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Show how the amphiprotic ion hydrogen carbonate, \(\mathrm{HCO}_{3}^{-},\) can react as both an acid and a base.

Short Answer

Expert verified
HCO鈧冣伝 acts as an acid by donating H鈦 to form CO鈧兟测伝 and as a base by accepting H鈦 to form H鈧侰O鈧.

Step by step solution

01

Define Amphiprotic

Amphiprotic ions are capable of acting as either an acid or a base. An amphiprotic species must have at least one hydrogen atom that can be donated and must also be able to accept a hydrogen ion.
02

Reaction as an Acid

When \text{HCO}_{3}^{-} acts as an acid, it donates a hydrogen ion. The reaction with water is as follows:\[ \text{HCO}_{3}^{-} (aq) + \text{H}_{2}\text{O} (l) \rightarrow \text{CO}_{3}^{2-} (aq) + \text{H}_{3}\text{O}^{+} (aq) \]This reaction shows \text{HCO}_{3}^{-} donating a proton to water, forming the carbonate ion \text{CO}_{3}^{2-}.
03

Reaction as a Base

When \text{HCO}_{3}^{-} acts as a base, it accepts a hydrogen ion. The reaction with water is as follows:\[ \text{HCO}_{3}^{-} (aq) + \text{H}_{2}\text{O} (l) \rightarrow \text{H}_{2}\text{CO}_{3} (aq) + \text{OH}^{-} (aq) \]In this reaction, \text{HCO}_{3}^{-} accepts a proton from water, forming carbonic acid \text{H}_{2}\text{CO}_{3}.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Reactions
Acid-base reactions are fundamental processes that involve the transfer of protons (hydrogen ions) between reactants. In chemistry, an acid is defined as a substance that can donate a proton to another substance, while a base is one that can accept a proton. These reactions are vital to understanding how various substances interact in solution.

In an acid-base reaction, we often see the use of indicators to determine the endpoint of a reaction. However, it is the role of amphiprotic species like hydrogen carbonate (\(\text{HCO}_{3}^{-}\)), which makes these reactions particularly intriguing. Amphiprotic ions have the unique ability to act either as an acid or a base, which allows them to donate or accept protons depending on the reaction environment. This dual ability plays a crucial role in many biological and chemical processes.

Understanding the behavior of amphiprotic ions like \(\text{HCO}_{3}^{-}\) is essential for predicting how certain substances will behave in different chemical environments. This knowledge is particularly useful in fields such as biochemistry, environmental science, and industrial chemistry.
Hydrogen Carbonate
Hydrogen carbonate, also known as bicarbonate and denoted as \(\text{HCO}_{3}^{-}\), is an interesting ion because of its amphiprotic nature. Being amphiprotic means \(\text{HCO}_{3}^{-}\) can participate in acid-base reactions both as an acid and as a base.

When hydrogen carbonate acts as an acid, it donates a proton to form a carbonate ion (\(\text{CO}_{3}^{2-}\)). Here鈥檚 how the reaction takes place with water: \(\text{HCO}_{3}^{-} + \text{H}_{2}\text{O} \rightarrow \text{CO}_{3}^{2-} + \text{H}_{3}\text{O}^{+}\). This reaction highlights its ability to release a hydrogen ion, thus behaving like an acid.
  • Formation of carbonate ion \(\text{CO}_{3}^{2-}\)
  • Provision of hydronium ion \(\text{H}_{3}\text{O}^{+}\)

On the other hand, when acting as a base, \(\text{HCO}_{3}^{-}\) accepts a proton, resulting in the formation of carbonic acid (\(\text{H}_{2}\text{CO}_{3}\)). The reaction with water looks like this: \(\text{HCO}_{3}^{-} + \text{H}_{2}\text{O} \rightarrow \text{H}_{2}\text{CO}_{3} + \text{OH}^{-}\). Here, hydrogen carbonate acts as a base as it accepts a proton from the water.
  • Formation of carbonic acid \(\text{H}_{2}\text{CO}_{3}\)
  • Release of hydroxide ion \(\text{OH}^{-}\)

This amphiprotic characteristic of \(\text{HCO}_{3}^{-}\) is what makes it so versatile and crucial in maintaining various natural and chemical equilibrium processes.
Chemical Equilibrium
Chemical equilibrium occurs when the rates of the forward and reverse reactions are equal, resulting in no net change in the concentration of reactants and products. In acid-base reactions involving amphiprotic ions like \(\text{HCO}_{3}^{-}\), equilibrium plays a key role.

During these reactions, you will notice that while \(\text{HCO}_{3}^{-}\) can act as both an acid and a base, the actual behavior depends on the surrounding conditions鈥攕uch as pH, concentration, and the presence of other ions. The equilibrium is established when \(\text{HCO}_{3}^{-}\) alternates between donating and accepting protons until a balance is reached.

A stable equilibrium ensures that the solution maintains a consistent pH over time, an essential factor in biological systems and industrial processes alike. For instance, in the human body, hydrogen carbonate is a key component of the bicarbonate buffer system that regulates blood pH. This system relies heavily on the equilibrium established among bicarbonate, carbonic acid, and carbon dioxide.
  • Dynamic balance in reactions involving \(\text{HCO}_{3}^{-}\)
  • Impact on solution pH and stability
  • Essential role in buffer systems

Grasping the concept of chemical equilibrium is vital to understanding and predicting how amphiprotic ions like hydrogen carbonate will react in various chemical and environmental contexts.

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Most popular questions from this chapter

Over the past 250 years, the average upper-ocean pH near the Pacific Northwest has decreased by about 0.1 units, from about 8.2 to \(8.1 .\) This drop in pH corresponds to an increase in acidity of about \(30 \%\). When \(\mathrm{CO}_{2}\) levels in seawater rise, the availability of carbonate ion, \(\mathrm{CO}_{3}^{2-},\) decreases. This makes it more difficult for marine organisms to build and maintain shells and other body parts from calcium carbonate. (a) Calculate \(\mathrm{H}_{3} \mathrm{O}^{+}\) and \(\mathrm{OH}^{-}\) concentrations at \(\mathrm{pH}\) levels of 8.2 and 8.1. (b) Demonstrate by calculations that this decrease in \(\mathrm{pH}\) corresponds to an increase in acidity of about \(30 \%\). (c) Explain the relationship between the pH of seawater and the availability of carbonate ion. Does the change in pH from 8.2 to 8.1 result in an increase or decrease in the availability of carbonate ion?

Write the formula for the conjugate acid of each base. (a) \(\mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{HPO}_{4}^{2-}\) (c) \(\mathrm{CH}_{3} \mathrm{NH}_{2}\) (d) \(\mathrm{PO}_{4}^{3-}\)

Write the formula for the conjugate base of each acid. (a) \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) (b) \(\mathrm{H}_{2} \mathrm{S}\) (c) \(\mathrm{HCO}_{3}^{-}\) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) (e) \(\mathrm{H}_{2} \mathrm{O}\)

The pH of a \(0.10 \mathrm{M}\) solution of acetic acid is 2.93. When 0.10 mol of sodium acetate, \(\mathrm{CH}_{3} \mathrm{COONa}\), is added to this solution, its pH changes to 4.74 Explain why the pH changes and why it changes to this particular value.

A scale of \(K_{\mathrm{b}}\) values for bases could be set up in a manner similar to that for the \(K_{\mathrm{a}}\) scale for acids. However, this setup is generally considered unnecessary. Explain.

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