Chapter 13: Problem 16
What is \(\left[\mathrm{OH}^{-}\right]\) in a solution whose \(\left[\mathrm{H}^{+}\right]\) is \(9.44 \times 10^{-11} \mathrm{M} ?\)
Short Answer
Expert verified
\( \left[ \mathrm{OH}^{-} \right] = 1.06 \times 10^{-4} \mathrm{M} \).
Step by step solution
01
Understanding the Relationship Between \\( \left[ \mathrm{H}^{+} \right] \\) and \\( \left[ \mathrm{OH}^{-} \right] \\)
To solve this problem, we need to use the relationship between the hydrogen ion concentration \( \left[ \mathrm{H}^{+} \right] \) and hydroxide ion concentration \( \left[ \mathrm{OH}^{-} \right] \). At 25°C, the product of these two concentrations in water is a constant:\[\left[ \mathrm{H}^{+} \right] \times \left[ \mathrm{OH}^{-} \right] = 1.0 \times 10^{-14} \text{ M}^2\]This expression is known as the water ion-product constant, \( K_w \).
02
Solving for \\( \left[ \mathrm{OH}^{-} \right] \\)
Given \( \left[ \mathrm{H}^{+} \right] = 9.44 \times 10^{-11} \mathrm{M} \,\) substitute this value into the ion-product constant equation to find \( \left[ \mathrm{OH}^{-} \right] \):\[\left[ \mathrm{OH}^{-} \right] = \frac{K_w}{\left[ \mathrm{H}^{+} \right]}\]Substitute \( K_w = 1.0 \times 10^{-14} \text{ M}^2 \) and \( \left[ \mathrm{H}^{+} \right] = 9.44 \times 10^{-11} \mathrm{M} \):\[\left[ \mathrm{OH}^{-} \right] = \frac{1.0 \times 10^{-14}}{9.44 \times 10^{-11}}\]
03
Calculating the \\( \left[ \mathrm{OH}^{-} \right] \\) Value
Perform the division from Step 2:\[\left[ \mathrm{OH}^{-} \right] = \frac{1.0 \times 10^{-14}}{9.44 \times 10^{-11}} = 1.06 \times 10^{-4} \mathrm{M}\]Thus, the hydroxide ion concentration is approximately \( 1.06 \times 10^{-4} \mathrm{M} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Water Ion-Product Constant (K_w)
The water ion-product constant, often symbolized as \( K_w \), is a crucial concept when dealing with ion concentration in aqueous solutions. At 25°C, pure water continuously undergoes a self-ionization process where it dissociates into equal concentrations of hydrogen ions \( \left[ \mathrm{H}^{+} \right] \) and hydroxide ions \( \left[ \mathrm{OH}^{-} \right] \). The product of these concentrations is a constant value:
This powerful relationship means that if you know the concentration of one ion, \( \left[ \mathrm{H}^{+} \right] \) or \( \left[ \mathrm{OH}^{-} \right] \), you can easily determine the concentration of the other using the formula \( \left[ \mathrm{OH}^{-} \right] = \frac{K_w}{\left[ \mathrm{H}^{+} \right]} \). In essence, \( K_w \) is the key that maintains the balance between acidity and basicity in water.
- \( K_w = \left[ \mathrm{H}^{+} \right] \times \left[ \mathrm{OH}^{-} \right] = 1.0 \times 10^{-14} \text{ M}^2 \)
This powerful relationship means that if you know the concentration of one ion, \( \left[ \mathrm{H}^{+} \right] \) or \( \left[ \mathrm{OH}^{-} \right] \), you can easily determine the concentration of the other using the formula \( \left[ \mathrm{OH}^{-} \right] = \frac{K_w}{\left[ \mathrm{H}^{+} \right]} \). In essence, \( K_w \) is the key that maintains the balance between acidity and basicity in water.
Hydrogen Ion Concentration (H^+)
Understanding hydrogen ion concentration \( \left[ \mathrm{H}^{+} \right] \) is essential for determining the pH and acidic nature of solutions. The acidity of a solution is directly related to how many \( \mathrm{H}^{+} \) ions it contains.
In pure water at 25°C, the concentration of \( \mathrm{H}^{+} \) ions is \( 1.0 \times 10^{-7} \text{ M} \). In solutions, however, this concentration varies leading to different pH levels.
In pure water at 25°C, the concentration of \( \mathrm{H}^{+} \) ions is \( 1.0 \times 10^{-7} \text{ M} \). In solutions, however, this concentration varies leading to different pH levels.
- An increase in \( \left[ \mathrm{H}^{+} \right] \) indicates a more acidic solution.
- A decrease means a more basic or alkaline solution.
- pH = -\( \log_{10} \left[ \mathrm{H}^{+} \right] \)
- Acidic solutions have a pH less than 7
- Neutral solutions have a pH of 7
- Basic solutions have a pH greater than 7
Hydroxide Ion Concentration (OH^-)
Hydroxide ion concentration \( \left[ \mathrm{OH}^{-} \right] \) is pivotal when examining the basic nature of a solution. The presence of \( \mathrm{OH}^{-} \) ions indicates the capacity of a solution to neutralize acids. Just like \( \left[ \mathrm{H}^{+} \right] \), the concentration of \( \left[ \mathrm{OH}^{-} \right] \) changes depending on whether a solution is acidic or basic.
In the exercise, we found that \( \left[ \mathrm{H}^{+} \right] \) was \( 9.44 \times 10^{-11} \mathrm{M} \), leading to \( \left[ \mathrm{OH}^{-} \right] \) being approximately \( 1.06 \times 10^{-4} \mathrm{M} \).
Knowing \( \left[ \mathrm{OH}^{-} \right] \) in a solution is crucial for calculating pOH, which follows the relationship \( \text{pOH} = -\log_{10} \left[ \mathrm{OH}^{-} \right] \).
This relationship complements the pH scale and helps in deducing the overall nature of the solution.
- In a basic solution, \( \left[ \mathrm{OH}^{-} \right] \) is higher than \( 1.0 \times 10^{-7} \text{ M} \).
- For acidic solutions, \( \left[ \mathrm{OH}^{-} \right] \) is lower than \( 1.0 \times 10^{-7} \text{ M} \).
In the exercise, we found that \( \left[ \mathrm{H}^{+} \right] \) was \( 9.44 \times 10^{-11} \mathrm{M} \), leading to \( \left[ \mathrm{OH}^{-} \right] \) being approximately \( 1.06 \times 10^{-4} \mathrm{M} \).
Knowing \( \left[ \mathrm{OH}^{-} \right] \) in a solution is crucial for calculating pOH, which follows the relationship \( \text{pOH} = -\log_{10} \left[ \mathrm{OH}^{-} \right] \).
This relationship complements the pH scale and helps in deducing the overall nature of the solution.