Chapter 14: Problem 85
Why does brass cause your skin to turn green?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 14: Problem 85
Why does brass cause your skin to turn green?
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
The following table gives the results of reactions between five metals and solutions of their nitrate salts. NR means "no reaction" and MD means "metal displaced from solution." From these results, arrange the five metals in order of decreasing chemical activity. \begin{tabular}{lccccc} \hline & \(\mathrm{Ag}(s)\) & \(\mathrm{Fe}(s)\) & \(\mathrm{Hg}(l)\) & \(\mathrm{Mn}(s)\) & \(\mathrm{Ni}(s)\) \\ \hline \(\mathrm{AgNO}_{3}(a q)\) & \(-\) & \(\mathrm{MD}\) & \(\mathrm{NR}\) & \(\mathrm{MD}\) & \(\mathrm{MD}\) \\ \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{2}(a q)\) & \(\mathrm{NR}\) & \(-\) & \(\mathrm{NR}\) & \(\mathrm{MD}\) & \(\mathrm{NR}\) \\ \(\mathrm{Hg}\left(\mathrm{NO}_{3}\right)_{2}(a q)\) & \(\mathrm{MD}\) & \(\mathrm{MD}\) & \(-\) & \(\mathrm{MD}\) & \(\mathrm{MD}\) \\ \(\mathrm{Mn}\left(\mathrm{NO}_{3}\right)_{2}(a q)\) & \(\mathrm{NR}\) & \(\mathrm{NR}\) & \(\mathrm{NR}\) & \(-\) & \(\mathrm{NR}\) \\ \(\mathrm{Ni}\left(\mathrm{NO}_{3}\right)_{2}(a q)\) & \(\mathrm{NR}\) & \(\mathrm{MD}\) & \(\mathrm{NR}\) & \(\mathrm{MD}\) & \(-\) \end{tabular}
What is an oxidation-reduction reaction?
In the following oxidation-reduction reactions, identify the oxidizing agent, the reducing agent, and the number of electrons transferred. (a) \(\mathrm{I}_{2}(a q)+2 \mathrm{OH}^{-}(a q) \longrightarrow \mathrm{I}^{-}(a q)+\mathrm{IO}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) (b) \(\mathrm{Cr}(s)+2 \mathrm{H}^{+}(a q) \longrightarrow \mathrm{Cr}^{2+}(a q)+\mathrm{H}_{2}(g)\) (c) \(2 \mathrm{Cr}_{2} \mathrm{O}_{7}{ }^{2}(a q)+16 \mathrm{H}^{+}(a q) \longrightarrow\) \(4 \mathrm{Cr}^{3+}(a q)+3 \mathrm{O}_{2}(g)+8 \mathrm{H}_{2} \mathrm{O}(l)\) (d) \(3 \mathrm{Fe}^{3+}(a q)+\mathrm{Al}(s) \longrightarrow 3 \mathrm{Fe}^{2 *}(a q)+\mathrm{Al}^{34}(a q)\)
The reaction that occurs in a common dry cell battery is as follows: $$ \begin{aligned} \mathrm{Zn}(s)+2 \mathrm{MnO}_{2}(s)+2 \mathrm{NH}_{4}^{+}(a q) & \longrightarrow \\ \mathrm{Zn}^{2 *}(a q) &+\mathrm{Mn}_{2} \mathrm{O}_{3}(s)+2 \mathrm{NH}_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \end{aligned} $$ What gets oxidized in this battery? What gets reduced? What is the oxidizing agent? What is the reducing agent?
The reaction that occurs in gas grills involves the burning of propane: $$ \mathrm{C}_{3} \mathrm{H}_{\mathrm{s}}(g)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g) $$ Assign oxidation numbers to all of the reactants and identify the oxidizing and reducing agents.
What do you think about this solution?
We value your feedback to improve our textbook solutions.