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For each of the following nonmetals, how many electrons will each atom of the nonmetal gain in reacting with a metal? a. oxygen b. fluorine c. nitrogen d. chlorine e. sulfur

Short Answer

Expert verified
a. Oxygen gains 2 electrons. b. Fluorine gains 1 electron. c. Nitrogen gains 3 electrons. d. Chlorine gains 1 electron. e. Sulfur gains 2 electrons.

Step by step solution

01

Identify the number of valence electrons

Before determining how many electrons will be gained, we need to identify the number of valence electrons for each nonmetal. Valence electrons are found in the outermost shell of an atom and are responsible for chemical reactions. a. Oxygen has 6 valence electrons (2s虏 2p鈦). b. Fluorine has 7 valence electrons (2s虏 2p鈦). c. Nitrogen has 5 valence electrons (2s虏 2p鲁). d. Chlorine has 7 valence electrons (3s虏 3p鈦). e. Sulfur has 6 valence electrons (3s虏 3p鈦).
02

Determine the number of electrons needed for a stable configuration

Next, we will determine the number of electrons needed by each nonmetal to achieve a stable configuration similar to the noble gases. a. Oxygen needs 2 more electrons to achieve a stable configuration (2s虏 2p鈦). b. Fluorine needs 1 more electron to achieve a stable configuration (2s虏 2p鈦). c. Nitrogen needs 3 more electrons to achieve a stable configuration (2s虏 2p鈦). d. Chlorine needs 1 more electron to achieve a stable configuration (3s虏 3p鈦). e. Sulfur needs 2 more electrons to achieve a stable configuration (3s虏 3p鈦).
03

Write the number of electrons gained by each nonmetal in a reaction

Now that we know the number of electrons needed to achieve a stable configuration, we can determine how many electrons each nonmetal will gain when reacting with a metal. a. Oxygen will gain 2 electrons in a reaction with a metal. b. Fluorine will gain 1 electron in a reaction with a metal. c. Nitrogen will gain 3 electrons in a reaction with a metal. d. Chlorine will gain 1 electron in a reaction with a metal. e. Sulfur will gain 2 electrons in a reaction with a metal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Valence Electrons
Valence electrons play a pivotal role in determining how elements interact with each other. They are the electrons located in the outermost shell of an atom and are involved in forming chemical bonds. For nonmetals, these electrons are particularly significant because they tend to gain electrons to achieve a full valence shell, similar to the noble gases which are known for their stability and inertness.

When nonmetals react with metals, they invariably look to achieve this full shell. Here's how it works: a nonmetal like oxygen, which has six valence electrons, will aim to gain two more electrons to complete its octet, resulting in a stable electron configuration (2s虏 2p鈦). This is a typical property of nonmetals and helps predict the kind of ions they will form and their valence in compounds.
Chemical Reactions
A chemical reaction is a process where substances, known as reactants, transform into new substances called products. This transformation involves the making and breaking of chemical bonds, which are largely influenced by the arrangement of valence electrons. In our example, nonmetals gain electrons from metals during chemical reactions. Metals have few valence electrons, which they can easily lose, while nonmetals have more valence electrons and are just a few short of completing their outer shell.

Therefore, in a reaction between a metal and a nonmetal, the nonmetal gains the desired number of electrons to achieve stability, forming negative ions known as anions. This transfer of electrons is the foundation of ionic bonding and is critical to understanding the behavior of elements during chemical reactions.
Electron Configuration
The electron configuration of an atom is a description of the distribution of electrons in atomic or molecular orbitals. For nonmetals, achieving a stable electron configuration usually means obtaining a full valence shell, which is the driving force behind their tendency to gain electrons in reactions with metals. When nonmetals interact with metals, which typically have fewer valence electrons and a tendency to lose them, they attain electron configurations that are characteristic of the closest noble gases, thus stabilizing the atoms involved.

Understanding electron configurations is not only crucial for predicting the gain or loss of electrons during chemical reactions but also for determining the types of bonds that an element can form. For instance, oxygen's electron configuration is 2s虏 2p鈦, indicating it needs two additional electrons to match the noble gas neon's configuration of 2s虏 2p鈦. At the heart of electron configuration is the principle that atoms seek the most stable electronic arrangement possible, which often manifests as a balance in the transfer or sharing of electrons in chemical processes.

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Most popular questions from this chapter

Write the balanced molecular, complete ionic, and net ionic equations for the reaction between nickel(II) chloride and sodium sulfide.

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On the basis of the general solubility rules given in Table 7.1 , predict the identity of the precipitate that forms when aqueous solutions of the following substances are mixed. If no precipitate is likely, indicate which rules apply. a. copper(II) chloride, \(\mathrm{CuCl}_{2}\), and ammonium sulfide, \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{~S}\) b. barium nitrate, \(\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2},\) and potassium phosphate, \(\mathrm{K}_{3} \mathrm{PO}_{4}\) c. silver acetate, \(\mathrm{AgC}_{2} \mathrm{H}_{3} \mathrm{O}_{2},\) and calcium chloride, \(\mathrm{CaCl}_{2}\) d. potassium carbonate, \(\mathrm{K}_{2} \mathrm{CO}_{3}\), and cobalt(II) chloride, \(\mathrm{CoCl}_{2}\) e. sulfuric acid, \(\mathrm{H}_{2} \mathrm{SO}_{4},\) and calcium nitrate, \(\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\) f. mercurous acetate, \(\mathrm{Hg}_{2}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2},\) and hydrochloric acid, \(\mathrm{HCl}\)

When the ionic solute \(\mathrm{K}_{3} \mathrm{PO}_{4}\) is dissolved in water, what can you say about the number of potassium ions \(\left(\mathrm{K}^{+}\right)\) present in the solution compared with the number of phosphate ions \(\left(\mathrm{PO}_{4}^{3-}\right)\) in the solution?

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