/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 88 For each of the following metals... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 7: Problem 88

For each of the following metals, how many electrons will the metal atoms lose when the metal reacts with a nonmetal? a. sodium b. potassium c. magnesium d. barium e. aluminum

Short Answer

Expert verified
When the given metals react with nonmetals, they will lose the following number of electrons to form positive ions (cations): a. Sodium (Na): 1 electron b. Potassium (K): 1 electron c. Magnesium (Mg): 2 electrons d. Barium (Ba): 2 electrons e. Aluminum (Al): 3 electrons

Step by step solution

01

a. Sodium

: Sodium (Na) is found in Group 1 of the periodic table, which means it has 1 valence electron. When reacting with a nonmetal, it will lose this valence electron and form a +1 cation. Therefore, sodium will lose 1 electron when reacting with a non-metal.
02

b. Potassium

: Potassium (K) is also found in Group 1 of the periodic table, meaning it has 1 valence electron similar to sodium. As a Group 1 element, potassium will lose its single valence electron when reacting with a nonmetal, forming a +1 cation. Thus, potassium will lose 1 electron when reacting with a non-metal.
03

c. Magnesium

: Magnesium (Mg) is a Group 2 element in the periodic table, which means it has 2 valence electrons. When reacting with a nonmetal, magnesium will lose both of its valence electrons, forming a +2 cation. Therefore, magnesium will lose 2 electrons when reacting with a non-metal.
04

d. Barium

: Barium (Ba) is another Group 2 element in the periodic table, meaning it also possesses 2 valence electrons. When reacting with a nonmetal, barium will lose both of its valence electrons, forming a +2 cation like magnesium. Thus, barium will lose 2 electrons when reacting with a non-metal.
05

e. Aluminum

: Aluminum (Al) is located in Group 13 of the periodic table, which indicates that it has 3 valence electrons. When reacting with a nonmetal, aluminum will lose all 3 of its valence electrons to form a +3 cation. Therefore, aluminum will lose 3 electrons when reacting with a non-metal.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Identify each of the following unbalanced reaction equations as belonging to one or more of the following categories: precipitation, acid-base, or oxidation-reduction. a. \(\operatorname{Fe}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{Fe}_{3}\left(\mathrm{SO}_{4}\right)_{2}(a q)+\mathrm{H}_{2}(g)\) b. \(\mathrm{HClO}_{4}(a q)+\mathrm{RbOH}(a q) \rightarrow \mathrm{RbClO}_{4}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) \(\overline{\mathrm{c}} . \mathrm{Ca}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{CaO}(s)\) d. \(\mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\mathrm{NaOH}(a q) \rightarrow \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) e. \(\operatorname{Pb}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{Na}_{2} \mathrm{CO}_{3}(a q) \rightarrow\) \(\mathrm{PbCO}_{3}(s)+\mathrm{NaNO}_{3}(a q)\) f. \(\mathrm{K}_{2} \mathrm{SO}_{4}(a q)+\mathrm{CaCl}_{2}(a q) \rightarrow \mathrm{KCl}(a q)+\mathrm{CaSO}_{4}(s)\) g. \(\mathrm{HNO}_{3}(a q)+\mathrm{KOH}(a q) \rightarrow \mathrm{KNO}_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) h. \(\mathrm{Ni}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}(a q)+\mathrm{Na}_{2} \mathrm{S}(a q) \rightarrow\) \(\mathrm{NiS}(s)+\mathrm{NaC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)\) i. \(\mathrm{Ni}(s)+\mathrm{Cl}_{2}(g) \rightarrow \mathrm{NiCl}_{2}(s)\)

When aqueous solutions of sodium chloride, \(\mathrm{NaCl}\) and silver nitrate, \(\mathrm{AgNO}_{3}\), are mixed, a precipitate forms, but this precipitate is not sodium nitrate. What does this reaction tell you about the solubility of \(\mathrm{NaNO}_{3}\) in water?

For each of the following unbalanced molecular equations, write the corresponding balanced net ionic equation for the reaction. a. \(\mathrm{HCl}(a q)+\mathrm{AgNO}_{3}(a q) \rightarrow \mathrm{AgCl}(s)+\mathrm{HNO}_{3}(a q)\) b. \(\mathrm{CaCl}_{2}(a q)+\mathrm{Na}_{3} \mathrm{PO}_{4}(a q) \rightarrow \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s)+\) \(\mathrm{NaCl}(a q)\) c. \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{BaCl}_{2}(a q) \rightarrow\) \(\mathrm{PbCl}_{2}(s)+\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}(a q)\) d. \(\operatorname{FeCl}_{3}(a q)+\operatorname{NaOH}(a q) \rightarrow \operatorname{Fe}(\mathrm{OH})_{3}(s)+\mathrm{NaCl}(a q)\)

For the reaction \(2 \mathrm{Al}(s)+3 \mathrm{Br}_{2}(l) \rightarrow 2 \mathrm{AlBr}_{3}(s),\) show how electrons are gained and lost by the atoms.

Reactions involving the combustion of fuel substances make up a subclass of ______ reactions.
See all solutions

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Read Explanation

Chemistry Branches

Read Explanation

Chemical Reactions

Read Explanation

Organic Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation

Inorganic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.