} 4 s^{2} 4 p^{6}\) (c) \(2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{7}\) (d) \(1 s^{2} 2 s^{2} 2 p^{7} 3 s^{3} 3 p^{6}\) (e) \(1 s^{2} 2 s^{2} 2 p^{5} 3 s^{1}\) (f) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{1} 4 d^{4}\) [This is the transition metal niobium, which violates the four-block electron-assignment rules, so be careful.]

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