Chapter 20: Problem 30
For which of the following ions would you expect the spin-only formula to give reasonable estimates of the magnetic moment: (a) \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}\) (b) \(\left[\mathrm{V}\left(\mathrm{OH}_{2}\right)_{6}\right]^{3+}\) (c) \(\left[\mathrm{CoF}_{6}\right]^{3-} ?\) Rationalize your answer.
Short Answer
Step by step solution
Understand Spin-Only Magnetic Moment Formula
Determine Electron Configuration of Ions
Count Unpaired Electrons
Evaluate Ligand Field Strength
Apply Spin-Only Formula
Make a Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Spin-Only Formula
- \( \mu = \sqrt{n(n+2)} \)
Unpaired Electrons
- In the case of Chromium (III), with its electron configuration of \([Ar] 3d^3\), there are 3 unpaired electrons.
- Vanadium (III) has the configuration \([Ar] 3d^2\), thus having 2 unpaired electrons.
- Cobalt (III), configured as \([Ar] 3d^6\), is a bit more complex as the presence of unpaired electrons depends on the interaction with the ligands.
Ligand Field Strength
- Strong field ligands: These cause larger splitting in the d-orbitals and can pair up electrons in the lower energy orbitals.
- Weak field ligands: These result in smaller splitting, often leaving electrons unpaired.
- \( \mathrm{NH}_3 \) in \([\mathrm{Cr}(\mathrm{NH}_3)_6]^{3+}\) is a weak field ligand, leaving unpaired electrons.
- Similarly, \( \mathrm{H}_2\mathrm{O} \) in \([\mathrm{V}(\mathrm{OH}_2)_6]^{3+}\) is weak, with electrons remaining unpaired.
- \( \mathrm{F}^- \) in \([\mathrm{CoF}_6]^{3-}\) also acts as a weak field ligand, but \( \mathrm{Co}^{3+} \)'s magnetic moment can be more affected by potential orbital contributions.
The ligand field strength thereby dictates whether or not utilizing the spin-only formula will yield accurate results, by affecting the number of unpaired electrons.
Octahedral Complexes
- The five d-orbitals split into two sets: a lower energy set comprising three orbitals known as \( t_{2g} \), and a higher energy set of two orbitals known as \( e_g \).
- The extent of this splitting depends on the nature of the ligands. Strong field ligands tend to cause larger splitting, potentially pairing up the electrons within the lower \( t_{2g} \) set.
- Weak field ligands generally result in smaller splitting, which typically leaves the unpaired electrons unaffected.