Chapter 13: Problem 31
Why does warmer liquid dissolve less gas than colder liquid?
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These are the key concepts you need to understand to accurately answer the question.
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Chapter 13: Problem 31
Why does warmer liquid dissolve less gas than colder liquid?
These are the key concepts you need to understand to accurately answer the question.
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Graphing Calculator Predicting Solubility from Tabular Data The graphing calculator can run a programthat graphs solubility data. Given solubility measurements for KCl, you will use the data to predict its solubility at various temperatures. Go to Appendix C. If you are using a TI-83 Plus, you can download the program and data sets and run the application as directed. Press the APPS key on your calculator, then choose the application CHEMAPPS. Press 3 then highlight ALL on the screen, press 1 , then highlight LOAD and press 2 to load the data into your calculator. Press the keys 2nd and then QUIT, and then run the program \(\mathrm{SOLUBIL}\) . For \(\mathrm{L}_{1}\) press 2nd and LIST and choose SOL21. If you are using another calculator, your teacher will provide you with keystrokes and data sets to use. $$\begin{array}{l}{\text { a. At what temperature would you expect }} \\ {\text { the solubility to be } 48.9 \text { g per } 100 \mathrm{g} \mathrm{H}_{2} \mathrm{O} \text { ? }} \\\ {\text { b. At what temperature would you expect }} \\ {\text { the solubility to be } 35 \mathrm{g} \text { per } 100 \mathrm{g} \mathrm{H}_{2} \mathrm{O} \text { ? }} \\ {\text { c. What would you expect the solubility to }} \\ {\text { be at a temperature of } 100^{\circ} \mathrm{C} ?}\end{array}$$
What is the molarity of a solution that contains 20.0 g \(\mathrm{NaOH}\) in 2.00 \(\mathrm{L}\) of solution?
Write a paragraph explaining what happens to an ionic salt in the following steps: it is dissolved in water, more of it than its solubility amount is added to the solution, the solution is heated, the solution is cooled to room temperature, and the solution is disturbed by adding more solute.
Calculate the mass of LiF in 100.0 \(\mathrm{mL}\) of 0.100 \(\mathrm{M}\) solution.
How many milliliters of 1.0 \(\mathrm{M} \mathrm{AgNO}_{3}\) are needed to provide 168.88 \(\mathrm{g}\) of pure \(\mathrm{AgNO}_{3} ?\)
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