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Write the half-reaction for the production of silver metal from silver ions. Write the half-reaction for the production of gold metal from gold(III) ions. Using these half- reactions, provide an explanation for the difference in the rates of production of the metals.

Short Answer

Expert verified
Half-reaction for silver: \(Ag^{+}(aq) + e^{-} \rightarrow Ag(s)\), for gold: \(Au^{3+}(aq) + 3e^{-} \rightarrow Au(s)\). The production rate of silver is faster than that of gold due to the number of electrons required in the reduction process.

Step by step solution

01

Write the half-reaction for silver ions to silver metal

In the reduction half-reaction, silver ions (Ag+) gain an electron to become silver metal. Therefore, the half-reaction for silver is: \(Ag^{+}(aq) + e^{-} \rightarrow Ag(s)\)
02

Write the half-reaction for gold(III) ions to gold metal

For gold(III) ions (Au3+), three electrons are needed for their reduction to gold metal, hence the half-reaction for gold is: \(Au^{3+}(aq) + 3e^{-} \rightarrow Au(s)\)
03

Explain the difference in rates of production

The different rates of silver and gold production are due to the number of electrons involved in their respective reduction half-reactions. Silver ion is reduced to silver metal in a one electron process, whereas the gold(III) ion requires three electrons to be reduced to gold metal. Therefore, it's reasonable to expect that the reduction of gold(III) ions to gold metal occurs at a slower rate than the reduction of silver ions to silver metal, given everything else being equal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Silver Ion Reduction
Understanding the process of silver ion reduction is essential in electrochemistry, particularly in contexts such as the purification of silver and the manufacture of photographic films. This reaction involves a transfer of electrons that transforms positively charged silver ions back into metallic silver.

Silver ion reduction can be represented by a simple half-reaction equation: \(Ag^{+}(aq) + e^{-} \rightarrow Ag(s)\). In this equation, \(Ag^{+}(aq)\) denotes a silver ion in aqueous solution, \(e^{-}\) represents an electron, and \(Ag(s)\) is the solid silver produced. During this reaction, each silver ion accepts a single electron, which is why this process is termed a one-electron transfer reaction.

Gold(III) Ion Reduction
The process of gold(III) ion reduction is another fascinating aspect of redox chemistry, particularly valued for applications in gold refining and electronic device manufacturing. This reaction is more complex than the reduction of silver ions because it involves a three-electron transfer.

The correct half-reaction for the reduction of gold(III) ions to solid gold is expressed by the equation: \(Au^{3+}(aq) + 3e^{-} \rightarrow Au(s)\). Here, the \(Au^{3+}(aq)\) indicates a gold(III) ion in an aqueous solution, requiring three electrons (\(3e^{-}\)) to be reduced to metallic gold (\(Au(s)\)). This multi-electron process signifies that more steps are involved to achieve reduction, which inherently affects the kinetics of the reaction.

Rate of Metal Production
The rate of metal production during such reduction reactions is greatly influenced by the number of electrons each metal ion requires for reduction. The concept of rate plays a crucial part in industrial applications, where efficiency and speed are paramount.

To compare, silver ions undergo a single-electron reduction process which is typically faster than gold's three-electron process. Factors such as the number of steps required and availability of electrons play a role in dictating how quickly the reaction can proceed. Consequently, with one electron needed per ion, silver can be reduced more quickly than gold, where three electrons are needed per ion. These differences in the rates of metal production influence how we design and operate processes for extracting these precious metals.

Electrochemistry
Electrochemistry encompasses the study of chemical processes that cause electrons to move. This field is important for numerous applications, including the functioning of batteries, corrosion prevention, and the electroplating of metals.

Both the silver and gold ion reduction reactions are quintessential examples of redox reactions in electrochemistry. Redox reactions are classified into two parts: oxidation, where a substance loses electrons, and reduction, where a substance gains electrons. The movement of electrons from one element to another underpins the concept of current in electrochemical cells. This intrinsic connection between chemical reactions and electricity is what makes electrochemistry a cornerstone of modern science and technology.

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