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Chapter 8: Problem 110

Calculate the molar mass for each of the following substances. a. ferrous sulfate b. mercuric iodide c. stannic oxide d. cobaltous chloride e. cupric nitrate

Short Answer

Expert verified
Molar masses: a. Ferrous sulfate: 151.9 g/mol b. Mercuric iodide: 454.4 g/mol c. Stannic oxide: 150.7 g/mol d. Cobaltous chloride: 129.9 g/mol e. Cupric nitrate: 187.5 g/mol

Step by step solution

01

1. Identify the chemical formula of each substance

a. Ferrous sulfate: \(FeSO_4\) b. Mercuric iodide: \(HgI_2\) c. Stannic oxide: \(SnO_2\) d. Cobaltous chloride: \(CoCl_2\) e. Cupric nitrate: \(Cu(NO_3)_2\)
02

2. Find the molar mass of each element in the substance

a. Ferrous sulfate (Fe: 55.8 g/mol, S: 32.1 g/mol, O: 16.0 g/mol) b. Mercuric iodide (Hg: 200.6 g/mol, I: 126.9 g/mol) c. Stannic oxide (Sn: 118.7 g/mol, O: 16.0 g/mol) d. Cobaltous chloride (Co: 58.9 g/mol, Cl: 35.5 g/mol) e. Cupric nitrate (Cu: 63.5 g/mol, N: 14.0 g/mol, O: 16.0 g/mol)
03

3. Multiply the molar mass of each element by the number of atoms in the substance

a. Ferrous sulfate: Fe: \(55.8 \times 1\), S: \(32.1 \times 1\), O: \(16.0 \times 4\) b. Mercuric iodide: Hg: \(200.6 \times 1\), I: \(126.9 \times 2\) c. Stannic oxide: Sn: \(118.7 \times 1\), O: \(16.0 \times 2\) d. Cobaltous chloride: Co: \(58.9 \times 1\), Cl: \(35.5 \times 2\) e. Cupric nitrate: Cu: \(63.5 \times 1\), N: \(14.0 \times 2\), O: \(16.0 \times 6\)
04

4. Add up the molar masses of all the elements in the substance

a. Ferrous sulfate: \(55.8 + 32.1 + (16.0 \times 4) = 151.9 \, g/mol\) b. Mercuric iodide: \(200.6 + (126.9 \times 2) = 454.4 \, g/mol\) c. Stannic oxide: \(118.7 + (16.0 \times 2) = 150.7 \, g/mol\) d. Cobaltous chloride: \(58.9 + (35.5 \times 2) = 129.9 \, g/mol\) e. Cupric nitrate: \(63.5 + (14.0 \times 2) + (16.0 \times 6) = 187.5 \, g/mol\) Molar masses of the given substances are: a. Ferrous sulfate: 151.9 g/mol b. Mercuric iodide: 454.4 g/mol c. Stannic oxide: 150.7 g/mol d. Cobaltous chloride: 129.9 g/mol e. Cupric nitrate: 187.5 g/mol

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