Chapter 12: Problem 7
Write the balanced chemical equation for the neutralization reaction between \(\mathrm{KOH}\) and \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\). What is the salt?
Short Answer
Expert verified
The balanced equation is \(2\mathrm{KOH} + \mathrm{H}_2\mathrm{C}_2\mathrm{O}_4 \rightarrow \mathrm{K}_2\mathrm{C}_2\mathrm{O}_4 + 2\mathrm{H}_2\mathrm{O}\). The salt is potassium oxalate \(\mathrm{K}_2\mathrm{C}_2\mathrm{O}_4\).
Step by step solution
01
Write Down the Reactants
In a neutralization reaction, an acid reacts with a base to form salt and water. Here, potassium hydroxide \(\mathrm{KOH}\) is the base, and oxalic acid \(\mathrm{H}_2\mathrm{C}_2\mathrm{O}_4\) is the acid. Write down the reactants:\[\mathrm{KOH} + \mathrm{H}_2\mathrm{C}_2\mathrm{O}_4}\]
02
Identify the Products
In a neutralization reaction, the products are a salt and water. For \(\mathrm{KOH}\), the cation is \(\mathrm{K^+}\), and for \(\mathrm{H}_2\mathrm{C}_2\mathrm{O}_4\), the anion is \(\mathrm{C}_2\mathrm{O}_4^{2-}\). The salt formed will be \(\mathrm{K}_2\mathrm{C}_2\mathrm{O}_4\), and water \(\mathrm{H}_2\mathrm{O}\) will be another product.
03
Write the Unbalanced Equation
Combine the identified reactants and products in an unbalanced chemical equation:\[\mathrm{KOH} + \mathrm{H}_2\mathrm{C}_2\mathrm{O}_4 \rightarrow \mathrm{K}_2\mathrm{C}_2\mathrm{O}_4 + \mathrm{H}_2\mathrm{O}\]
04
Balance the Chemical Equation
To balance the equation, make sure there are equal numbers of each type of atom on both sides. For potassium (K), you have 2 potassium atoms on the product side in \(\mathrm{K}_2\mathrm{C}_2\mathrm{O}_4\), so use 2 \(\mathrm{KOH}\) molecules:\[2\mathrm{KOH} + \mathrm{H}_2\mathrm{C}_2\mathrm{O}_4 \rightarrow \mathrm{K}_2\mathrm{C}_2\mathrm{O}_4 + 2\mathrm{H}_2\mathrm{O}\]
05
Verify the Balanced Equation
Check each element:- Potassium (K): 2 on each side- Hydrogen (H): 4 on each side- Carbon (C): 2 on each side- Oxygen (O): 6 on each sideThe balanced equation is:\[2\mathrm{KOH} + \mathrm{H}_2\mathrm{C}_2\mathrm{O}_4 \rightarrow \mathrm{K}_2\mathrm{C}_2\mathrm{O}_4 + 2\mathrm{H}_2\mathrm{O}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Balancing Chemical Equations
Balancing chemical equations is a fundamental skill in chemistry. It ensures that the law of conservation of mass is upheld, meaning the total mass of reactants equals the total mass of products.
In a chemical reaction, the number of atoms of each element must be the same on both sides of the equation. Let's take a closer look at how this is done with the neutralization of potassium hydroxide ( KOH ) and oxalic acid ( H_2C_2O_4 ).
When we write down the unbalanced reaction for neutralization, we have:
In a chemical reaction, the number of atoms of each element must be the same on both sides of the equation. Let's take a closer look at how this is done with the neutralization of potassium hydroxide ( KOH ) and oxalic acid ( H_2C_2O_4 ).
When we write down the unbalanced reaction for neutralization, we have:
- Reactants: KOH and H_2C_2O_4
- Products: K_2C_2O_4 and H_2O
- Count and compare each type of atom on both sides.
- Adjust coefficients to have the same number of each atom on each side.
- Continue until the numbers are balanced."
Understanding Acid-Base Reactions
Acid-base reactions are a type of chemical reaction where an acid reacts with a base, resulting in the formation of water and a salt.
This is commonly referred to as a neutralization reaction since the acid and base effectively neutralize each other's properties.
In our example, potassium hydroxide ( KOH ) acts as the base, and oxalic acid ( H_2C_2O_4 ) acts as the acid.
The following steps occur in an acid-base reaction:
This is commonly referred to as a neutralization reaction since the acid and base effectively neutralize each other's properties.
In our example, potassium hydroxide ( KOH ) acts as the base, and oxalic acid ( H_2C_2O_4 ) acts as the acid.
The following steps occur in an acid-base reaction:
- The hydrogen ions (\(\mathrm{H^+}\)) from the acid combine with the hydroxide ions (\(\mathrm{OH^-}\)) from the base to form water (\(\mathrm{H_2O}\)).
- The cation from the base ( K^+ from KOH ) combines with the anion from the acid ( C_2O_4^{2-} from H_2C_2O_4 ) to form the salt ( K_2C_2O_4 ).
Salt Formation in Reactions
Salt formation occurs in a neutralization reaction such as the one between an acid and a base. In this process, the cations from the base bond with the anions from the acid, creating a compound known as salt.
In our neutralization reaction:
In our neutralization reaction:
- The base is potassium hydroxide ( KOH ), providing K^+ ions.
- The acid is oxalic acid ( H_2C_2O_4 ), providing C_2O_4^{2-} ions.
- The resulting salt is potassium oxalate ( K_2C_2O_4 ).
- Salts usually consist of the ions that remain after H^+ and OH^- ions combine to form water.
- The formation of salt is what gives neutralization reactions their characteristic result—neutral solutions if neither the acid nor the base is in excess.
- This process not only forms water but yields a salt that may have practical uses, such as flavoring, preservation, or in industrial applications.