Chapter 7: Problem 7
When NaCN dissolves in water, the resulting solution is basic. Account for this observation given that \(\mathrm{p} K_{\mathrm{a}}\) for HCN is 9.31.
Short Answer
Expert verified
NaCN forms a basic solution as CN\(^-\) forms OH\(^-\) ions, making the solution basic.
Step by step solution
01
Understand the Dissolution Process
When NaCN dissolves in water, it dissociates into sodium ions (Na\(^+\)) and cyanide ions (CN\(^-\)). These ions are free to interact with water molecules.
02
Analyze the Cyanide Ion Behavior
The CN\(^-\) ion is the conjugate base of the weak acid HCN. Since CN\(^-\) can accept protons, it can react with water to form HCN and OH\(^-\): \[ \text{CN}^- + \text{H}_2\text{O} \rightleftharpoons \text{HCN} + \text{OH}^- \] This reaction produces hydroxide ions (OH\(^-\)), which make the solution basic.
03
Consider the Strength of HCN as an Acid
HCN is a weak acid with a high \(pK_a\) value of 9.31, indicating it only partially ionizes in water. Consequently, its conjugate base CN\(^-\) is relatively strong and effectively able to accept protons, increasing the OH\(^-\) concentration in the solution.
04
Conclude the Basicity of the Solution
Since the CN\(^-\) ions react with water to produce OH\(^-\) ions, the overall concentration of hydroxide ions in the solution exceeds that of hydronium ions \((H_3O^+)\), resulting in a basic solution.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Basic Solutions
Basic solutions are a key concept in inorganic chemistry and are characterized by the presence of more hydroxide ions (OH\(^-\)) than hydrogen ions (H\(^+\)). This results in a pH greater than 7. An everyday example of a basic solution is household ammonia.
In the context of our exercise, when NaCN dissolves in water, the solution becomes basic. This is because the cyanide ions (CN\(^-\)) interact with water to produce hydroxide ions. This shift in ion balance makes the solution basic.
Here’s a quick recap of why the solution turns basic:
In the context of our exercise, when NaCN dissolves in water, the solution becomes basic. This is because the cyanide ions (CN\(^-\)) interact with water to produce hydroxide ions. This shift in ion balance makes the solution basic.
Here’s a quick recap of why the solution turns basic:
- NaCN dissociates into Na\(^+\) and CN\(^-\) in water.
- CN\(^-\) interacts with water molecules, leading to the generation of hydroxide ions (OH\(^-\)).
- The increase in OH\(^-\) in the solution means the pH is above 7, characterizing it as basic.
Dissolution Process of NaCN
The dissolution process is the method by which solutes dissolve in a solvent. In this case, NaCN dissolving in water is our focus.
When NaCN is added to water, it undergoes dissociation. This means breaking apart into ions: Na\(^+\) and CN\(^-\). The key players in this reaction are these ions and water molecules.
Na\(^+\), a spectator ion, doesn’t significantly affect the pH of the solution. However, CN\(^-\) plays a major role. It interacts with water as follows:
When NaCN is added to water, it undergoes dissociation. This means breaking apart into ions: Na\(^+\) and CN\(^-\). The key players in this reaction are these ions and water molecules.
Na\(^+\), a spectator ion, doesn’t significantly affect the pH of the solution. However, CN\(^-\) plays a major role. It interacts with water as follows:
- The CN\(^-\) ion binds with a water molecule.
- This interaction forms hydrogen cyanide (HCN) and hydroxide ions (OH\(^-\)).
- Importantly, this process generates OH\(^-\), increasing the solution's basicity.
Exploring Weak Acids and Bases
Weak acids and bases do not fully ionize in solution, meaning only a small fraction of their molecules are converted into ions. HCN is an example of a weak acid, characterized by a high pK\(_a\) value of 9.31. This implies that HCN only partially ionizes in water.
Since the ionization is incomplete, the conjugate base CN\(^-\) remains relatively strong. This conjugate base has a high tendency to accept protons (H\(^+\)) from water, shifting equilibrium and leading to the formation of hydroxide ions (OH\(^-\)).
The key features of weak acids and their conjugate bases include:
Since the ionization is incomplete, the conjugate base CN\(^-\) remains relatively strong. This conjugate base has a high tendency to accept protons (H\(^+\)) from water, shifting equilibrium and leading to the formation of hydroxide ions (OH\(^-\)).
The key features of weak acids and their conjugate bases include:
- High pK\(_a\) value indicates a weak acid like HCN, which doesn’t donate protons readily.
- The conjugate base (CN\(^-\)) is stronger as it can easily accept protons from water.
- This acceptance of protons increases OH\(^-\) concentration, making the solution more basic.