Chapter 3: Problem 2
How can benzene be converted to m-dibromobenzene?
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Chapter 3: Problem 2
How can benzene be converted to m-dibromobenzene?
These are the key concepts you need to understand to accurately answer the question.
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When 2 -hydroxybenzoic acid (salicylic acid) is treated with bromine water, the product formed is
Statement 1 Phenoxide ion is more reactive than phenol towards electrophiles. and Statement 2 Phenoxide ion is stabilized more by resonance than phenol.
(A) and (b) are respectively (a) o-nitrophenol and o-nitrobenzoic acid. (b) p-nitrosophenol and p-nitrophenol (c) m-nitrosophenol and m-nitrophenol (d) p-nitrosophenol and \(\mathrm{p}\) -aminophenol
Column I Column II (a) Electrophilic substitution (p) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{~N}_{2} \mathrm{Cl}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH} \stackrel{\mathrm{NaOH}}{\longrightarrow}\) (b) Nucleophilic substitution (q) Toluene + \(\mathrm{NBS} \longrightarrow\) (c) Free radical substitution (r) Dow's process (d) Coupling reaction (s) Phenol \(\longrightarrow\) picric acid (t) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O} \mathrm{Na}+\mathrm{CH}_{3} \mathrm{Br} \longrightarrow\)
Give the major product of mono nitration of the following compounds. Justify each case.
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