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Mixture of \((X)=0.02\) mole of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{SO}_{4}\right] \mathrm{Br}\) and \(0.02\) mole of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Br}\right] \mathrm{SO}_{4}\) was prepared in 2 litre of solution; Hitre of mixture \([X]+\mathrm{excess} \mathrm{AgNO}_{3} \longrightarrow[Y]\) litre of mixture \([X]+\) excess \(\mathrm{BaCl}_{2} \longrightarrow[Z]\) No. of moles of \([Y]\) and \([Z]\) are: \(\quad\) [I.I.T. (S) 2003] (a) \(0.01,0.01\) \(\square\) (b) \(0.02,0.01\) - (c) \(0.01,0.02\) \(\square\) (d) \(0.02,0.02\) \(\square\)

Short Answer

Expert verified
The number of moles of [Y] and [Z] are 0.02 and 0.02, respectively. Hence, the correct answer is (d).

Step by step solution

01

Reaction with AgNO3

Let's begin by treating the mixture with excess AgNO_3 . When AgNO3 reacts with Co(NH3)_{5}SO_{4}Br , only the bromide ion (Br^-) will precipitate as AgBr . The only source of Br^- ion in the mixture is from the [Co(NH3)_5SO_4]Br complex. As there are 0.02 moles of this complex, 0.02 moles of AgBr will be formed.
02

Reaction with BaCl2

Now, consider the reaction of the mixture with excess BaCl2 . The Ba^2+ reacts with SO_4^2- ions to form BaSO_4 precipitate. Both complexes provide SO_4^2- ions, each contributing 0.01 mole (since each complex is 0.02 moles in a 2-litre solution and only one SO_4^2- per complex is available). Thus, in total, 0.01 (from [Co(NH3)_5SO_4]Br ) + 0.01 (from [Co(NH3)_5Br]SO_4 ) = 0.02 moles of BaSO_4 are produced.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Precipitation Reactions
Precipitation reactions occur when two soluble salts in a solution react to form one or more insoluble products, called precipitates. This is a common phenomenon in coordination chemistry, where the reactions often involve complex ions. In our exercise, we see an example involving silver nitrate (AgNO鈧) and barium chloride (BaCl鈧) applied to coordination compounds.

When silver nitrate is added to the mixture, it specifically reacts with the bromide ions (Br鈦) to form silver bromide (AgBr), a white precipitate. The reaction proceeds as follows:
  • AgNO鈧 + Br鈦 鈫 AgBr 鈫 + NO鈧冣伝
In the context of this example, only the complex \([Co(NH鈧)_5SO_4]Br\) contributes bromide ions, leading to the formation of 0.02 moles of AgBr.

When barium chloride is added, it reacts with the sulfate ions (SO鈧劼测伝) to form barium sulfate (BaSO鈧), another precipitate:
  • BaCl鈧 + SO鈧劼测伝 鈫 BaSO鈧 鈫 + 2Cl鈦
Each complex in the mixture provides sulfate ions, resulting in a total of 0.02 moles of BaSO鈧 being produced.
Stoichiometry in Coordination Chemistry
Stoichiometry in coordination chemistry involves the calculation of quantities of reactants and products in reactions involving complex ions. Coordination compounds often contain a central metal ion bonded to surrounding ligands, making their stoichiometry considerations more intricate compared to simple ionic compounds.

In our problem, stoichiometry helps us calculate the amounts of precipitate. Let's examine each component:
  • The mixture contains 0.02 moles of \([Co(NH鈧)_5SO_4]Br\) and 0.02 moles of \([Co(NH鈧)_5Br]SO鈧刓) in a 2-liter solution, meaning we work with stoichiometric coefficients related to these components.
  • The reaction with AgNO鈧 identifies bromide ions, all originating from the first complex, showing a direct 1:1 mole relationship in forming AgBr.
  • In the BaCl鈧 reaction with sulfate ions, each complex releases sulfate into the solution. Here, the stoichiometry must consider two sources, adding together to predict the total BaSO鈧 formed.
Utilizing stoichiometric principles allows the accurate computation of 0.02 moles of AgBr and 0.02 moles of BaSO鈧, reinforcing the predictability in coordination chemistry reactions.
Complex Ions
Complex ions consist of a central metal ion surrounded by molecules or anions known as ligands. These structures, typical in coordination compounds, play a crucial role in the reactivity and properties of the resultant complexes.

Consider the example from our problem, where both \([Co(NH鈧)_5SO_4]Br\) and \([Co(NH鈧)_5Br]SO鈧刓) feature cobalt at their center. The ligands, such as \(NH鈧僜), are neutral molecules, and anions like \(SO_4^{2-}\) and \(Br^-\) confer overall charge and stability to these complexes.

The key to understanding complex ions lies in their formation and interaction with external reagents. For instance:
  • The ligand's ability to donate electron pairs to the metal centers defines the complex ion's stability.
  • The composition influences the ion's chemical behavior, determining which ions (bromide or sulfate) can be released during precipitation reactions.
In coordination chemistry, complex ions must be carefully analyzed to predict outcomes and reactions, as seen in the precipitation of AgBr and BaSO鈧 from our mixtures.

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Most popular questions from this chapter

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