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Answer true or false. (a) The mole is a counting unit, just as a dozen is a counting unit. (b) Avogadro's number is the number of formula units in one mole. (c) Avogadro's number, to three significant figures, is \(6.02 \times 10^{23}\) formula units per mole. (d) \(1 \mathrm{mol}\) of \(\mathrm{H}_{2} \mathrm{O}\) contains \(3 \times 6.02 \times 10^{23}\) formula units. (e) \(1 \mathrm{mol}\) of \(\mathrm{H}_{2} \mathrm{O}\) has the same number of molecules as \(1 \mathrm{mol}\) of \(\mathrm{H}_{2} \mathrm{O}_{2}\) (f) The molar mass of a compound is its formula weight expressed in amu. (g) The molar mass of \(\mathrm{H}_{2} \mathrm{O}\) is \(18 \mathrm{g} / \mathrm{mol}\). (h) \(1 \mathrm{mol}\) of \(\mathrm{H}_{2} \mathrm{O}\) has the same molar mass as \(1 \mathrm{mol}\) of \(\mathrm{H}_{2} \mathrm{O}_{2}\) (i) 1 mol of ibuprofen, \(C_{13} H_{18} O_{2},\) contains 33 mol of atoms. (j) To convert moles to grams, multiply by Avogadro's number. (k) To convert grams to moles, divide by molar mass. (1) \(1 \mathrm{mol}\) of \(\mathrm{H}_{2} \mathrm{O}\) contains \(1 \mathrm{mol}\) of hydrogen atoms and one mol of oxygen atoms. \((\mathrm{m}) 1 \mathrm{mol}\) of \(\mathrm{H}_{2} \mathrm{O}\) contains \(2 \mathrm{g}\) of hydrogen atoms and 1 g of oxygen atoms. (n) 1 mole of \(\mathrm{H}_{2} \mathrm{O}\) contains \(18.06 \times 10^{23}\) atoms.

Short Answer

Expert verified
a) True, b) True, c) True, d) True, e) True, f) False, g) True, h) False, i) True, j) False, k) True, l) False, m) False, n) True.

Step by step solution

01

Comparison of Counting Units

Both a mole and a dozen are counting units. A dozen always refers to 12 items, while a mole refers to approximately \(6.022 \times 10^{23}\) entities. Therefore, statement (a) is true.
02

Definition of Avogadro's Number

Avogadro's number is defined as the number of elementary entities (atoms, molecules, etc.) per mole of substance. This corresponds with statement (b), which describes the number of formula units in one mole, making statement (b) true.
03

Scientific Notation for Avogadro's Number

Avogadro's number, rounded to three significant figures, is correctly written as \(6.02 \times 10^{23}\). This makes statement (c) true.
04

Calculating Moles of Atoms in a Compound

For statement (d), \(1 \text{ mole of } \text{H}_2\text{O}\) consists of 1 mole of water molecules, which includes 2 moles of hydrogen atoms and 1 mole of oxygen atoms. Therefore, \(3 \times 6.02 \times 10^{23}\) formula units is correct, making statement (d) true.
05

Molecular Consistency Across Substances

Statement (e) holds true as 1 mole of any substance contains the same number of molecules, \(6.022 \times 10^{23}\), irrespective of their chemical nature. Hence, (e) is true.
06

Definition of Molar Mass

Molar mass is the mass of one mole of a substance, measured in grams, not amu. Therefore, statement (f) is false.
07

Calculation of Water Molar Mass

The molar mass of \(\text{H}_2\text{O}\) is calculated as 2*(1 g/mol) for hydrogen + 16 g/mol for oxygen, totaling 18 g/mol. Therefore, statement (g) is true.
08

Comparison of Molar Masses in Compounds

Statement (h) is false as \(1 \text{ mol of } \text{H}_2\text{O}_2\) (hydrogen peroxide) has a different molar mass due to the additional oxygen atom, resulting in a higher total molar mass than water.
09

Counting Atoms in a Mole

In statement (i), 1 mole of ibuprofen contains 13 moles of carbon, 18 moles of hydrogen, and 2 moles of oxygen, totaling 33 moles of atoms. Therefore, this statement is true.
10

Converting Moles to Mass

To convert moles to grams, multiply by the molar mass, not Avogadro's number. Therefore, statement (j) is false.
11

Converting Mass to Moles

To convert grams to moles, divide by the molar mass, as correctly stated in (k). Therefore, statement (k) is true.
12

Chemical Composition of Water

Statement (l) is false because 1 mole of \(\text{H}_2\text{O}\) contains 2 moles of hydrogen atoms (not 1) and 1 mole of oxygen atoms.
13

Massing Elements in Water

For statement (m), 1 mol of \(\text{H}_2\text{O}\) actually contains 2 grams of hydrogen (from the two hydrogen atoms) and 16 grams of oxygen, so this is false.
14

