Chapter 16: Problem 55
Why does the amount of excess solid solute present in a solution not affect the amount of solute that ultimately dissolves in a given amount of solvent?
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Chapter 16: Problem 55
Why does the amount of excess solid solute present in a solution not affect the amount of solute that ultimately dissolves in a given amount of solvent?
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When a reaction system has reached chemical equilibrium, the concentrations of the reactants and products no longer changes with time. Why does the amount of product no longer increase, even though large concentrations of the reactants may still be present?
For a given reaction at a given temperature, the special ratio of products to reactants defined by the equilibrium constant is always equal to the same number. Explain why this is true, no matter what initial concentrations of reactants (or products) may have been taken in setting up an experiment.
How do chemists define a state of chemical equilibrium?
Approximately 0.14 g of nickel(II) hydroxide, \(\mathrm{Ni}(\mathrm{OH})_{2}(s),\) dissolves per liter of water at \(20^{\circ} \mathrm{C} .\) Calculate \(K_{\mathrm{sp}}\) for \(\mathrm{Ni}(\mathrm{OH})_{2}(s)\) at this temperature.
Mercuric sulfide, HgS, is one of the least soluble salts known, with \(K_{\mathrm{sp}}=1.6 \times 10^{-54}\) at \(25^{\circ} \mathrm{C} .\) Calculate the solubility of HgS in moles per liter and in grams per liter.
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