/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 100 Welders commonly use an apparatu... [FREE SOLUTION] | 91影视

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Welders commonly use an apparatus that contains a tank of acetylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)\) gas and a tank of oxygen gas. When burned in pure oxygen, acetylene generates a large amount of heat. $$ 2 \mathrm{C}_{2} \mathrm{H}_{2}(g)+5 \mathrm{O}_{2}(g) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(g)+4 \mathrm{CO}_{2}(g) $$ What volume of carbon dioxide gas at STP is produced if \(1.00 \mathrm{~g}\) of acetylene is combusted completely?

Short Answer

Expert verified
When 1.00 g of acetylene is combusted completely, 1.72 L of carbon dioxide gas at STP is produced.

Step by step solution

01

Calculate the number of moles of acetylene

To find the number of moles of acetylene, use the formula: number of moles = (mass of compound) / (molar mass of compound) The molar mass of acetylene, C鈧侶鈧, is 2 脳 molar mass of C + 2 脳 molar mass of H Molar mass of C = 12.01 g/mol Molar mass of H = 1.01 g/mol So, molar mass of acetylene = 2 脳 12.01 + 2 脳 1.01 = 26.04 g/mol number of moles of acetylene = (1.00 g) / (26.04 g/mol) = 0.0384 mol
02

Use the stoichiometry of the balanced chemical equation to find the number of moles of CO鈧 produced

From the balanced chemical equation, we have: 2 C鈧侶鈧 + 5 O鈧 鈫 2 H鈧侽 + 4 CO鈧 We can see that 2 moles of acetylene react to produce 4 moles of CO鈧. So, we can set up a proportion: moles of CO鈧 / moles of acetylene = 4 / 2 moles of CO鈧 = \( (4/2) 脳 0.0384 \) = 0.0768 mol
03

Use the ideal gas law to find the volume of CO鈧 gas at STP

At STP (Standard Temperature and Pressure), the temperature (T) is 273.15 K, and the pressure (P) is 1 atm. The ideal gas law states: PV = nRT Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (8.314 J鈦(mol路K) or 0.0821 L路atm鈦(mol路K)), and T is the temperature. We want to find the volume (V) of CO鈧 gas produced. Since we are working at STP, we can use the molar volume of a gas at STP (22.4 L/mol): V = n 脳 molar volume at STP V = 0.0768 mol 脳 22.4 L/mol = 1.72 L So, the volume of CO鈧 gas produced at STP is 1.72 L.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The ideal gas law is a fundamental principle in chemistry and physics that describes the behavior of gases under ideal conditions.
It combines several important gas laws into one equation:
  • Boyle's Law states that the pressure of a gas is inversely proportional to its volume when temperature is held constant.
  • Charles's Law shows that the volume of a gas is directly proportional to its temperature when pressure is constant.
  • Avogadro's Law indicates that the volume of a gas is directly proportional to the number of moles of gas, assuming pressure and temperature are constant.
The ideal gas law formula is: \[ PV = nRT \] In this equation:
  • P represents pressure,
  • V is the volume,
  • n denotes the number of moles,
  • R is the universal gas constant (0.0821 L路atm鈦(mol路K) for most practical purposes),
  • and T is the temperature in Kelvin.
At Standard Temperature and Pressure (STP), which is defined as 273.15 Kelvin and 1 atmosphere of pressure, 1 mole of an ideal gas occupies 22.4 liters.
This is a handy approximation that simplifies calculations when you're dealing with gases.
In this exercise, the ideal gas law helps determine the volume of CO鈧 produced by combustion.
Molar Mass
Molar mass is a critical concept when you're working with chemical reactions and stoichiometry.
It refers to the mass of one mole of a given substance.
Understanding molar mass is key to converting between moles鈥攁 measure of how many molecules or atoms there are鈥攁nd grams, which is a measure of mass.
To calculate a compound's molar mass, you must sum the atomic masses of all atoms present in the molecule.
  • For example, the molar mass of carbon ( C) is 12.01 g/mol,
  • while hydrogen ( H) is 1.01 g/mol.
In acetylene ( C鈧侶鈧), you calculate the total molar mass by adding together the weighted contributions of each element: 2 times the molar mass of C (carbon) plus 2 times the molar mass of H (hydrogen).
This gives you a molar mass of 26.04 g/mol for acetylene, essential for converting its mass in grams into moles for further calculations.
This conversion allows you to utilize stoichiometry to determine the amounts of reactants and products.
Chemical Reactions
Chemical reactions are processes where substances (reactants) change into new substances (products).
In this exercise, acetylene (C鈧侶鈧) combusts with oxygen to produce water and carbon dioxide: \[2 \; \mathrm{C}_{2}\mathrm{H}_{2}(g) + 5 \; \mathrm{O}_{2}(g) \rightarrow 2 \; \mathrm{H}_{2}\mathrm{O}(g) + 4 \; \mathrm{CO}_{2}(g)\]This balanced equation tells us a lot about the reaction.
  • The numbers in front of each molecule represent the stoichiometric coefficients.
  • These coefficients indicate the ratios of moles of each substance involved in the reaction.
These are crucial in stoichiometry, a method used to calculate the relative quantities of reactants and products in chemical reactions.
By understanding this stoichiometric relationship, we can see that 2 moles of C鈧侶鈧 yield 4 moles of CO鈧.
For example, using this ratio, we calculate that when 1 mole of acetylene reacts, it will produce 2 moles of carbon dioxide.
This fundamental relationship allows chemists and students alike to predict how much product can be formed from a given amount of reactant, and is vital for both practical applications and theoretical calculations.

