/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 111 Carbon dioxide gas, in the dry s... [FREE SOLUTION] | 91影视

91影视

Carbon dioxide gas, in the dry state, may be produced by heating calcium carbonate. $$ \mathrm{CaCO}_{3}(s) \rightarrow \mathrm{CaO}(s)+\mathrm{CO}_{2}(g) $$ What volume of \(\mathrm{CO}_{2},\) collected dry at \(55 \quad \mathrm{C}\) and a pressure of 774 torr, is produced by complete thermal decomposition of \(10.0 \mathrm{~g}\) of \(\mathrm{CaCO}_{3} ?\)

Short Answer

Expert verified
The volume of CO2 gas produced by the complete thermal decomposition of 10.0 g of CaCO3 at 55 掳C and a pressure of 774 Torr is 2.65 liters.

Step by step solution

01

Convert mass of CaCO3 to moles

To convert the mass of CaCO3 to moles, we will use its molar mass. The molar mass of calcium carbonate is 100.09 g/mol (40.08 g/mol for Ca, 12.01 g/mol for C, and 16.00 g/mol for each O). Using the formula: moles = mass / molar mass moles of CaCO3 = 10.0 g / 100.09 g/mol = 0.0999 mol
02

Calculate moles of CO2 produced

The balanced chemical equation provides the stoichiometry of the decomposition reaction: CaCO3(s) 鈫 CaO(s) + CO2(g) From the equation, 1 mole of CaCO3 produces 1 mole of CO2. Therefore, the moles of CO2 produced are equal to the moles of CaCO3. moles of CO2 = moles of CaCO3 = 0.0999 mol
03

Convert moles of CO2 to volume using the Ideal Gas Law

The Ideal Gas Law is given by: PV = nRT where P is pressure, V is volume, n is moles, R is the ideal gas constant, and T is the temperature in Kelvin. We are given the pressure in Torr (774 Torr), which we need to convert to atmospheres by dividing by 760: P = 774 Torr / 760 Torr/atm = 1.0184 atm The temperature in Celsius (55 掳C) should be converted to Kelvin: T = 55 掳C + 273.15 = 328.15 K We will use the value of the ideal gas constant R in the units L路atm路mol鈦宦孤稫鈦宦: R = 0.0821 L路atm路mol鈦宦孤稫鈦宦 Now we can solve the Ideal Gas Law equation for V: V = nRT / P V = (0.0999 mol)脳(0.0821 L路atm路mol鈦宦孤稫鈦宦)脳(328.15 K) / (1.0184 atm) = 2.65 L
04

Report final answer

The volume of CO2 gas produced by the complete thermal decomposition of 10.0 g of CaCO3 at 55 掳C and a pressure of 774 Torr is 2.65 liters.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is the backbone of chemical equations and involves the calculation of reactants and products in chemical reactions. It plays a crucial role when we are interested in understanding how much of a substance is consumed or produced during a reaction.

Consider the decomposition of calcium carbonate (CaCO3), which produces calcium oxide (CaO) and carbon dioxide (CO2). The balanced chemical equation is written as:
\[ \mathrm{CaCO}_{3}(s) \rightarrow \mathrm{CaO}(s) + \mathrm{CO}_{2}(g) \]
The equation tells us that 1 mole of calcium carbonate yields exactly 1 mole of carbon dioxide. When we apply stoichiometry, beginning with the mass of calcium carbonate, we first determine the moles of calcium carbonate present and then, through the coefficients provided by the balanced equation, ascertain the moles of carbon dioxide produced.

Using stoichiometric coefficients, the number of moles and the law of conservation of mass, we ensure that matter is neither created nor destroyed; so, if we start with 10.0 grams of calcium carbonate, we would theoretically produce an equivalent amount of product, which in our case, is carbon dioxide. The step by step solution included also is an example of applying stoichiometry principles.
Ideal Gas Law
The Ideal Gas Law is a fundamental equation in chemistry that relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas. It is commonly expressed as:
\[PV = nRT\]
Here, R is the gas constant. This law is pivotal when determining the volume of a gas, such as carbon dioxide in our example, under specific conditions of temperature and pressure.

