Chapter 5: Problem 13
Calculate the mass of each product when \(100.0 \mathrm{~g}\) of CuCl react according to the reaction \(2 \mathrm{CuCl}(\mathrm{aq}) \rightarrow \mathrm{CuCl}_{2}(\mathrm{aq})+\mathrm{Cu}(\mathrm{s})\) What do you notice about the sum of the masses of the products? What concept is being illustrated here?
Short Answer
Step by step solution
Understand the Reaction and It's Stoichiometry
Calculate Moles of CuCl
Determine Moles of Products Formed
Calculate Mass of Cu Produced
Calculate Mass of CuClâ‚‚ Produced
Verify Mass Conservation and Identify the Concept
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molar Mass
This concept is crucial in helping convert grams to moles and vice versa. Grams tell us about the mass, but in chemical reactions, we relate substances in moles to best compare them on a molecular level.
- To calculate moles from a given mass, use the formula: \[\text{Moles} = \frac{\text{Given Mass}}{\text{Molar Mass}}\]
- This allows us to determine the amount of reactants and products involved in a chemical reaction.
Conservation of Mass
In the given exercise, you can see this principle at play. When 100.0 g of CuCl react,
- We calculated the mass of copper (Cu) produced to be 32.08 g.
- The mass of copper(II) chloride (CuClâ‚‚) produced was determined to be 67.90 g.
The slight discrepancy you noticed is due to calculation rounding, reminding us to always be mindful of significant figures and accuracy in our computations.
Chemical Reaction
In this particular exercise, the reaction: \[2 \text{CuCl} \rightarrow \text{CuCl}_2 + \text{Cu}\]shows copper(I) chloride (CuCl) reacting to form copper (Cu) and copper(II) chloride (CuClâ‚‚). Chemical reactions are guided by stoichiometry, which tells us the proportions of molecules involved based on their coefficients in the balanced equation.
- In our reaction, two moles of CuCl yield one mole of CuClâ‚‚ and one mole of Cu.