Chapter 14: Problem 3
What is the main component of stomach acid? Why do we have stomach acid?
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Chapter 14: Problem 3
What is the main component of stomach acid? Why do we have stomach acid?
These are the key concepts you need to understand to accurately answer the question.
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Determine \(\left[\mathrm{OH}^{-}\right]\)in each base solution. If the acid is weak, indicate the value that \(\left[\mathrm{OH}^{-}\right]\)is less than. (a) \(2.5 \mathrm{M} \mathrm{KOH}\) (b) \(1.95 \mathrm{M} \mathrm{NH}_{3}\) (c) \(0.225 \mathrm{M} \mathrm{Ba}(\mathrm{OH})_{2}\) (d) \(1.8 \mathrm{MC}_{5} \mathrm{H}_{5} \mathrm{~N}\)
For each \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\), determine the \(\mathrm{pH}\) and state whether the solution is acidic or basic. (a) \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=0.0025 \mathrm{M}\) (b) \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=1.8 \times 10^{-12} \mathrm{M}\) (c) \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=9.6 \times 10^{-9} \mathrm{M}\) (d) \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=0.0195 \mathrm{M}\)
How is pOH defined? A change of \(2.0 \mathrm{pOH}\) units corresponds to how much of a change in \(\left[\mathrm{OH}^{-}\right] ?\)
Calculate \(\left[\mathrm{OH}^{-}\right]\)given \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\)in each aqueous solution and classify the solution as acidic or basic. (a) \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=1.3 \times 10^{-3} \mathrm{M}\) (b) \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=9.1 \times 10^{-12} \mathrm{M}\) (c) \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=5.2 \times 10^{-4} \mathrm{M}\) (d) \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=6.1 \times 10^{-9} \mathrm{M}\)
Calculate \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\)for each solution. (a) \(\mathrm{pH}=1.76\) (b) \(\mathrm{pH}=3.88\) (c) \(\mathrm{pH}=8.43\) (d) \(\mathrm{pH}=12.32\)
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