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Are carboxylic acids typically strong acids or weak acids? Write an equation showing the acid \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH}\) ionizing in water.

Short Answer

Expert verified
Carboxylic acids are typically weak acids, meaning they partially dissociate in water. The ionization equation for propanoic acid (CH鈧僀H鈧侰OOH) in water is: \[ CH_{3}CH_{2}COOH \ + \ H_{2}O \ \rightleftharpoons \ CH_{3}CH_{2}COO^{-} \ + \ H_{3}O^{+} \] This equation shows the acid reacts with water, forming a carboxylate ion (CH鈧僀H鈧侰OO鈦) and a hydronium ion (H鈧僌鈦), with the equilibrium indicated by the double arrows (\(\rightleftharpoons\)).

Step by step solution

01

Identify the strength of carboxylic acids

Carboxylic acids are typically weak acids. They partially dissociate in water, producing a relatively small concentration of hydrogen ions (H鈦) and leaving the majority of the acid molecules intact.
02

Write the ionization equation for CH鈧僀H鈧侰OOH in water

To show the ionization of CH鈧僀H鈧侰OOH (propanoic acid) in water, we need to write a balanced equation. The reaction involves the transfer of a proton (H鈦) from the carboxylic acid to a water molecule, forming a hydronium ion (H鈧僌鈦) and a carboxylate ion. The ionization equation for propanoic acid (CH鈧僀H鈧侰OOH) in water is: \[ CH_{3}CH_{2}COOH \ + \ H_{2}O \ \rightleftharpoons \ CH_{3}CH_{2}COO^{-} \ + \ H_{3}O^{+} \] This equation shows that propanoic acid (CH鈧僀H鈧侰OOH) reacts with water (H鈧侽) and reaches an equilibrium with the conjugate base CH鈧僀H鈧侰OO鈦 and the hydronium ion H鈧僌鈦. The double arrows (\(\rightleftharpoons\)) indicate a state of equilibrium, where the forward and reverse reactions occur at the same rate, typical of weak acids in water.

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