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Carbon tetrachloride was widely used for many years as a solvent until its harmful properties became well established. Carbon tetrachloride may be prepared by the reaction of natural gas (methane, \(\mathrm{CH}_{4}\) ) and elemental chlorine gas in the presence of ultraviolet light. Write the unbalanced chemical equation for this process.

Short Answer

Expert verified
The balanced chemical equation for the reaction of methane (\(\mathrm{CH}_{4}\)) and chlorine gas (\(\mathrm{Cl}_{2}\)) to form carbon tetrachloride (\(\mathrm{CCl}_{4}\)) is: \[ \mathrm{CH}_{4} + 2\mathrm{Cl}_{2} \rightarrow \mathrm{CCl}_{4} \]

Step by step solution

01

Identify the reactants and product

The reactants in this chemical reaction are natural gas (methane, \(\mathrm{CH}_{4}\)) and elemental chlorine gas (\(\mathrm{Cl}_{2}\)). The product formed in this reaction is carbon tetrachloride (\(\mathrm{CCl}_{4}\)).
02

Write the unbalanced chemical equation

Now that we have identified the reactants and product, we can write the unbalanced chemical equation representing the reaction: $$ \mathrm{CH}_{4} + \mathrm{Cl}_{2} \rightarrow \mathrm{CCl}_{4} $$ The equation is unbalanced because the number of atoms of each element isn't equal on both sides. We need to find the appropriate coefficients (numbers in front of the compounds) to balance the equation.
03

Balance the chemical equation

To balance the equation, let's first check the number of chlorine atoms. The product has 4 chlorine atoms, so we need 4 chlorine atoms in the reactants as well. To balance this, we place a coefficient of 2 in front of elemental chlorine gas since it has a formula of \({Cl_2}\). The balanced equation now becomes: $$ \mathrm{CH}_{4} + 2\mathrm{Cl}_{2} \rightarrow \mathrm{CCl}_{4} $$ Now, we need to check the other atoms. There is one carbon atom and four hydrogen atoms on each side of the equation, so our equation is correctly balanced. Here is the final balanced chemical equation for the reaction of methane and chlorine gas to form carbon tetrachloride: $$ \mathrm{CH}_{4} + 2\mathrm{Cl}_{2} \rightarrow \mathrm{CCl}_{4} $$

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Most popular questions from this chapter

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