/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 55 Account for the fact that the si... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Account for the fact that the six-membered ring in benzene is planar but the six-membered ring in cyclohexane is not.

Short Answer

Expert verified
Benzene is planar due to sp2 hybridization and aromatic stability, while cyclohexane's sp3 hybridization leads to non-planar conformations.

Step by step solution

01

Understanding Planarity in Benzene

Benzene, a six-membered ring, is planar because it involves sp2 hybridized carbon atoms. Each carbon in benzene has three sigma bonds and one delocalized pi bond, forming a continuous overlap that creates a stable, planar aromatic system. The planar structure allows for maximum overlap of the delocalized pi electrons above and below the ring.
02

Examining Hybridization in Benzene

The carbons in benzene are sp2 hybridized, which means they form three sigma bonds: two with neighboring carbons and one with a hydrogen atom, leaving one unhybridized p orbital. These p orbitals from each carbon overlap to form a pi bond, resulting in resonance that stabilizes the planar structure.
03

Understanding Cyclohexane Conformation

Cyclohexane, although it has a six-membered ring, is not planar because it minimizes torsional strain by adopting non-planar conformations. The most stable conformations are the chair and boat forms, with the chair being the lowest energy conformation. This 3D conformation avoids eclipsing interactions.
04

Comparing Hybridization in Cyclohexane

The carbons in cyclohexane are sp3 hybridized, resulting in tetrahedral geometry that promotes different angles than those in a planar structure. Each carbon bonds with two other carbons and two hydrogens, allowing for staggered conformations that reduce strain but necessitate a non-planar structure.
05

Summarizing Planarity Differences

The planarity of benzene is due to its aromatic nature and continuous pi-bonding system from sp2 hybridization. In contrast, cyclohexane's sp3 hybridization and need to reduce torsional strain result in non-planar chair or boat conformations. These structural differences explain the deviation in planarity between the two compounds.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Benzene: The Planar Aromatic Ring
Benzene is a fascinating molecule in organic chemistry known for its planar, symmetrical structure. It consists of six carbon atoms arranged in a hexagonal ring, each carbon atom forming bonds through sp2 hybridization. This type of hybridization allows each carbon to create three sigma bonds. Two of these bonds connect to adjacent carbon atoms, while the third attaches to a hydrogen atom. The remaining electrons form a pi system by delocalizing in overlapping p orbitals. This delocalization above and below the plane of the carbon atoms imparts exceptional stability to benzene, known as aromatic stability. The planar nature of benzene is crucial because it maximizes this overlapping, facilitating strong pi bonding. Thus, benzene is uniquely stable and rigidly planar, unlike many other organic molecules.
Cyclohexane: Non-Planar Comfort in Chair Form
Cyclohexane presents a stark contrast to benzene; it does not adopt a planar structure. This molecule, also a six-membered ring like benzene, adopts a non-planar conformation to minimize torsional strain. The most energetically favorable conformation for cyclohexane is the chair form. This conformation enables all carbon-carbon bonds to be staggered rather than eclipsed, reducing strain significantly. Cyclohexane's carbons are sp3 hybridized, meaning each carbon forms four sigma bonds in a tetrahedral arrangement, leading to the classic chair shape. Key reasons for cyclohexane's non-planarity include the minimization of steric hindrance and maximization of distance between hydrogen atoms. While cyclohexane can warp into different shapes like the boat form, the chair conformation remains the most stable and preferred geometric orientation.
Molecular Hybridization: Foundation of Geometry
Molecular hybridization is essential in determining the three-dimensional structure of organic molecules. In benzene, sp2 hybridization means each carbon has three sp2 hybrid orbitals and one unhybridized p orbital. The sp2 orbitals form sigma bonds with adjacent atoms, while the p orbitals overlap to create the delocalized pi electron cloud, contributing to the molecule's aromatic characteristics and planar structure. On the other hand, cyclohexane displays sp3 hybridization, resulting in four equivalent hybrid orbitals arranged tetrahedrally. This geometry leads to non-planar conformations that effectively reduce molecular strain. Understanding hybridization is crucial as it influences molecular geometry, bond angles, and the overall stability of chemical structures. Thus, it reveals why benzene is planar while cyclohexane is not.
Aromaticity: A Unique Kind of Stability
Aromaticity is an important concept in organic chemistry, especially when it comes to understanding the planar structure of benzene. Aromatic compounds have a cyclic, planar structure with a ring of resonance-stabilized pi bonds. The defining feature of an aromatic molecule is its ability to sustain the circulation of pi electrons across a loop of overlapping p orbitals. This phenomenon is embodied in benzene due to its six-membered ring and delocalized pi system, obeying Hückel's rule of 4n + 2 pi electrons, where n is an integer. Aromaticity grants benzene a unique level of chemical stability, making it less reactive than typical alkenes. This special stability explains why aromatic compounds like benzene remain planar. It ensures maximal overlap of pi orbitals, maintaining a continuous electron cloud, in contrast to non-aromatic, three-dimensional molecules such as cyclohexane.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Answer true or false. (a) Alkenes, alkynes, and arenes are unsaturated hydrocarbons. (b) Aromatic compounds were so named because many of them have pleasant odors. (c) According to the resonance model of bonding, benzene is best described as a hybrid of two equivalent contributing structures. (d) Benzene is a planar molecule.

