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What is the basic structural difference between starch and cellulose?

Short Answer

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Answer: The basic structural difference between starch and cellulose lies in the types of glycosidic bonds present between their glucose monomers. Starch has α-linkages that form a helical structure, while cellulose has β-linkages that form a straight, rigid structure. This difference in structure influences their properties, making starch an energy storage molecule and cellulose a structural support material for plants.

Step by step solution

01

Introduction to starch and cellulose

Starch and cellulose are both polysaccharides, which means they are long chains of sugar molecules. Starch is primarily used by plants as energy storage while cellulose plays a vital role in providing structural support to plant cells. Even though they are both composed of glucose monomers, their molecular structures and bonding patterns differ, which affects their properties and uses in living organisms.
02

Starch structure

Starch is a polysaccharide made up of glucose monomers, and it can exist in two forms: amylose and amylopectin. Amylose is a linear chain of glucose molecules linked by α(1→4) glycosidic bonds, while amylopectin is a branched molecule with both α(1→4) glycosidic bonds (for the main chain) and α(1→6) glycosidic bonds (for the branches). These α-linkages allow the glucose molecules to form a helical structure.
03

Cellulose structure

Cellulose, on the other hand, is a linear chain of glucose molecules connected by β(1→4) glycosidic bonds. This difference in bonding results in a straight, rigid structure instead of a helical one like in starch. The cellulose chains form strong hydrogen bonds with adjacent chains, leading to an overall strong fibrous structure, which provides structural support to plant cell walls.
04

Comparison of starch and cellulose structures

The essential structural difference between starch and cellulose lies in the type of glycosidic bonds that connect their glucose monomer units. Starch uses α(1→4) glycosidic bonds, which grants it a helical structure, while cellulose utilizes β(1→4) glycosidic bonds, resulting in a straight, rigid structure. Additionally, starch may contain branching α(1→6) glycosidic bonds, while cellulose remains unbranched.
05

Conclusion

The basic structural difference between starch and cellulose lies in the types of glycosidic bonds present between their glucose monomers. Starch has α-linkages that form a helical structure, while cellulose has β-linkages that form a straight, rigid structure. This difference in structure influences their properties, making starch an energy storage molecule and cellulose a structural support material for plants.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polysaccharides
Imagine a long train composed of multiple carriages; this is similar to 'polysaccharides', with each carriage representing a sugar molecule. Polysaccharides are large, complex carbohydrates formed by linking together numerous 'glucose monomers' — the building blocks of these biological polymers. They serve varied functions in nature: some are used for storage, like 'starch', which plants use to stockpile energy, whereas others, such as 'cellulose', provide structural integrity to plant cell walls.

Depending on how these glucose units are linked, polysaccharides can be either highly branched, like a tree with many offshoots, or linear and straight, like a bamboo pole. This can dramatically affect their physical properties – imagine trying to push a rope through a tight space versus a solid rod. The 'glycosidic bonds' that act as ties between each glucose unit are critical in determining the final structure and function of these molecules in living organisms.
Glycosidic Bonds
Glycosidic bonds are like the handshakes between glucose monomers; they are the connections that form the structural backbone of 'polysaccharides'. In the case of 'starch' and 'cellulose', the position and orientation of the 'glucose monomers' involved in these handshakes are distinct.

'Starch' is like a group of people standing in a spiral staircase, connected by handshakes. This spiral structure is formed through the 'α(1→4) glycosidic bonds'. In contrast, 'cellulose' is akin to people standing in a straight line hand in hand, created via 'β(1→4) glycosidic bonds'. These different bond types result in different 3-dimensional shapes, leading to varied functions such as easily accessible energy in starch or rigid structure in cellulose. Thus, these 'glycosidic bonds' greatly influence the properties and the usage of the polysaccharides in which they are found.
Glucose Monomers
The simple sugar 'glucose' acts as a monomer, or single unit, that can be linked with others to form more complex molecules such as 'starch' and 'cellulose'. Just as individual beads can be strung together to create various forms of jewelry, 'glucose monomers' can be connected in different ways to create a variety of 'polysaccharides'.

