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The solubility of \(\mathrm{PbI}_{2}\) in water at \(25^{\circ} \mathrm{C}\) is \(1.52 \times 10^{-3}\) M. How many grams of \(\mathrm{PbI}_{2}\) will dissolve in \(2.50 \times 10^{6}\) gallons of water at \(25^{\circ} \mathrm{C}\) ?

Short Answer

Expert verified
Therefore, \(6.62 \times 10^{6}\) grams of PbI鈧 will dissolve in \(2.50 \times 10^{6}\) gallons of water at 25掳C.

Step by step solution

01

Convert gallons to liters

We are given the volume of water as 2.50 x 10鈦 gallons. To convert this volume to liters, we will use the following conversion factor: 1 gallon = 3.78541 liters \(Volume\,in\,liters = (2.50 \times 10^{6})\,gallons \times \frac{3.78541\,liters}{1\,gallon} = 9.46 \times 10^{6}\,liters\)
02

Calculate moles of PbI鈧 that can dissolve

We know the solubility of PbI鈧 in water is 1.52 x 10鈦宦 M. Thus, in one liter of water, we have 1.52 x 10鈦宦 moles of PbI鈧. To find the number of moles in the given volume, we can use the following calculation: Moles of PbI鈧 = (solubility in moles per liter) x (volume in liters) Moles of PbI鈧 = (1.52 x 10鈦宦) M x (9.46 x 10鈦) L 鈮 14402.32 moles
03

Convert moles of PbI鈧 to grams

To convert the calculated moles of PbI鈧 to grams, we need to multiply the number of moles by the molar mass of PbI鈧: Molar mass of PbI鈧 = 207.2 g/mol (Pb) + 2 x 126.9 g/mol (I) 鈮 460 g/mol Mass of PbI鈧 = moles of PbI鈧 x molar mass of PbI鈧 Mass of PbI鈧 = 14402.32 moles * 460 g/mol 鈮 6.62 x 10鈦 grams Therefore, 6.62 x 10鈦 grams of PbI鈧 will dissolve in 2.50 x 10鈦 gallons of water at 25掳C.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass
Understanding molar mass is crucial for solving chemistry problems involving substances' weights and reactions. Molar mass represents the mass of one mole of a chemical compound or element. It's usually expressed in grams per mole (g/mol).
For instance, in the problem of finding out how much PbI鈧 can dissolve, we calculated its molar mass. Lead (Pb) has a molar mass of 207.2 g/mol, and iodine (I) has a molar mass of 126.9 g/mol. Since PbI鈧 consists of one atom of lead and two atoms of iodine, we add these together:
  • One Pb: 207.2 g/mol
  • Two I: 2 x 126.9 g/mol = 253.8 g/mol
Thus, the molar mass of PbI鈧 is approximately 460 g/mol. This value is essential for converting moles into grams, allowing us to measure how much solute will actually dissolve in a given amount of solvent.
Unit Conversion
Unit conversion is a fundamental skill in chemistry, especially when dealing with different measurement systems. In this exercise, we start with the volume of water in gallons, which we need to convert to liters.
The conversion factor between gallons and liters is:
  • 1 gallon = 3.78541 liters
To convert 2.50 x 10鈦 gallons to liters, you multiply:
  • Volume in liters = 2.50 x 10鈦 gallons x 3.78541 liters/gallon
  • This results in approximately 9.46 x 10鈦 liters
This conversion is necessary because the solubility values are typically expressed per liter. Taking this step ensures accuracy when calculating solubility-related problems.
Moles and Grams
Moles and grams are front and center in chemistry problems, often acting as a bridge between theoretical calculations and practical applications. In the given problem, once we understand the solubility in terms of moles, we convert this into grams for a tangible mass measurement.
To do this, we start with moles. Solubility tells us how many moles of a solute (here, PbI鈧) can dissolve in a particular volume of solvent:
  • Given solubility: 1.52 x 10鈦宦 M, meaning moles per liter.
Calculate moles in the total volume:
  • Moles of PbI鈧 = 1.52 x 10鈦宦 moles/L x 9.46 x 10鈦 L = 14402.32 moles
We then convert moles to grams using molar mass:
  • Mass of PbI鈧 = 14402.32 moles x 460 g/mol
  • This results in approximately 6.62 x 10鈦 grams
Converting moles to grams is vital for practical measurement and real-world applications.
Concentration and Solubility
Concentration and solubility are fundamental concepts when discussing solutions. Solubility refers to the maximum amount of solute that can dissolve in a solvent at a given temperature and pressure. Concentration, often expressed in molarity (M), describes the amount of solute in a certain volume of solution.
In this example, we know the solubility of PbI鈧 in water is 1.52 x 10鈦宦 M at 25掳C. This means, under these conditions, 1.52 x 10鈦宦 moles of PbI鈧 can dissolve per liter of water.
  • To find the concentration of a solution, use the formula: Concentration (M) = Moles of solute / Volume of solution (L)
By multiplying the molarity by the volume, we calculate the total moles that can dissolve in that volume of water. This information helps us translate into grams (using molar mass), allowing us to see how much solute can be dissolved in a practical scenario.
Understanding both solubility and concentration is key for preparing solutions and predicting the behavior of substances in various environments.

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Most popular questions from this chapter

A certain reaction has a \(K_{\text {eq }}\) value of \(1.5 \times 10^{-6}\). (a) Would this be a practical reaction from which to isolate pure product? Explain your answer.

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