/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 What is the product of 0.8102 \(... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

What is the product of 0.8102 \(\mathrm{m}\) and 3.44 \(\mathrm{m} ?\)

Short Answer

Expert verified
The product of 0.8102 \(\mathrm{m}\) and 3.44 \(\mathrm{m}\) is 2.787088 \(\mathrm{m}^2\).

Step by step solution

01

Arrange the Numbers

First, arrange the numbers so that 0.8102 is on top of 3.44. The decimal points should be directly above each other.
02

Perform the Multiplication

Next, perform the multiplication as if there were no decimal points. Multiply 8102 by 344.
03

Place the Decimal Point

The next step is determining the correct place for the decimal point in the product. Add the number of digits after the decimal in the original numbers (four in 0.8102 and two in 3.44, total of six) and place the decimal in the product so that there are six digits after it.
04

Expressing the Solution

Finally, express the product in terms of the units given in the problem, which in this case are meters (\(\mathrm{m}\)).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Graphing Celsius and Fahrenheit Temperatures The graphing calculator can run a program that makes a graph of a given Fahrenheit temperature (on the \(x\) -axis) and the corresponding Celsius temperature (on the \(y\) -axis). You can use the TRACE button on the calculator to explore this graph and learn more about how the two temperature scales are related. Go to Appendix c. If you are using a TI-83 Plus, you can download the program CELSIUS and run the application as directed. If you are using another calculator, your teacher will provide you with keystrokes and data sets to use. After the graph is displayed, press TRACE. An X-shaped cursor on the graph line indicates a specific point. At the bottom of the screen the values are shown for that point. The one labeled \(\mathrm{X}=\) is the Fahrenheit temperature and the one labeled \(\mathrm{Y}=\) is the Celsius temperature. Use the right and left arrow keys to move the cursor along the graph line to find the answers to these questions. a. What is the Fahrenheit temperature when the Celsius temperature is zero? (This is where the graph line crosses the horizontal \(x\) -axis. What is the significance of this temperature? b. Human internal body temperature averages \(98.6^{\circ} \mathrm{F.}\) What is the corresponding value on the Celsius scale? c. Determine the Fahrenheit temperature in your classroom or outside, as given in a weather report. What is the corresponding Celsius temperature? d. At what temperature are the Celsius and Fahrenheit temperatures the same?

Express 743000000 in scientific notation to the following number of significant figures: a. one significant figure b. two significant figures c. four significant figures

A student measures the mass of some sucrose as 0.947 mg. Convert that quantity to grams and to kilograms.

How many grams are in 882\(\mu \mathrm{g} ?\)

Use the following terms to create a map: energy, endothermic, physical law of conservation of energy, and exothermic.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.