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Which of the following halides is least stable and has doubtful existence? (a) \(\mathrm{CL}_{4}\) \(\square\) (b) \(\mathrm{SnI}_{4}\) (c) \(\mathrm{GeL}_{4}\) \(\square\) (d) \(\mathrm{Pbl}_{4}\)

Short Answer

Expert verified
(d) abla>PbI_{4} is the least stable halide with doubtful existence.

Step by step solution

01

Analyze Lead Tetraiodide Stability

Lead tetriodide ( abla>PbI_{4}) is the focus. Typically, lead prefers the oxidation state +2. When it's in the +4 state, as in abla>PbI_{4, it is unusual and energetically less favorable compared to common halides, like abla>PbI_{2}.
02

Compare with Other Halides

Evaluate the stability of other compounds. SnIâ‚„, Clâ‚„, and GeLâ‚„ are stable in their respective oxidation states (Sn and Ge prefer +4). Clâ‚„, while unusual, could form in theory but typically forms Clâ‚‚.
03

Identify the Least Stable Halide

Since Pb in abla>PbI_{4} is in an unstable +4 oxidation state and prefers +2, this compound is less common than abla>SnI_{4}, abla>GeL_{4}, and Clydro67.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation States
Understanding oxidation states is key to evaluating the stability of chemical compounds. Oxidation states represent the degree of oxidation of an atom in a compound. It indicates the number of electrons an atom gains or loses to form chemical bonds.
In our exercise, lead ( abla{Pb} abla) in lead tetraiodide ( abla{PbI}_4 abla) is highlighted for its +4 oxidation state. Typically, lead is more stable in the +2 oxidation state because it requires less energy. The transition from +2 to +4 involves losing two more electrons, an energetically unfavorable condition for lead.
Contrarily, tin ( abla{Sn} abla) and germanium ( abla{Ge} abla) more comfortably inhabit the +4 oxidation state in compounds like tin tetraiodide ( abla{SnI}_4 abla) and hypothetical compounds like abla{GeL}_4 abla. They remain stable as they do not face the same unfavorable condition as lead does when moving to a higher oxidation state.
Lead Tetraiodide
Lead tetraiodide ( abla{PbI}_4 abla) deserves special attention due to its unique aspects in the realm of halides. This compound harbors lead in an unusually high +4 oxidation state. Such a configuration is sparingly observed because lead more commonly forms compounds in the +2 state, making abla{PbI}_2 abla a more typical occurrence.
In abla{PbI}_4 abla, each iodine atom pulls on electrons from lead, maintaining the tetrahedral structure of the molecule. However, the energetic demand for lead to remain in this tetra-state causes it to be energetically less favorable. If energy conditions change, abla{PbI}_4 abla could decompose, reverting lead to its preferred +2 state.
When we compare it to stable halides like abla{SnI}_4 abla and other similar compounds, lead tetraiodide stands out primarily because it disrupts lead's typical chemical behavior. This makes its existence less common and even doubtful in typical conditions.
Chemical Stability
Chemical stability involves a compound's ability to maintain its structure without undergoing chemical change. Stability is often dictated by the energy balance within the compound's molecular structure.
In the context of halides discussed in the exercise, abla{PbI}_4 abla is noteworthy due to its observed instability. Since lead prefers a lower energy +2 oxidation state, its tendency to revert to this state makes abla{PbI}_4 abla less stable. This highlights a key aspect of chemical stability: the alignment of a compound's oxidation state with the element's preference.
Chemically stable compounds like abla{SnI}_4 abla and theoretical abla{GeL}_4 abla maintain their structural integrity because their atomic constituents in +4 oxidation states do not necessitate a shift to a different state to achieve a lower energy configuration. These insights make it clear why lead tetraiodide presents as a textbook example of least stability, driven by the core principles of oxidation tendencies and energetic alignments.

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