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Most popular questions from this chapter

We often collect small samples of gases in the laboratory by bubbling the gas into a bottle or flask containing water. Explain why the gas becomes saturated with water vapor and how we must take the presence of water vapor into account when calculating the properties of the gas sample.

Calcium carbide, \(\mathrm{CaC}_{2}\), reacts with water to produce acetylene gas, \(\mathrm{C}_{2} \mathrm{H}_{2}\) $$ \mathrm{CaC}_{2}(s)+2 \mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{C}_{2} \mathrm{H}_{2}(g)+\mathrm{Ca}(\mathrm{OH})_{2}(s) $$ What volume of acetylene at 25 ' \(\mathrm{C}\) and 1.01 atm is generated by the complete reaction of \(2.49 \mathrm{~g}\) of calcium carbide? What volume would this quantity of acetylene occupy at STP?

For each of the following sets of volume/temperature data, calculate the missing quantity. Assume that the pressure and the mass of gas remain constant. a. \(V=2.01 \times 10^{2} \mathrm{~L}\) at 1150 " \(\mathrm{C} ; V=5.00 \mathrm{~L}\) at? \(\mathrm{C}\) b. \(V=44.2 \mathrm{~mL}\) at \(298 \mathrm{~K} ; V=?\) at \(0 \mathrm{~K}\) c. \(V=44.2 \mathrm{~mL}\) at \(298 \mathrm{~K} ; V=?\) at 0 'C

Consider the following unbalanced chemical equation: $$ \mathrm{Cu}_{2} \mathrm{~S}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{Cu}_{2} \mathrm{O}(s)+\mathrm{SO}_{2}(g) $$ What volume of oxygen gas, measured at 27.5 " \(\mathrm{C}\) and 0.998 atm, is required to react with \(25 \mathrm{~g}\) of copper(I) sulfide? What volume of sulfur dioxide gas is produced under the same conditions?

An expandable vessel contains \(729 \mathrm{~mL}\) of gas at \(22 \mathrm{C}\). What volume will the gas sample in the vessel have if it is placed in a boiling water bath \((100 . \quad \mathrm{C}) ?\)

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