Counting Atoms in Water

In statement (n), 1 mole of water contains \(6.022\times 10^{23}\) molecules, which is \(18.066\times 10^{23}\) atoms (with 3 atoms per molecule), making this true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Avogadro's number
Avogadro's number is a fundamental concept in chemistry, representing the quantity of atoms, molecules, or other entities in one mole of a substance. Just like a dozen refers to 12 items, one mole refers to approximately \(6.022 \times 10^{23}\) entities. This large number arises from the tiny scale of atoms. Even a tiny amount of a substance like a gram of hydrogen contains billions of atoms.
Understanding Avogadro's number is crucial, as it allows chemists to count these minuscule entities in practical, large-scale amounts.
  • It defines the mole as a counting unit in chemistry, originating from Avogadro's hypothesis that equal volumes of gases at the same temperature and pressure contain an equal number of molecules.
  • While Avogadro's number is often rounded to \(6.02 \times 10^{23}\) for simplicity, it provides a solid basis for converting between microscopic entities and macroscopic quantities useful in laboratory settings.
Molar mass calculations
Molar mass is the mass of one mole of a substance expressed in grams per mole (g/mol). This concept is vital for translating between masses in an experiment and the number of moles involved in chemical reactions.
To determine the molar mass of a compound, you sum the atomic masses of its elements, each weighted by the number of times the element appears in the compound. For example, the molar mass of water \( ext{H}_2 ext{O}\) is calculated as:
\[2 \times (1 \, ext{g/mol for H}) + 16 \, ext{g/mol for O} = 18 \, ext{g/mol}\]
  • When converting from moles to grams, multiply the number of moles by the molar mass.
  • When converting from grams to moles, divide the mass of the substance by its molar mass.
  • Consistent use of the correct molar masses is essential in calculations for stoichiometry and balancing chemical equations.
Chemical composition of compounds
Understanding the chemical composition of compounds allows chemists to predict how they will react. Compounds are made of atoms from different elements, bonded together in specific ratios, which are represented by their chemical formulas.
For example, in the compound water (\( ext{H}_2 ext{O}\)), each molecule consists of two hydrogen atoms and one oxygen atom. This ratio directly affects the compound's properties and how it interacts chemically.
  • The chemical formula gives insight into the compound's molar mass, as explained in the molar mass calculations.
  • One mole of any compound will have Avogadro's number of molecules, allowing easy conversion between the number of molecules and the mass of the sample.
  • Understanding chemical compositions is critical for predicting the outcome of reactions, especially in determining how much of each reactant is needed and the amounts of products formed.

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Most popular questions from this chapter

When gaseous dinitrogen pentoxide, \(\mathrm{N}_{2} \mathrm{O}_{5}\), is bubbled into water, nitric acid, \(\mathrm{HNO}_{3}\), forms. Write a balanced equation for this reaction.

Answer true or false. (a) Stoichiometry is the study of mass relationships in chemical reactions. (b) To determine mass relationships in a chemical reaction, you first need to know the balanced chemical equation for the reaction. (c) To convert from grams to moles and vice versa, use Avogadro's number as a conversion factor. (d) To convert from grams to moles and vice versa, use molar mass as a conversion factor. (e) A limiting reagent is the reagent that is used up first. (f) Suppose a chemical reaction between A and B requires 1 mol of \(A\) and 2 mol of \(B\). If 1 mol of each is present, then \(\mathrm{B}\) is the limiting reagent. (g) Theoretical yield is the yield of product that should be obtained according to the balanced chemical equation. (h) Theoretical yield is the yield of product that should be obtained if all limiting reagent is converted to product. (i) Percent yield is the number of grams of product divided by the number of grams of the limiting reagent times 100 (j) To calculate percent yield, divide the mass of product formed by the theoretical yield and multiply by 100

In the equation \(2 \mathrm{Na}^{+}(\mathrm{aq})+\mathrm{CO}_{3}^{2-(\mathrm{aq})+\mathrm{Sr}^{2+}(\mathrm{aq})+2 \mathrm{Cl}^{-}(\mathrm{aq}) \longrightarrow}\) \(\mathrm{SrCO}_{3}(\mathrm{s})+2 \mathrm{Na}^{+}(\mathrm{aq})+2 \mathrm{Cl}^{-}(\mathrm{aq})\) (a) Identify the spectator ions. (b) Write the balanced net ionic equation.

In the industrial chemical preparation of chlorine, \(\mathrm{Cl}_{2}\) electric current is passed through an aqueous solution of sodium chloride to give \(\mathrm{Cl}_{2}(\mathrm{g})\) and \(\mathrm{H}_{2}(\mathrm{g})\). The other product of this reaction is sodium hydroxide. Write a balanced equation for this reaction.

Furan, an organic compound used in the synthesis of nylon and referenced in Section \(19.2,\) has the molecular formula \(\mathrm{C}_{4} \mathrm{H}_{4} \mathrm{O}\) (a) Determine the number of moles of furan in a \(441 \mathrm{mg}\) sample (b) If the density of furan is known to be \(0.936 \mathrm{g} / \mathrm{mL}\), how many carbon atoms are present in \(0.060 \mathrm{L}\) of furan? (c) Calculate the mass in grams of \(9.86 \times 10^{25}\) molecules of furan.

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