Chapter 15: Problem 11
Uranium hexafluoride (UF \(_{6}\) ) reacts with water to make uranyl fluoride \(\left(\mathrm{UO}_{2} \mathrm{~F}_{2}\right)\) and \(\mathrm{HF}\). Balance the following reaction: \(\mathrm{UF}_{6}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{UO}_{2} \mathrm{~F}_{2}+\mathrm{HF}\)
Short Answer
Expert verified
The balanced equation is: UF
_{6} + 2
_{H}_{2}O
_{→} UO
_{2}
_{F}_{2} + 4
_{HF}.
Step by step solution
01
Write the Unbalanced Equation
The first step is to write down the unbalanced chemical equation:\[\text{UF}_6 + \text{H}_2\text{O} \rightarrow \text{UO}_2\text{F}_2 + \text{HF}\]
02
Identify the Atoms in the Reaction
List the different types of atoms present on the reactants side and the products side: U (uranium), F (fluorine), H (hydrogen), and O (oxygen).
03
Balance Uranium Atoms
There is 1 uranium atom on the reactants side and 1 uranium atom in \(\text{UO}_2\text{F}_2\) on the products side, so no change is needed for uranium.
04
Balance Fluorine Atoms
There are 6 fluorine atoms from \(\text{UF}_6\) on the reactants side and a total of \(2 + x\) fluorine atoms from \(\text{UO}_2\text{F}_2\) and \(x\) \(\text{HF}\) on the products side. Set up the equation:\[6 = 2 + x\]Solving gives \(x = 4\), so add a coefficient of 4 in front of HF: \[\text{UF}_6 + \text{H}_2\text{O} \rightarrow \text{UO}_2\text{F}_2 + 4\text{HF}\]
05
Balance Hydrogen Atoms
Now, the right side has \(4\) hydrogen atoms (from \(4\text{HF}\)), so you need \(2\) water molecules to provide those \(4\) hydrogen atoms. Change the coefficient for \(\text{H}_2\text{O}\):\[\text{UF}_6 + 2\text{H}_2\text{O} \rightarrow \text{UO}_2\text{F}_2 + 4\text{HF}\]
06
Balance Oxygen Atoms
Check the oxygen atoms. On the left, there are 2 from \(2\text{H}_2\text{O}\), and on the right, there are 2 in \(\text{UO}_2\text{F}_2\). Oxygen is balanced.
07
Confirm the Balanced Equation
Now, verify that all atoms are balanced: 1 Uranium, 6 Fluorine, 4 Hydrogen, and 2 Oxygen atoms on both sides. The balanced equation is:\[\text{UF}_6 + 2\text{H}_2\text{O} \rightarrow \text{UO}_2\text{F}_2 + 4\text{HF}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chemical Reactions
A chemical reaction is a process where substances (reactants) are transformed into different substances (products). This transformation happens at a molecular level as bonds are broken in reactants and new bonds are formed to create the products. In our example, uranium hexafluoride (UF\( _6 \)) reacts with water (H\( _2 \)O) and undergoes a chemical transformation resulting in uranyl fluoride (UO\( _2 \)F\( _2 \)) and hydrogen fluoride (HF). Understanding the representation of chemical reactions through chemical equations is crucial:
- Reactants are written on the left side of the equation.
- Products are written on the right side of the equation.
- An arrow indicates the direction of the transformation.
Stoichiometry
Stoichiometry involves the calculation of reactants and products in chemical reactions. It relies on the concept of a balanced equation to provide relationships between the amounts of reactants used and products formed.For the reaction UF\( _6 \) + H\( _2 \)O → UO\( _2 \)F\( _2 \) + HF, stoichiometry helps us determine the amount of each substance involved:
- Coefficients: The numbers placed before compounds in equations denote the number of molecules (or moles) of each substance. In the balanced equation UF\( _6 \) + 2H\( _2 \)O → UO\( _2 \)F\( _2 \) + 4HF, these coefficients are crucial for stoichiometric calculations.
- Mole Ratio: This ratio is determined from the coefficients and is used to calculate how many moles of a reactant will produce a given number of moles of a product.
Uranium Hexafluoride
Uranium hexafluoride (UF\( _6 \)) is an important compound in the nuclear industry. Its primary use is in the production of fuel for nuclear reactors and atomic bombs. UF\( _6 \) is used in the enrichment process where uranium is converted to a gaseous form to separate isotopes.Here are some interesting aspects about UF\( _6 \):
- Physical State: UF\( _6 \) is a solid at room temperature but sublimates (turns directly from a solid to a gas) at slightly higher temperatures.
- Reactivity: It reacts with water to produce uranyl fluoride and hydrogen fluoride, as demonstrated in the balanced reaction UF\( _6 \) + 2H\( _2 \)O → UO\( _2 \)F\( _2 \) + 4HF. This reaction is significant in processing UF\( _6 \) for further use.
- Safety Considerations: Both UF\( _6 \) and HF are highly corrosive and toxic, requiring careful handling and the use of appropriate safety measures.