Chapter 4: Problem 6
The value of \(K_{b}\), for pyridine, \(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{~N}\), is \(1.8 \times 10^{-9} .\) Calculate \(K_{\mathrm{a}}\) (in water) for the conjugate acid, \(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{NH}^{+}\).
Short Answer
Expert verified
The value of \(K_a\) for \(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{NH}^+\) is \(5.56 \times 10^{-6}.\)
Step by step solution
01
Identify Given Information
We are given that the base dissociation constant \(K_b\) for pyridine, \(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{N}\), is \(1.8 \times 10^{-9}\).
02
Understand the Relationship Between \( K_a \) and \( K_b \)
In water, the relationship between the acid dissociation constant \(K_a\) and the base dissociation constant \(K_b\) for a conjugate acid-base pair is given by the equation: \[K_a \times K_b = K_w\] where \(K_w\) is the ion-product constant of water, commonly \(1.0 \times 10^{-14} \; \text{at 25°C}.\)
03
Rearrange the Equation to Solve for \( K_a \)
Rearrange the equation \(K_a \times K_b = K_w\) to solve for \(K_a\): \[ K_a = \frac{K_w}{K_b} \]
04
Substitute Known Values to Calculate \( K_a \)
Substitute the given values into the rearranged formula: \[ K_a = \frac{1.0 \times 10^{-14}}{1.8 \times 10^{-9}} \]
05
Perform the Calculation
Calculate \( K_a \) using a calculator: \[ K_a = \frac{1.0 \times 10^{-14}}{1.8 \times 10^{-9}} = 5.56 \times 10^{-6} \]
06
Summarize the Result
The acid dissociation constant \(K_a\) for the conjugate acid \(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{NH}^+\) is found to be \(5.56 \times 10^{-6}.\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
base dissociation constant (Kb)
The base dissociation constant, often denoted as \( K_b \), measures a base's ability to accept protons in a solution. It is an indicator of the strength of a base, with higher \( K_b \) values representing stronger bases. For example, pyridine (\( \mathrm{C}_5 \mathrm{H}_5 \mathrm{N} \)), has a \( K_b \) value of \( 1.8 \times 10^{-9} \), indicating it is a relatively weak base.
To calculate \( K_b \), you measure the concentration of the hydroxide ions produced when a base dissociates in water. The equation for a generic base, \( \mathrm{B} \triangleq \mathrm{B} + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{BH}^+ + \mathrm{OH}^- \) becomes
To calculate \( K_b \), you measure the concentration of the hydroxide ions produced when a base dissociates in water. The equation for a generic base, \( \mathrm{B} \triangleq \mathrm{B} + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{BH}^+ + \mathrm{OH}^- \) becomes
- \( K_b = \frac{[\mathrm{BH}^+][\mathrm{OH}^-]}{[\mathrm{B}]} \)
conjugate acid-base pair
Conjugate acid-base pairs consist of two species that transform into each other by gaining or losing a proton (\( \mathrm{H}^+ \)). When a base gains a proton, it becomes its conjugate acid, and when an acid loses a proton, it transforms into its conjugate base.
For instance, consider pyridine, \( \mathrm{C}_5 \mathrm{H}_5 \mathrm{N} \). When it gains a proton, it turns into \( \mathrm{C}_5 \mathrm{H}_5 \mathrm{NH}^+ \), its conjugate acid. Here, \( \mathrm{C}_5 \mathrm{H}_5 \mathrm{N} \) and \( \mathrm{C}_5 \mathrm{H}_5 \mathrm{NH}^+ \) form a conjugate acid-base pair.Key characteristics of conjugate pairs:
For instance, consider pyridine, \( \mathrm{C}_5 \mathrm{H}_5 \mathrm{N} \). When it gains a proton, it turns into \( \mathrm{C}_5 \mathrm{H}_5 \mathrm{NH}^+ \), its conjugate acid. Here, \( \mathrm{C}_5 \mathrm{H}_5 \mathrm{N} \) and \( \mathrm{C}_5 \mathrm{H}_5 \mathrm{NH}^+ \) form a conjugate acid-base pair.Key characteristics of conjugate pairs:
- The acid has one more \(\mathrm{H}^+\) and a higher positive charge than its conjugate base.
- Pairs are found ubiquitously in acid-base reactions, notably following the Brønsted-Lowry theory.
- The \( K_a \) of the acid and \( K_b \) of the base are inversely related through \( K_w \).
ion-product constant of water (Kw)
The ion-product constant of water, denoted as \( K_w \), is a special equilibrium constant that reflects the autoionization of water:\[ \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{H}^+ + \mathrm{OH}^- \]At room temperature (25°C), \( K_w \) is approximately \( 1.0 \times 10^{-14} \). It signifies the product of the concentrations of hydrogen ions \( [\mathrm{H}^+] \) and hydroxide ions \( [\mathrm{OH}^-] \) in pure water.
\[ K_w = [\mathrm{H}^+] \times [\mathrm{OH}^-] = 1.0 \times 10^{-14} \] This constant is crucial because it shows water undergoes a slight but significant degree of ionization, influencing the balance between acidic and basic environments.
Important points about \( K_w \):
\[ K_w = [\mathrm{H}^+] \times [\mathrm{OH}^-] = 1.0 \times 10^{-14} \] This constant is crucial because it shows water undergoes a slight but significant degree of ionization, influencing the balance between acidic and basic environments.
Important points about \( K_w \):
- It remains the same under standard conditions, balancing acid and base concentrations.
- \( K_w \) connects \( K_a \) and \( K_b \) for conjugate pairs in water: \( K_a \times K_b = K_w \).
- Temperature changes can affect the value of \( K_w \), altering acidic and basic properties of solutions.