Chapter 15: Problem 120
Hybridisation, shape and magnetic moment of \(\mathrm{K}_{3}\left[\mathrm{Co}\left(\mathrm{CO}_{3}\right)_{3}\right]\) is : |J.E.E. (Orissa) 2008] (a) \(d^{2} s p^{3}\), octahedral, \(4.9\) B.M. (b) \(s p^{3} d^{2}\), octahedral, \(4.9 \mathrm{~B} \cdot \mathrm{M}\) (c) \(d s p^{2}\), square planar, \(4.9\) B.M. (d) \(s p^{3}\), tetrahedral, 4.9 B.M.
Short Answer
Step by step solution
Determine Oxidation State of Cobalt
Identify the Hybridisation
Determine the Geometry
Calculate the Magnetic Moment
Match with Given Options
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxidation State
- Potassium (K) is known to have a standard oxidation state of +1. Since there are three potassium ions in the formula, they contribute a total of +3.
- The complex must be neutral, so the overall charge on the cobalt-carbonate complex must balance this. Thus, \([\mathrm{Co(CO}_{3})_{3}]^{3-}\).
- Here, the carbonate ligand is known to have a charge of -2. Three such ligands contribute -6.
- Therefore, the oxidation state of cobalt (Co) must be +3 to balance the 3- charge from three carbonate ions.
Octahedral Geometry
- The coordination number, which is the number of ligand donor atoms directly attached to the central atom, is 6.
- The hybridisation, derived from the process of mixing atomic orbitals, results in a \(d^{2}sp^{3}\) arrangement for cobalt in its +3 oxidation state.
- Each orbital in \(d^{2}sp^{3}\) hybridisation forms a bond with a ligand, effectively creating an octahedral shape.
Magnetic Moment
- It contains 4 unpaired electrons.
- Using the formula, \[ \mu = \sqrt{4(4+2)} = 4.9 \text{ B.M.} \]
Transition Metal Complexes
- These complexes exhibit a wide range of oxidation states, enabling them to participate in a variety of chemical reactions.
- When ligands coordinate with metal atoms, they can significantly affect the metal’s electronic structure and, consequently, the compound's physical and chemical properties.
- The concept of hybridisation in these complexes—where atomic orbitals mix to form new orbitals suitable for bonding—leads to different geometries, such as octahedral or tetrahedral.