Depending on how they are connected via 'glycosidic bonds', the chains of glucose can form distinct structures, each with their function. As in the case of 'starch', these monomers are mostly organized in branching chains that are easily broken down, making them well-suited for energy storage. Meanwhile, in 'cellulose', the glucose units are arranged in straight lines, which contribute to a rigid structure that is not easily digestible – ideal for the plant cell structure that needs to withstand various pressures.
Plant Cell Structure
The 'plant cell structure' is like a castle with different materials for different purposes; it requires materials for strength, storage, and more. In this analogy, 'starch' could be seen as the food reserves stored in the castle's cellars, readily accessed when needed. 'Cellulose', on the other hand, is akin to the stones that make up the massive walls, providing protection and stability.

While starch accumulates within the cells often in the form of granules, cellulose is a fundamental component of the cell wall, which surrounds plant cells. This wall is not just a rigid box; rather, it's a dynamic structure, strengthened by the long, straight chains of 'cellulose' that resist pressure and protect the cell. The differences in the way their constituent 'glucose monomers' are linked are critical and result in 'starch' and 'cellulose' serving vastly different roles in the life of a plant.

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Most popular questions from this chapter

This section contains 2 paragraphs. Based upon the paragraph, 3 multiple choice questions have to be answered. Each question has 4 choices \((a),(b),(c)\) and \((d)\), out of which ONLY ONE is correct. In order to identify and characterize the various functional groups present in an organic compound (or a mixture of organic compounds), a complete knowledge of the tests answered by these functional groups is essential. An organic compound burns with a sooty flame and gives a violet colouration with neutral \(\mathrm{FeCl}_{3}\) solution. It gives effervescence when treated with metallic sodium and also with sodium bicarbonate solution. The compound could be (a) phenol (b) benzoic acid (c) salicyclic acid (d) toluic acid

Give reasons for the following statements. (i) o- and p-nitrophenols can be separated by steam distillation. (ii) Sodium fusion extract has to be neutralized with dil.HNO \(_{3}\) before testing for the halogen with \(\mathrm{AgNO}_{3^{*}}\) (iii) Benzene does not decolourise bromine water though it contains three double bonds. (iv) Lassaigne's test for nitrogen is not given by diazonium compound. (v) Sodium fusion extract is boiled with \(\mathrm{HNO}_{3}\) for testing for halogen, if nitrogen and sulphur are present.

This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. An organic compound on elemental analysis is found to contain two chlorine atoms. This compound is treated with caustic soda and subsequently with \(\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right] \mathrm{OH}\) to get a silver deposit. Then we can say that (a) The two \(\mathrm{Cl}\) atoms are attached to an aromatic ring. (b) The two \(\mathrm{Cl}\) atoms are on adjacent carbons of an aliphatic chain. (c) The two \(\mathrm{Cl}\) atoms are on the same carbons of an aliphatic chain. (d) One chlorine is on a tertiary carbon atom.

This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. A compound containing a conjugated double bond, decolourises bromine water. On heating with \(\mathrm{I}_{2}\) and \(\mathrm{NaOH}\), a yellow precipitate is formed. If the compound contains five carbons including a methyl substituent, the compound may be (a) 3 -methyl but- 3 -en- 2 -one. (b) 3 -methyl but- 3 -enal (c) 3 -methyl but- 2 -enal (d) 2 -methyl but- 2 -enal

Carbohydrates are classified as monosaccharides, oligosaccharides and polysaccharides depending on their behaviour towards hydrolysis. All monosaccharides containing five or six carbon atoms can have two cyclic structures namely furanose and pyranose form. Oligosaccharides are further classified as di, tri, tetra etc saccharides depeding upon the number of monosaccharide units actually obntained on hyrolysis. In oligosaccharides and polysaccharides, the different monomer units are joined together by glycosidic linkages. The incorrect statement about sucrose is (a) It does not reduce Tollen's reagent for Fehling's solution. (b) It is not optically active. (c) It is an a-D-glucoside. (d) It does not form osazone with phenyl hydrazine.

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