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Chapter 6: Problem 70

When copper(II) oxide is boiled in an aqueous solution of sulfuric acid, a strikingly blue solution of copper(II) sulfate forms along with additional water. Write the unbalanced chemical equation for this reaction.

Short Answer

Expert verified
The unbalanced chemical equation for the reaction between copper(II) oxide (CuO) and sulfuric acid (H鈧係O鈧�) is: \( \text{CuO} + \text{H鈧係O鈧剗 \to \text{CuSO鈧剗 + \text{H鈧侽} \)

Step by step solution

01

Identify Reactants and Products

The reactants in this reaction are copper(II) oxide (CuO) and sulfuric acid (H鈧係O鈧�). During the reaction, a blue solution of copper(II) sulfate (CuSO鈧�) forms as a product, along with additional water (H鈧侽).
02

Write the Unbalanced Chemical Equation

Now that we know the reactants and products, we can write the unbalanced chemical equation for this reaction: \( \text{CuO} + \text{H鈧係O鈧剗 \to \text{CuSO鈧剗 + \text{H鈧侽} \) This is the unbalanced chemical equation for the reaction between copper(II) oxide and sulfuric acid, and it shows that copper(II) sulfate and water are produced during the reaction.

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