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Chapter 5: Problem 87

Write the formula for each of the following chromium-containing ions, including the overall charge of the ion. a. chromous b. chromate c. chromic d. dichromate

Short Answer

Expert verified
a. Chromous: \(\text{Cr}^{2+}\) b. Chromate: \(\text{CrO}_4^{2-}\) c. Chromic: \(\text{Cr}^{3+}\) d. Dichromate: \(\text{Cr}_2\text{O}_7^{2-}\)

Step by step solution

01

a. Chromous

Chromous indicates that chromium is in its +2 oxidation state. Thus, the ion is represented as \(\text{Cr}^{2+}\).
02

b. Chromate

Chromate is a polyatomic ion containing chromium in its +6 oxidation state. The chromate ion has the formula \(\text{CrO}_4^{2-}\). The overall charge of the chromate ion is -2.
03

c. Chromic

Chromic indicates that chromium is in its +3 oxidation state. Therefore, the ion is represented as \(\text{Cr}^{3+}\).
04

d. Dichromate

Dichromate is a polyatomic ion containing two chromium atoms in their +6 oxidation state. The dichromate ion has the formula \(\text{Cr}_2\text{O}_7^{2-}\). The overall charge of the dichromate ion is -2. In summary, the formulas and overall charges for the given chromium-containing ions are: a. Chromous: \(\text{Cr}^{2+}\) b. Chromate: \(\text{CrO}_4^{2-}\) c. Chromic: \(\text{Cr}^{3+}\) d. Dichromate: \(\text{Cr}_2\text{O}_7^{2-}\)

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Most popular questions from this chapter

What is an oxyanion? How is a series of oxyanions named? (Give an example.)

What is a polyatomic ion? Give examples of five common polyatomic ions.

Write the formula for each of the following carboncontaining polyatomic ions, including the overall charge of the ion. a. carbonate b. hydrogen carbonate c. acetate d. cyanide

Write the name of each of the following ionic substances, using the system that includes a Roman numeral to specify the charge of the cation. a. \(\mathrm{SnO}\) d. \(\mathrm{Cu}_{2} \mathrm{S}\) b. \(\operatorname{SnO}_{2}\) e. \(\mathrm{FeCl}_{3}\) c. \(CuS\) f. \(\mathrm{Fel}_{2}\)

When we write the formula for an ionic compound, we are merely indicating the relative numbers of each type of ion in the compound, not the presence of "molecules" in the compound with that formula. Explain.
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