To apply the Ideal Gas Law, one must ensure that the pressure is in atmospheres (atm) and the temperature is in Kelvin (K). Any given values in other units should be converted accordingly - this ensures accuracy in the final calculations. For instance, in the provided solution, the pressure was initially in Torr and had to be converted to atmospheres, while the temperature was given in Celsius and had to be converted to Kelvin.

The law is applied best when gases behave ideally, which means they follow certain assumptions, including no interactions between gas particles and that the particles occupy no volume. While these assumptions are not perfectly true for real gases, the Ideal Gas Law provides a good approximation for many conditions, especially those involving higher temperatures and lower pressures, like in our example where CO2 is being produced at a fairly high temperature.
Chemical Reaction
Chemical reactions involve the transformation of substances through the breaking of old bonds and the formation of new ones. These can be described through chemical equations that illustrate what reactants are used and what products are formed.

Thermal decomposition, such as when heating calcium carbonate to yield calcium oxide and carbon dioxide, is a specific type of chemical reaction where a compound breaks down into simpler ones upon heating. This process is represented in the equation:
\[\mathrm{CaCO}_{3}(s) \xrightarrow{\Delta} \mathrm{CaO}(s) + \mathrm{CO}_{2}(g)\]
The triangle above the arrow signifies that heat is applied for the reaction to occur. It is essential to know that not all compounds will decompose with heat alone, and different substances will require different amounts of energy (heat) for decomposition to take place.

The exercise provided is a practical application of understanding chemical reactions. It requires comprehension of how substances interact under specific conditions, predicting the outcomes, and then using other chemistry concepts like stoichiometry and the ideal gas law to quantify the products of the reaction.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Given each of the following sets of values for three of the gas variables, calculate the unknown quantity. a. \(P=21.2\) atm \(; V=142 \mathrm{~mL} ; n=0.432 \mathrm{~mol} ; T=? \mathrm{~K}\) b. \(P=?\) atm \(; V=1.23 \mathrm{~mL} ; n=0.000115 \mathrm{~mol} ; T=293 \mathrm{~K}\) c. \(P=755 \mathrm{~mm} \mathrm{Hg} ; V=? \mathrm{~mL} ; n=0.473 \mathrm{~mol} ; T=131 \mathrm{C}\)

If 0.00901 mole of neon gas at a particular temperature and pressure occupies a volume of \(242 \mathrm{~mL}\), what volume would 0.00703 mole of neon occupy under the same conditions?

A widely used weather instrument called a barometer can be built from a long, thin tube of glass that is sealed at one end. The tube is completely filled with mercury and then inverted into a small pool of mercury. The level of the mercury inside the tube drops initially but then stabilizes at some height. A measure of the height of the column of mercury once it stabilizes is a measure of pressure in \(\mathrm{mm} \mathrm{Hg}\) (or torr). Which of the following is the best explanation of how this barometer works? a. Air pressure outside the tube (pressure of the atmosphere) counterbalances the weight of the mercury inside the tube. b. Air pressure inside the tube causes the mercury to move in the tube until the air pressure inside and outside the tube are equal. c. Air pressure outside the tube causes the mercury to move in the tube until the air pressure inside and outside the tube are equal. d. The vacuum that is formed at the top of the tube of mercury (once the mercury level in the tube has dropped some) holds up the mercury. e. I have no idea how a barometer works.

Suppose that \(1.29 \mathrm{~g}\) of argon gas is confined to a volume of \(2.41 \mathrm{~L}\) at 29 C. What would be the pressure in the container? What would the pressure become if the temperature were raised to 42 " \(\mathrm{C}\) without a change in volume?

We often collect small samples of gases in the laboratory by bubbling the gas into a bottle or flask containing water. Explain why the gas becomes saturated with water vapor and how we must take the presence of water vapor into account when calculating the properties of the gas sample.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.