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What solution can you add to each cation mixture to precipitate one cation while keeping the other cation in solution? Write a net ionic equation for the precipitation reaction that occurs. (a) \(\mathrm{Fe}^{2+}(a q)\) and \(\mathrm{Pb}^{2+}(a q)\) (b) \(\mathrm{K}^{+}(a q)\) and \(\mathrm{Ca}^{2+}(a q)\) (c) \(\mathrm{Ag}^{+}(a q)\) and \(\mathrm{Ba}^{2+}(a q)\) (d) \(\mathrm{Cu}^{2+}(a q)\) and \(\mathrm{Hg}_{2}{ }^{2+}(a q)\)

Short Answer

Expert verified
Add Na鈧係O鈧 to precipitate PbSO鈧 (Fe虏鈦/Pb虏鈦), Na鈧侰O鈧 for CaCO鈧 (K鈦/Ca虏鈦), Na鈧係O鈧 for BaSO鈧 (Ag鈦/Ba虏鈦), and NaCl for Hg鈧侰l鈧 (Cu虏鈦/Hg鈧偮测伜). Net ionic equations are: (a) Pb虏鈦 + SO鈧劼测伝 鈫 PbSO鈧(s), (b) Ca虏鈦 + CO鈧兟测伝 鈫 CaCO鈧(s), (c) Ba虏鈦 + SO鈧劼测伝 鈫 BaSO鈧(s), (d) Hg鈧偮测伜 + 2Cl鈦 鈫 Hg鈧侰l鈧(s).

Step by step solution

01

Identify the Precipitating Reagent for Fe虏鈦 and Pb虏鈦

To precipitate one cation while keeping the other in solution, we can add sodium sulfate (Na鈧係O鈧). Lead sulfate (PbSO鈧) is insoluble in water and will precipitate, while iron(II) sulfate (FeSO鈧) remains soluble.
02

Write the Net Ionic Equation for Fe虏鈦 and Pb虏鈦

The net ionic equation for the precipitation of lead(II) sulfate is: \(\mathrm{Pb}^{2+}(aq) + \mathrm{SO}_4^{2-}(aq) \rightarrow \mathrm{PbSO}_4(s)\).
03

Identify the Precipitating Reagent for K鈦 and Ca虏鈦

We can add carbonate (CO鈧兟测伝), such as sodium carbonate (Na鈧侰O鈧), because calcium carbonate (CaCO鈧) precipitates, while potassium carbonate (K鈧侰O鈧) is soluble.
04

Write the Net Ionic Equation for K鈦 and Ca虏鈦

The net ionic equation for the precipitation of calcium carbonate is: \(\mathrm{Ca}^{2+}(aq) + \mathrm{CO}_3^{2-}(aq) \rightarrow \mathrm{CaCO}_3(s)\).
05

Identify the Precipitating Reagent for Ag鈦 and Ba虏鈦

Sodium sulfate (Na鈧係O鈧) can be used here because barium sulfate (BaSO鈧) is insoluble and will precipitate, while silver sulfate (Ag鈧係O鈧) is moderately soluble and will mostly remain in solution.
06

Write the Net Ionic Equation for Ag鈦 and Ba虏鈦

The net ionic equation for the precipitation of barium sulfate is: \(\mathrm{Ba}^{2+}(aq) + \mathrm{SO}_4^{2-}(aq) \rightarrow \mathrm{BaSO}_4(s)\).
07

Identify the Precipitating Reagent for Cu虏鈦 and Hg鈧偮测伜

To precipitate Hg鈧偮测伜 while keeping Cu虏鈦 in solution, we can use chloride (Cl鈦), for example, from sodium chloride (NaCl), because mercury(I) chloride (Hg鈧侰l鈧) precipitates, while copper(II) chloride (CuCl鈧) remains soluble.
08

Write the Net Ionic Equation for Cu虏鈦 and Hg鈧偮测伜

The net ionic equation for the precipitation of mercury(I) chloride is: \(\mathrm{Hg}_{2}^{2+}(aq) + 2\mathrm{Cl}^-(aq) \rightarrow \mathrm{Hg}_2\mathrm{Cl}_2(s)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solubility Rules
Understanding solubility rules is essential for predicting whether a compound will dissolve in water or form a precipitate. These rules are a set of guidelines that help us determine the solubility of various ionic compounds.

For instance, most sulfate (SO鈧劼测伝) salts are soluble, with exceptions like barium sulfate (BaSO鈧) and lead sulfate (PbSO鈧), which are insoluble. Similarly, most compounds of alkali metal ions and ammonium are soluble, which is why compounds containing potassium (K鈦) and sodium (Na鈦) ions dissolve readily in water. Conversely, carbonates (CO鈧兟测伝) are typically insoluble except when paired with alkali metal ions, as in the case of potassium carbonate (K鈧侰O鈧).

These rules are crucial when selecting a reagent to precipitate a specific cation out of a mixture, as demonstrated in the original exercise. By adding the appropriate reagent that forms an insoluble compound with the targeted cation, we can selectively precipitate it out from the solution.
Net Ionic Equations
A net ionic equation represents the chemical reaction that occurs in solution at the ionic level. It focuses on the species that participate directly in the reaction, omitting the spectator ions that do not change during the process.

For example, in the original exercise's step 2, to precipitate lead(II) sulfate, we combine lead (II) ions with sulfate ions. The net ionic equation is simplified to \(\mathrm{Pb}^{2+}(aq) + \mathrm{SO}_4^{2-}(aq) \rightarrow \mathrm{PbSO}_4(s)\), showing only the ions that form the precipitate and leaving out the sodium ions which are spectator ions.

Net ionic equations provide a clearer picture of the underlying chemistry in precipitation reactions, helping students understand the process without the complexity of the complete ionic reaction.
Selective Precipitation
The concept of selective precipitation involves adding a reagent to a mixture of ions that will cause one of them to precipitate, while the others remain in solution. This technique is used for separating ions in a mixture based on the differences in their solubility.

As seen in the original exercise, by choosing an appropriate reagent, we can selectively remove a specific ion. For instance, adding sodium sulfate to a mixture of Fe虏鈦 and Pb虏鈦 will precipitate out the Pb虏鈦 as lead sulfate, while Fe虏鈦 stays dissolved as a sulfate. This method is not only vital in chemical analysis but also in metal purification and wastewater treatment processes.

Executing selective precipitation effectively requires a thorough understanding of the solubility rules to predict the reagent needed for the desired separation.
Double Displacement Reactions
A double displacement reaction, also known as a metathesis reaction, occurs when ions from two compounds exchange places in aqueous solution to form two new compounds. One of the products is typically a precipitate, a gas, or a weakly dissociated molecule like water.

For example, when sodium carbonate (Na鈧侰O鈧) is added to a solution of calcium chloride (CaCl鈧), calcium carbonate precipitates, and sodium chloride remains in solution. The reaction can be represented by the ionic equation: \(\mathrm{Na}_2\mathrm{CO}_3(aq) + \mathrm{CaCl}_2(aq) \rightarrow \mathrm{CaCO}_3(s) + 2\mathrm{NaCl}(aq)\). In the exercise provided, the reactions described are all double displacement reactions leading to the formation of an insoluble salt, demonstrating the kind of transformation characteristic of this reaction type.

Recognizing double displacement reactions is critical for predicting the outcomes of mixing various ionic compounds in solution, especially in the context of forming a precipitate.

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