/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Suppose you have a sample of \(\... [FREE SOLUTION] | 91Ó°ÊÓ

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Suppose you have a sample of \(\mathrm{CO}_{2}\) gas and want to know its mass without bothering to use a balance. How could you do this?

Short Answer

Expert verified
To find the mass of the COâ‚‚ gas sample without using a balance, first identify the pressure, volume, and temperature of the gas. Then, use the ideal gas law equation, \(PV = nRT\), to calculate the number of moles (n). Find the molar mass of COâ‚‚ by adding the molar mass of one carbon atom (12.01 g/mol) and two oxygen atoms (2 x 16.00 g/mol), resulting in a molar mass of 44.01 g/mol. Finally, calculate the mass of the COâ‚‚ gas by multiplying the number of moles (n) by the molar mass of COâ‚‚ (44.01 g/mol): \(m = n \times 44.01 \frac{g}{mol}\).

Step by step solution

01

Identify the properties of the gas

In order to find the number of moles of the COâ‚‚ gas, we need to know its pressure, temperature, and volume. Usually, these values will be given in the problem, and they'll be needed to determine the number of moles.
02

Calculate the number of moles

Once you have the pressure (P), volume (V), and temperature (T) of the COâ‚‚ gas, you can use the ideal gas law to find the number of moles (n). The ideal gas law is given by the equation: \(PV = nRT\) where R is the ideal gas constant (\(8.314 \frac{J}{molK}\)). Rearrange the ideal gas law equation to solve for n: \(n = \frac{PV}{RT}\) Plug in the values for P, V, and T, and calculate the number of moles of COâ‚‚ gas: \(n = \frac{P \cdot V}{R \cdot T}\)
03

Calculate the molar mass of COâ‚‚

The molar mass of COâ‚‚ can be found by adding the molar masses of one carbon atom and two oxygen atoms. Molar mass of carbon: 12.01 g/mol Molar mass of oxygen: 16.00 g/mol Thus, the molar mass of COâ‚‚ is: \(M_{COâ‚‚} = 12.01 \frac{g}{mol} + 2 \times 16.00 \frac{g}{mol} = 44.01 \frac{g}{mol}\)
04

Calculate the mass of the COâ‚‚ gas

Now that we have the number of moles (n) and the molar mass (M) of COâ‚‚, we can calculate the mass (m) of the COâ‚‚ gas using the equation: \(m = n \times M_{COâ‚‚}\) Plug in the values for n and M and calculate the mass of the COâ‚‚ gas: \(m = n \times 44.01 \frac{g}{mol}\) This will give you the mass of the COâ‚‚ gas sample without having to use a balance.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moles Calculation
Understanding how to calculate moles is key when working with gases. Moles represent a fundamental measure in chemistry describing the amount of a substance. For gases, we use the ideal gas law to find the number of moles. This is important because moles are used to connect the macroscopic world of gases with the microscopic world of atoms and molecules.

To calculate moles, you need three properties: pressure (P), volume (V), and temperature (T). These are often provided in problems or experiments. The formula you use is the ideal gas law: \(PV = nRT\), where \(R\) is the ideal gas constant, which has a value of \(8.314 \frac{J}{mol \, K}\). Rearranging this formula allows you to solve for the number of moles \(n\) with \(n = \frac{PV}{RT}\).

By substituting the known values of pressure, volume, and temperature into this equation, you can find the number of moles of your gas sample.
Molar Mass
Molar mass is an essential concept in chemistry that helps us understand the composition of molecules. It refers to the mass of a given substance (in grams) divided by the amount of substance (in moles). In the case of molecular compounds, it's the sum of the atomic masses of all the atoms in a molecule.

For example, to find the molar mass of carbon dioxide \(CO_2\), you add the molar masses of one carbon atom and two oxygen atoms. Carbon has a molar mass of \(12.01 \frac{g}{mol}\), while oxygen has a molar mass of \(16.00 \frac{g}{mol}\).

Thus, the molar mass of \(CO_2\) is:
  • 12.01 \(\frac{g}{mol}\) (Carbon)
  • 2 \(\times\) 16.00 \(\frac{g}{mol}\) (Oxygen)
Adding these together gives \(44.01 \frac{g}{mol}\). Knowing the molar mass allows you to convert between grams and moles, thereby determining the mass of your gas when the number of moles is known.
Gas Properties
Gases have unique properties that set them apart in the states of matter. These properties are pressure, volume, and temperature, which are all interconnected through the ideal gas law. Understanding these properties allows us to predict and quantify how gases will behave under various conditions.

  • Pressure (P): This is the force that the gas exerts on the walls of its container, and it is often measured in atm, Pa, or torr.
  • Volume (V): This is the space that a gas occupies, usually measured in liters or cubic meters.
  • Temperature (T): Related to the kinetic energy of the gas particles, it is measured in Kelvin for calculations involving gases.
The ideal gas law, \(PV = nRT\), combines these properties to help us understand gas behavior. For any given gas, knowing two of these properties typically allows us to calculate the third, as well as the amount in moles. Mastery of these properties enables natural calculations like how much gas can fill a balloon or how much work can be done by a piston in an engine.

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Most popular questions from this chapter

A balloon filled with He gas and another balloon filled with \(\mathrm{H}_{2}\) gas have the same values for \(P\) and \(\bar{T}\). (a) The density of the He gas is greater than the density of the \(\mathrm{H}_{2}\) gas. How can you prove this using the ideal gas law? (b) How much more dense than the \(\mathrm{H}_{2}\) gas is the He gas?

Normal atmospheric pressure will push a column of mercury up an evacuated glass tube (a barometer) to a height of \(76 \mathrm{~cm}(760 \mathrm{~mm} \mathrm{Hg})\), which we call one atmosphere. Suppose water were used as the liquid in a barometer instead of mercury. How high up would the atmosphere push a column of water in centimeters and in feet? Also, why would mercury give a more accurate indication of the atmospheric pressure then water? Some data you may need: Density of mercury, \(13.6 \mathrm{~g} / \mathrm{mL} ;\) Density of water, \(1.00 \mathrm{~g} / \mathrm{mL}\); Boiling point of mercury, \(357^{\circ} \mathrm{C}\); Boiling point of water, \(100^{\circ} \mathrm{C}\).

A 1.56-g sample of gas is contained in a \(250.0-\mathrm{mL}\) cylinder. Its pressure is \(1255.6 \mathrm{~mm} \mathrm{Hg}\), and its temperature is \(22.7{ }^{\circ} \mathrm{C}\). (a) What is the molar mass of the gas? (b) Combustion analysis reveals the empirical formula of this gas to be \(\mathrm{NO}_{2}\). What is the molecular formula?

Suppose the variable \(x\) is proportional to \(1 / y\). What does this tell you about how the numeric value of \(x\) changes as the numeric value of \(y\) changes?

Which variable is not needed to describe the behavior of an ideal gas: volume, number of moles, temperature, molar mass, or pressure?

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