Propose a structural formula for the product(s) when each of the following alkenes is treated with \(\mathrm{H}_{2} \mathrm{O} / \mathrm{H}_{2} \mathrm{SO}_{4} .\) Why are two products formed in part (b), but only one in parts (a) and (c)? (a) \(1-\) Hexene gives one alcohol with a molecular formula of \(\mathrm{C}_{6} \mathrm{H}_{14} \mathrm{O}\) (b) 2 -Hexene gives two alcohols, each with a molecular formula of \(\mathrm{C}_{6} \mathrm{H}_{14} \mathrm{O}\) (c) 3 -Hexene gives one alcohol with a molecular formula of \(\mathrm{C}_{6} \mathrm{H}_{14} \mathrm{O}\)

(Chemical Connections 12 B) In recycling codes, what do these abbreviations stand for? (a) \(\mathrm{V}\) (b) \(\mathrm{PP}\) (c) PS

Answer true or false. (a) Complete combustion of an alkene gives carbon dioxide and water. (b) Addition reactions of alkenes involve breaking one of the bonds of the carbon-carbon double bond and formation of two new single bonds in its place. (c) Markovnikov's rule refers to the regioselectivity of addition reactions of carbon-carbon double bonds. (d) According to Markovnikov's rule, in the addition of \(\mathrm{HCl}\), \(\mathrm{HBr}\), or \(\mathrm{HI}\) to an alkene, hydrogen adds to the carbon of the double bond that already has the greater number of hydrogen atoms bonded to it and the halogen adds to the carbon that has the lesser number of hydrogens bonded to it. (e) A carbocation is a carbon atom with four bonds that bears a positive charge. (f) The carbocation derived from ethylene is \(\mathrm{CH}_{3} \mathrm{CH}_{2}^{+}\) (g) The reaction mechanism for the addition of a halogen acid (HX) to an alkene is divided into two steps, (1) formation of a carbocation and (2) reaction of the carbocation with halide ion, which complete the reaction. (h) Acid-catalyzed addition of \(\mathrm{H}_{2} \mathrm{O}\) to an alkene is called hydration. (i) If a compound fails to react with \(\mathrm{Br}_{2}\), it is unlikely that the compound contains a carbon-carbon double bond. (j) Addition of \(\mathrm{H}_{2}\) to a double bond is a reduction reaction. (k) Catalytic reduction of cyclohexene gives hexane. (l) According to the mechanism presented in the text for acid-catalyzed hydration of an alkene, the H and \(-\) OH groups added to the carbon-carbon double bond both arise from the same molecule of \(\mathrm{H}_{2} \mathrm{O}\) \((\mathrm{m})\) The conversion of ethylene, \(\mathrm{CH}_{2}=\mathrm{CH}_{2},\) to ethanol \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH},\) is an oxidation reaction. (n) Acid-catalyzed hydration of 1-butene gives 1-butanol. Acid-catalyzed hydration of 2-butene gives 2 -butanol.

Three products with the molecular formula \(\mathrm{C}_{6} \mathrm{H}_{4} \mathrm{BrCl}\) form when bromobenzene is treated with chlorine, \(\mathrm{Cl}_{2}\) in the presence of \(\mathrm{FeCl}_{3}\) as a catalyst. Name and draw a structural formula for each product.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.