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Amongst the following, the lowest degree of paramagnetism per mole of the compound will be shown by: (a) \(\mathrm{MnSO}_{4} \cdot 4 \mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{FeSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\) (d) \(\mathrm{NiSO}_{4} \cdot 6 \mathrm{H}_{2} \mathrm{O}\)

Short Answer

Expert verified
CuSO4 路 5H2O has the lowest paramagnetism.

Step by step solution

01

Understand Paramagnetism

Paramagnetism arises due to the presence of unpaired electrons in a compound. The greater the number of unpaired electrons, the higher the paramagnetism. Therefore, the compound with the least number of unpaired electrons will show the lowest degree of paramagnetism.
02

Determine Electron Configuration

We need to find the unpaired electrons for each cation in the given compounds:- **MnSO4 路 4H2O:** Mn is in a +2 oxidation state, corresponding to the electron configuration \([Ar] 3d^5\). Mn has 5 unpaired electrons.- **CuSO4 路 5H2O:** Cu is in a +2 oxidation state, corresponding to the electron configuration \([Ar] 3d^9\). Cu has 1 unpaired electron.- **FeSO4 路 7H2O:** Fe is in a +2 oxidation state, corresponding to the electron configuration \([Ar] 3d^6\). Fe has 4 unpaired electrons.- **NiSO4 路 6H2O:** Ni is in a +2 oxidation state, corresponding to the electron configuration \([Ar] 3d^8\). Ni has 2 unpaired electrons.
03

Analyze and Compare

By comparing the number of unpaired electrons:- Mn: 5 unpaired electrons- Cu: 1 unpaired electron- Fe: 4 unpaired electrons- Ni: 2 unpaired electronsCopper sulfate (\(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\)) has the fewest unpaired electrons, hence, it will exhibit the lowest degree of paramagnetism.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unpaired Electrons
In the world of chemistry, unpaired electrons are a key factor that influences a compound鈥檚 magnetic properties. Simply put, unpaired electrons are electrons that are not paired with another electron in an atom or molecule's orbital. Atoms with one or more unpaired electrons are typically paramagnetic, meaning they are attracted to magnetic fields. This is because unpaired electrons have magnetic moments (like tiny magnets), and their spin can align with external magnetic fields.

In compounds such as sulfates of transition metals, the number of unpaired electrons determines their paramagnetic behavior. For example, as shown in the exercise, manganese (Mn) in MnSO鈧 路 4H鈧侽 has 5 unpaired electrons, while copper (Cu) in CuSO鈧 路 5H鈧侽 has only 1 unpaired electron.
  • More unpaired electrons result in stronger paramagnetism.
  • Fewer unpaired electrons result in weaker paramagnetism.
Understanding unpaired electrons gives insight into why certain materials are attracted to magnets and others aren't.
Electron Configuration
Understanding electron configuration is essential for grasping why substances exhibit different degrees of paramagnetism. Electron configuration refers to the distribution of electrons in an atom's or ion's orbitals, following specific principles like the Aufbau principle, Hund鈥檚 Rule, and the Pauli Exclusion Principle.

These rules help predict which orbitals will be filled with electrons in a particular atom. The electron configurations provided in the exercise correspond to the metal ions in a +2 oxidation state:
  • For Mn虏鈦, it is \[Ar\] 3d鈦 with 5 unpaired electrons.
  • For Cu虏鈦, it is \[Ar\] 3d鈦 with 1 unpaired electron.
  • For Fe虏鈦, it is \[Ar\] 3d鈦 with 4 unpaired electrons.
  • For Ni虏鈦, it is \[Ar\] 3d鈦 with 2 unpaired electrons.
These configurations tell us about the number of unpaired electrons, which directly impacts paramagnetic properties. The fewer the unpaired electrons, the less magnetic the compound is likely to be. Thus, electron configurations form a fundamental part of understanding the chemistry of paramagnetism.
Oxidation State
The oxidation state, also known as oxidation number, is a concept in chemistry that tells us the degree of oxidation or loss of electrons in an atom. This is crucial when determining the electron configuration of ions involving transition metals, which typically exhibit varying oxidation states.

In the exercise, oxidation states help determine the electronic arrangement of the transition metal ions: all are in a +2 state. This state helps us identify the number of electrons removed, and allows for a systematic approach to write their electron configuration.
  • Manganese begins as Mn with configuration \[Ar\] 4s虏 3d鈦, and as Mn虏鈦 becomes \[Ar\] 3d鈦.
  • Copper is \[Ar\] 4s虏 3d鹿鈦, but Cu虏鈦 configuration becomes \[Ar\] 3d鈦.
  • Iron is \[Ar\] 4s虏 3d鈦, whereas Fe虏鈦 is \[Ar\] 3d鈦.
  • Nickel is \[Ar\] 4s虏 3d鈦, and as Ni虏鈦 becomes \[Ar\] 3d鈦.
By understanding oxidation states, one can determine how many electrons are lost or gained, leading to the appropriate configuration that furthers the understanding of a compound's magnetic properties.

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