Chapter 21: Problem 5
Octahedral complexes of metal centres with high oxidation numbers or of \(\mathrm{d}\) metals of the second and third series are less labile than those of low oxidation number and \(\mathrm{d}\) metals of the first series of the block. Account for this observation on the basis of a dissociative rate- determining step.
Short Answer
Step by step solution
Understanding the Concepts
Explaining Electronic and Geometric Factors
Series Differences in Metal Centers
Understanding the Rate-Determining Step
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Metal-Ligand Bonds
- Stronger metal-ligand bonds mean that the metal center holds onto its ligands more tightly.
- This reduces the tendency for ligands to substitute, decreasing the complex's lability.
Oxidation State
- A high positive charge intensifies the attraction between the metal and its ligands.
- This attraction strengthens metal-ligand bonds and reduces the ease of ligand substitution.
Transition Metals
- First series (3d)
- Second series (4d)
- Third series (5d)
- Bigger ions tend to possess stronger field strengths, enhancing crystal field splitting.
- This often results in less reactive or less labile complexes.
Lability
- Stronger bonds result in lower lability due to more rigid ligand positions.
- Weaker bonds make ligand substitution easier, increasing lability.
Crystal Field Splitting
- The strength of the metal's field, influenced by the oxidation state.
- The series of the transition metal, with higher series typically displaying more significant splitting.