Chapter 13: Problem 49
What do we mean by activation energy?
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Chapter 13: Problem 49
What do we mean by activation energy?
These are the key concepts you need to understand to accurately answer the question.
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A reaction releases \(900 \mathrm{~kJ}\) of energy. (a) Is the reaction endothermic or exothermic? (b) Which are higher in the reaction-energy profile, reactants or products? Explain. (c) Does this reaction go uphill or downhill in energy? (d) Draw the reaction-energy profile.
Why is it unlikely that the reaction \(\mathrm{A}+2 \mathrm{~B}+\mathrm{C} \rightarrow \mathrm{P}\) occurs in one step?
Consider the reaction. Kinetics studies reveal a first-order rate dependence on the concentration of the \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}-\mathrm{Br}\) and a zero-order dependence on the concentration of \(\mathrm{H}_{2} \mathrm{O}\). (a) What happens to the reaction rate as the \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}-\mathrm{Br}\) concentration is changed? What happens to the reaction rate as the \(\mathrm{H}_{2} \mathrm{O}\) concentration is changed? (b) Two mechanisms for this reaction are offered below. Can you rule out either of them? Is either mechanism plausible, given the overall balanced equation and kinetic data? Explain your answer fully.
A student claims that an endothermic reaction will always have a higher activation energy than an exothermic reaction, because an endothermic reaction ends up with the products at a higher energy than the reactants. Is this correct or incorrect? Justify your answer.
Given the rate data below from a series of kinetics experiments, determine the orders for the following reaction, and state the overall order of the reaction: \(\mathrm{H}_{2} \mathrm{O}_{2}(a q)+3 \mathrm{I}^{-}(a q)+2 \mathrm{H}^{+}(a q) \rightarrow \mathrm{I}_{3}^{-}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l)\) $$\begin{array}{cccc} \text { Experiment }\left[\mathbf{H}_{2} \mathrm{O}_{2}\right] & {\left[\mathbf{I}^{-}\right]} & {\left[\mathbf{H}^{+}\right]} & \text {Rate }(\mathbf{M} / \mathbf{s}) \\ \hline 1 & 0.010 \mathrm{M} & 0.010 \mathrm{M} & 0.00050 \mathrm{M} & 1.15 \times 10^{-6} \\ 2 & 0.020 \mathrm{M} & 0.010 \mathrm{M} & 0.00050 \mathrm{M} & 2.30 \times 10^{-6} \\ 3 & 0.010 \mathrm{M} & 0.020 \mathrm{M} & 0.00050 \mathrm{M} & 2.30 \times 10^{-6} \\ 4 & 0.010 \mathrm{M} & 0.010 \mathrm{M} & 0.00100 \mathrm{M} & 1.15 \times 10^{-6} \end{array}$$
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