Chapter 21: Problem 18
Draw the structure of valine at \(\mathrm{pH} 1\) and at pH 12
Short Answer
Expert verified
At pH 1, valine has an
\(\text{-NH}_3^+\) group and a
\(\text{-COOH}\) group. At pH 12, it has an
\(\text{-NH}_2\) group and a
\(\text{-COO}^-\) group.
Step by step solution
01
Understanding Valine Structure
Valine is an amino acid with the chemical formula C5H11NO2. It contains a central \(\alpha\)-carbon bonded to a carboxyl group (-COOH), an amino group (-NH2), a hydrogen atom, and an isopropyl side chain (-(CH3)2CH). Before we consider the pH, we visualize valine with a neutral charge.
02
Structure of Valine at pH 1
At \(\mathrm{pH} 1\), the environment is very acidic, leading to protonation of groups. The amino group (-NH2) becomes \(\text{-NH}_3^+\), and the carboxyl group remains in its unionized form (-COOH) because it will not deprotonate in such an acidic environment. Therefore, valine at pH 1 looks like this: ! Valine at pH 1 Structure Description !
03
Structure of Valine at pH 12
At \(\mathrm{pH} 12\), the environment is very basic, which results in the deprotonation of groups. The carboxyl group (-COOH) loses a proton to become \(\text{-COO}^-\), while the amino group remains as (-NH2) due to the high \(\text{p}K_a\) of the ammonium ion. Hence, at pH 12, valine takes the following form: ! Valine at pH 12 Structure Description !
04
Drawing Valine Structures
To visualize both structures:- **Valine at pH 1:** Draw the amino group as \(\text{-NH}_3^+\), the carboxyl group as \(\text{-COOH}\) and the isopropyl group remains unchanged.- **Valine at pH 12:** Draw the amino group as \(\text{-NH}_2\), the carboxyl group as \(\text{-COO}^-\), and the isopropyl group unchanged.These are representative structures based on their environment.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Amino Acid
Amino acids are the building blocks of proteins. Each amino acid has a basic structure consisting of:
Valine has the chemical formula \(\text{C}_5\text{H}_{11}\text{NO}_2\). As an amino acid, valine plays a pivotal role in protein synthesis and various metabolic pathways. Its structure dictates how it behaves under different conditions, such as changes in pH.
- An amino group (-NH2)
- A carboxyl group (-COOH)
- An alpha (\(\alpha\)) carbon
- A unique side chain, called the R group
Valine has the chemical formula \(\text{C}_5\text{H}_{11}\text{NO}_2\). As an amino acid, valine plays a pivotal role in protein synthesis and various metabolic pathways. Its structure dictates how it behaves under different conditions, such as changes in pH.
pH Effects
The pH level of a solution has significant effects on amino acids and their ionization states. pH is a scale that measures the acidity or basicity of a solution:
- A pH less than 7 indicates an acidic environment.
- A pH of exactly 7 is neutral.
- A pH greater than 7 indicates a basic or alkaline environment.
- In acidic conditions (low pH), amino acids tend to gain protons.
- In basic conditions (high pH), they tend to lose protons.
Protonation
Protonation refers to the addition of a proton (H+) to an atom, molecule, or ion. In the context of amino acids, protonation affects the functional groups:
- The amino group (-NH2) becomes protonated to form \(\text{-NH}_3^+\).
- The carboxyl group (-COOH) remains unchanged in highly acidic solutions.
- The amino group accepts an additional proton, resulting in its protonated form \(\text{-NH}_3^+\).
- The carboxyl group does not undergo deprotonation under these conditions and stays as \(\text{-COOH}\).
Deprotonation
Deprotonation is the opposite of protonation. It involves the removal of a proton (H+) from an atom, molecule, or ion. In amino acids, the carboxyl group is primarily affected:
- The carboxyl group (-COOH) deprotonates to form \(\text{-COO}^-\).
- The amino group may remain unchanged in basic environments if its \(\text{p}K_a\) is high.
- The carboxyl group loses a proton, resulting in the deprotonated form \(\text{-COO}^-\).
- The amino group remains in its neutral form as \(\text{-NH}_2\).