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Comment on the variation in oxidation states of the first row metals. Why are Sc and Zn not classed as transition metals?

Short Answer

Expert verified
Sc and Zn are not classed as transition metals because Sc lacks d electrons in Sc鲁鈦, and Zn has a full d subshell in Zn虏鈦.

Step by step solution

01

Understanding Oxidation States

Oxidation states, also known as oxidation numbers, indicate the degree of oxidation of an atom in a compound. Transition metals can exhibit multiple oxidation states because of their ability to lose different numbers of d electrons and sometimes s electrons. As we traverse across the first row of transition metals, from Scandium (Sc) to Zinc (Zn), variation in oxidation states occurs due to the increasing number of d electrons.
02

Oxidation State Variation Across the Series

The first row of transition metals shows a gradual change in oxidation states. Scandium, with an electronic configuration [Ar] 3d鹿 4s虏, typically shows an oxidation state of +3. Moving along the series, elements such as Iron (Fe) can display multiple oxidation states, like +2 and +3. By the time we reach Zn, which has an electronic configuration of [Ar] 3d鹿鈦 4s虏, it exhibits a stable +2 oxidation state because it has a completely filled d subshell.
03

Identifying Transition Metals

Transition metals are typically defined as elements that form at least one ion with a partially filled d subshell. Scandium forms only Sc鲁鈦, which lacks d electrons. Zinc, on the other hand, forms only Zn虏鈦, with a completely filled d subshell (3d鹿鈦). Since neither Sc nor Zn has partially filled d orbitals in their most stable or common oxidation states, they do not fit the accepted definition of a transition metal.
04

Conclusion

In summary, while the first-row transition metals show variation in oxidation states due to the filling of the 3d subshell, Scandium and Zinc do not fit the typical definition of a transition metal. Scandium does not have partially filled d orbitals in its common ions, and Zinc has a full d sublevel, explaining why they are not classified as transition metals.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation States
Oxidation states are numbers assigned to an element in a chemical compound, indicating the number of electrons lost or gained by an atom. In transition metals, these states can vary widely because the atoms can lose different numbers of d and sometimes s electrons. This ability to have multiple oxidation states makes transition metals highly versatile in chemical reactions.

In the first-row transition metals, which span from Scandium (Sc) to Zinc (Zn), there is a notable variation in oxidation states. For example, Scandium generally exhibits an oxidation state of +3. As we move along the series, elements such as Iron (Fe) can have states like +2 and +3, showcasing their ability to participate in different types of chemical bonding. By the time we reach Zinc, the oxidation state stabilizes at +2 due to its completely filled d shell.

The range of oxidation states significantly contributes to the complex chemistry of these metals. Understanding these states helps predict how a transition metal will behave in a chemical reaction.
Scandium and Zinc Classification
Despite being in the d-block of the periodic table, Scandium and Zinc are not classified as transition metals. This classification relies on the presence of ions with partially filled d subshells.

  • Scandium: It forms Sc鲁鈦 ions, which completely lack d electrons because the 3d level does not get populated in this oxidation state.
  • Zinc: It forms Zn虏鈦 ions, which have a fully filled 3d鹿鈦 subshell, leaving no partially filled d orbitals to qualify it as a transition metal.
Since neither Scandium nor Zinc fits the criterion of having ions with incomplete d subshells in their most commonly observed oxidation states, they stand out as exceptions to the classification of transition metals.
Electronic Configuration
Electronic configuration refers to the distribution of electrons in an atom's orbitals. Understanding this helps in predicting an element's chemical behavior.

In the context of transition metals, the filling of the d orbitals is key. For Scandium, the electronic configuration is [Ar] 3d鹿 4s虏. As we move across the series, the d orbital fills with electrons, influencing oxidation states and chemical properties. For example, Iron has a configuration of [Ar] 3d鈦 4s虏, allowing for a variety of oxidation states due to the number of both d and s electrons available for bonding.
By the time we reach Zinc, the configuration is [Ar] 3d鹿鈦 4s虏, showing a fully filled d shell, which restricts it to a +2 oxidation state.

Examining electronic configurations can explain why different elements behave in certain ways in chemical reactions.
Definition of Transition Metals
The definition of transition metals centers around their electronic structure, particularly the d subshell. A transition metal is an element that forms at least one ion with a partially filled d subshell. This definition helps delineate elements that demonstrate the unique properties typical of transition metals.

Transition metals are known for several key characteristics:
  • The ability to form colorful compounds due to d-d electron transitions.
  • Variable oxidation states, which make them useful in catalysts and chemical processes.
  • Strong yet flexible bonding, contributing to the durability and high melting points of their compounds.
However, as per this definition, Scandium and Zinc do not qualify as transition metals because they do not have ions with incompletely filled d orbitals in their most stable forms. Understanding these intricacies helps clarify the distinct behaviors of elements within the d-block of the periodic table.

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Most popular questions from this chapter

(a) The value of \(\mu_{\mathrm{eff}}\) for \(\left[\mathrm{CoF}_{6}\right]^{3-}\) is \(5.63 \mu_{\mathrm{B}} .\) Explain why this value does not agree with the value for \(\mu\) calculated from the spin-only formula. (b) By using a simple \(\mathrm{M} \mathrm{O}\) approach, rationalize why oneelectron oxidation of the bridging ligand in \(\left[(\mathrm{CN})_{5} \mathrm{CoOOCo}(\mathrm{CN})_{5}\right]^{6-}\) leads to a shortening of the \(\mathrm{O}-\mathrm{O}\) bond (c) Salts of which of the following complex ions might be expected to be formed as racemates: \(\left[\mathrm{Ni}(\operatorname{acac})_{3}\right]^{-}\) \(\left[\mathrm{CoCl}_{3}(\mathrm{NCMe})\right]^{-},\) cis-\(\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]^{+},\) trans- \(\left[\mathrm{Cr}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]^{+} ?\)

Comment on each of the following observations. (a) \(\mathrm{Li}_{2} \mathrm{TiO}_{3}\) forms a continuous range of solid solutions with \(\mathrm{MgO}\) (b) When \(\mathrm{TiCl}_{3}\) is heated with concentrated aqueous \(\mathrm{NaOH}, \mathrm{H}_{2}\) is evolved.

Treatment of an aqueous solution of \(\mathrm{NiCl}_{2}\) with \(\mathrm{H}_{2} \mathrm{NCHPhCHPhNH}_{2}\) gives a blue complex \(\left(\mu_{\mathrm{eff}}=3.30 \mu_{\mathrm{B}}\right)\) which loses \(\mathrm{H}_{2} \mathrm{O}\) on heating to form a yellow, diamagnetic compound. Suggest explanations for these observations and comment on possible isomerism in the yellow species.

(a) When \([\mathrm{CN}]^{-}\) is added to aqueous \(\mathrm{Ni}^{2+}\) ions, a green precipitate forms; if excess \(\mathrm{KCN}\) is added, the precipitate dissolves to give a yellow solution and at high concentrations of \([\mathrm{CN}]^{-},\) the solution becomes red. Suggest an explanation for these observations. (b) If the yellow compound from part (a) is isolated and reacted with Na in liquid \(\mathrm{NH}_{3},\) a red, air-sensitive, diamagnetic product can be isolated. Suggest its identity.

Write down formulae for the following ions: (a) manganate(VII); (b) manganate(VI); (c) dichromate(VI); (d) vanadyl; (e) vanadate (ortho and meta); (f) hexacyanoferrate(III). Give an alternative name for manganate(VII).

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