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Write equations for the reaction of 2 -butanol with these reagents. (a) \(\mathrm{H}_{2} \mathrm{SO}_{4},\) heat (b) \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}, \mathrm{H}_{2} \mathrm{SO}_{4}\)

Short Answer

Expert verified
(a) 2-butanol → 2-butene + Water; (b) 2-butanol + oxidizing agent → 2-butanone.

Step by step solution

01

Understand the Reaction with H2SO4 and Heat

When 2-butanol is heated with concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\)\, it undergoes a dehydration reaction. This typically results in the formation of alkenes through the removal of water.
02

Write the Equation for Dehydration

Dehydration of 2-butanol involves the removal of an \(-\mathrm{OH}\) group and a hydrogen from an adjacent carbon, forming an alkene. The main product is 2-butene. Thus, the reaction is:\[\text{2-butanol} \rightarrow \text{2-butene} + \text{Water}.\]
03

Understand the Reaction with K2Cr2O7 and H2SO4

When 2-butanol reacts with \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) and \(\mathrm{H}_{2} \mathrm{SO}_{4}\), it undergoes oxidation. This reaction typically converts a secondary alcohol into a ketone.
04

Write the Equation for Oxidation

Oxidation of 2-butanol forms 2-butanone. This occurs by converting the alcohol group into a carbonyl group. The reaction is:\[\text{2-butanol} + \text{oxidizing agent} \rightarrow \text{2-butanone}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dehydration Reaction
Dehydration reactions are chemical processes where a molecule of water is removed from a compound. When dealing with alcohols like 2-butanol, the dehydration process often involves the use of an acid as a catalyst, commonly sulfuric acid (\(\mathrm{H_2SO_4}\)).
This reaction results in the formation of an alkene from the alcohol by removing a water molecule. In the case of 2-butanol, heating it with concentrated sulfuric acid facilitates the removal of an \(\text{-OH}\) group from one carbon and a hydrogen atom from an adjacent carbon atom. This removal results in the formation of 2-butene, a common alkene.
- **Summary of the process**: - The alcohol loses its hydroxyl group. - An adjoining carbon atom loses a hydrogen. - These two atoms form a molecule of water that gets released. - A double bond (alkene) forms between the two carbon atoms.
Dehydration reactions are essential in organic chemistry as they help form important compounds like alkenes, which are building blocks for more complex molecules.
Oxidation Reaction
Oxidation reactions involve the gain of oxygen or the loss of hydrogen in a molecule. When it comes to 2-butanol, an oxidation reaction transforms this secondary alcohol into a ketone by changing the alcohol group (\(\text{-OH}\)) into a carbonyl group (\(\text{=O}\)).
This is achieved using an oxidizing agent such as potassium dichromate (\(\mathrm{K_{2}Cr_{2}O_{7}}\)) in acidic conditions, provided by sulfuric acid (\(\mathrm{H_2SO_4}\)).
In this reaction:- **How it works**: - The secondary alcohol in 2-butanol undergoes oxidation. - The oxidizing agent facilitates the transformation of the alcohol group into a carbonyl group. - The end product of the reaction is 2-butanone, a ketone.
Understanding oxidation reactions, especially in organic chemistry, is key as they lead to significant transformations in organic molecules, creating functional groups such as ketones which are pivotal in numerous chemical reactions.
2-butanol
2-butanol is a type of secondary alcohol, meaning that the hydroxyl group (\(\text{-OH}\)) is connected to a secondary carbon atom — a carbon atom bonded to two other carbon atoms. This structure makes 2-butanol a versatile compound in chemical reactions, particularly dehydration and oxidation reactions.

**Characteristics of 2-butanol**:- It's represented by the molecular formula \(\mathrm{C_4H_{10}O}\).- As a secondary alcohol, it can be easily dehydrated to form an alkene or oxidized to yield a ketone.
These properties make 2-butanol an important molecule in organic synthesis.

In laboratory and industrial settings, 2-butanol is often used:- **For Dehydration**: Heating with acids like sulfuric acid easily converts 2-butanol into 2-butene through loss of water.- **For Oxidation**: Reacting it with oxidizing agents like potassium dichromate transforms it into 2-butanone.
Understanding the nature and behavior of 2-butanol helps chemists effectively manipulate it in creating a wide array of organic compounds.

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Most popular questions from this chapter

Answer true or false. (a) Ethanol and dimethyl ether are constitutional isomers. (b) The solubility of low-molecular-weight ethers in water is comparable to that of low-molecularweight alcohols in water (c) Ethers undergo many of the same reactions that alcohols do.

Knowing what you do about electronegativity, the polarity of covalent bonds, and hydrogen bonding, would you expect an \(\mathrm{N}-\mathrm{H}-\mathrm{N}\) hydrogen bond to be stronger than, the same strength as, or weaker than an O-H- -O hydrogen bond?

Arrange these compounds in order of increasing boiling point. Use the boiling point values of \(-42^{\circ} \mathrm{C}, 78^{\circ} \mathrm{C}\) \(138^{\circ} \mathrm{C},\) and \(198^{\circ} \mathrm{C}\) (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) \((\mathrm{c}) \quad \mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) \((\mathrm{d}) \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3}\)

Answer true or false. (a) Today, the major carbon sources for the synthesis of methanol are coal and methane (natural gas), both nonrenewable resources. (b) Today the major carbon sources for the synthesis of ethanol are petroleum and natural gas, both nonrenewable resources. (c) Intermolecular acid-catalyzed dehydration of ethanol gives diethyl ether. (d) Conversion of ethylene to ethylene glycol involves oxidation to ethylene oxide, followed by acidcatalyzed hydration (addition of water) to ethylene oxide. (e) Ethylene glycol is soluble in water in all proportions. (f) A major use of ethylene glycol is as automobile antifreeze.

(Chemical Connections \(13 \mathrm{C}\) ) What does it mean to say that ethylene oxide is a highly strained molecule?

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