Chapter 10: Problem 10
(a) Write equations for the reactions of KH with \(\mathrm{NH}_{3}\) and with ethanol. (b) Identify the conjugate acid-base pairs in each reaction.
Short Answer
Expert verified
KH reacts with NH鈧 to form KNH鈧 and H鈧, and with ethanol to form C鈧侶鈧匫K and H鈧. Conjugate pairs are KH/H鈧 and NH鈧/KNH鈧 in the first reaction, and KH/H鈧 and C鈧侶鈧匫H/C鈧侶鈧匫鈦 in the second.
Step by step solution
01
Write Equation for KH and NH3 Reaction
Potassium hydride (KH) reacts with ammonia (NH_3"). The reaction proceeds as follows: \(\mathrm{KH} + \mathrm{NH}_3 \rightarrow \mathrm{KNH}_2 + \mathrm{H}_2\).Here, hydrogen gas is released and potassium amide (KNH鈧) is formed.
02
Identify Conjugate Acid-Base Pair in KH and NH3 Reaction
In the reaction \(\mathrm{KH} + \mathrm{NH}_3 \rightarrow \mathrm{KNH}_2 + \mathrm{H}_2\), the conjugate acid-base pairs are:1. Base: \(\mathrm{KH}\), which gives \(\mathrm{H}^-\) ion. Conjugate acid is \(\mathrm{H}_2\) after releasing \(\mathrm{H}^-\). 2. Acid: \(\mathrm{NH}_3\), which acts as a proton acceptor. Conjugate base is \(\mathrm{KNH}_2\) after donating a hydrogen ion.
03
Write Equation for KH and Ethanol Reaction
Potassium hydride reacts with ethanol (C鈧侶鈧匫H). The chemical equation is: \(\mathrm{KH} + \mathrm{C}_2\mathrm{H}_5\mathrm{OH} \rightarrow \mathrm{C}_2\mathrm{H}_5\mathrm{OK} + \mathrm{H}_2\).Hydrogen gas is again released, and potassium ethoxide (C鈧侶鈧匫K) is formed.
04
Identify Conjugate Acid-Base Pair in KH and Ethanol Reaction
In the reaction \(\mathrm{KH} + \mathrm{C}_2\mathrm{H}_5\mathrm{OH} \rightarrow \mathrm{C}_2\mathrm{H}_5\mathrm{OK} + \mathrm{H}_2\), the conjugate acid-base pairs are:1. Base: \(\mathrm{KH}\), providing \(\mathrm{H}^-\) ion, with \(\mathrm{H}_2 \) as the conjugate acid upon the release of \(\mathrm{H}^-\). 2. Acid: \(\mathrm{C}_2\mathrm{H}_5\mathrm{OH}\), which donates a proton to become \(\mathrm{C}_2\mathrm{H}_5\mathrm{O}^-\), the conjugate base.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Conjugate Acid-Base Pairs
In chemistry, a crucial aspect to understand in acid-base reactions is the concept of conjugate acid-base pairs. An acid-base pair includes an acid and a base that transform into each other by the gain or loss of a proton (H鈦 ion). Whenever an acid donates a proton, it becomes its conjugate base. Conversely, when a base accepts a proton, it becomes its conjugate acid.
- In the reaction between potassium hydride (KH) and ammonia (NH鈧), KH functions as a base by releasing an H鈦 ion and ultimately forms molecular hydrogen (H鈧) as its conjugate acid.
- Ammonia (NH鈧) accepts a proton from KH, acting as an acid in this case, and transforms into potassium amide (KNH鈧), which is the conjugate base.
- KH once again acts as a base, forming molecular hydrogen (H鈧) as its conjugate acid.
- Ethanol (C鈧侶鈧匫H) donates a proton, acting as an acid, and becomes potassium ethoxide (C鈧侶鈧匫鈦), the conjugate base.
Chemical Equations
Chemical equations represent the substances involved in a chemical reaction, showcasing the reactants transforming into products. Understanding the symbols and structure of these equations helps explain what is happening at the molecular level. For instance, in the reaction \[\mathrm{KH} + \mathrm{NH}_3 \rightarrow \mathrm{KNH}_2 + \mathrm{H}_2\]we see that potassium hydride (KH) and ammonia (NH鈧) are the reactants. They react to form potassium amide (KNH鈧) and hydrogen gas (H鈧), which are the products.
- The reactants are placed on the left side of the equation, and the products are shown on the right side, separated by an arrow (鈫) indicating the direction of the reaction.
- In a balanced equation, the number of atoms of each element is conserved, meaning they appear equally on both sides.
Reaction Mechanisms
Reaction mechanisms explain the step-by-step process through which a chemical reaction occurs. These mechanisms provide insight into the specific changes happening at the atomic or molecular level.
The reactions between potassium hydride (KH) and either ammonia (NH鈧) or ethanol (C鈧侶鈧匫H) illustrate clear steps:
- In both reactions, KH acts as a hydride donor, releasing a hydrogen ion, which is a key proton exchange process.
- Ammonia or ethanol, acting as acids, readily accept this proton, facilitating the formation of new products such as potassium amide or potassium ethoxide, respectively.