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Chapter 12: Problem 35

A gas sample has a volume of 125 \(\mathrm{mL}\) at 91.0 \(\mathrm{kPa}\) . What will its volume be at 101 \(\mathrm{kPa}\) ?

Short Answer

Expert verified
The volume of the gas at 101 kPa is approximately 113 mL

Step by step solution

01

Identify and write down all the known and unknown variables

The known variables are: Initial Volume \(V1 = 125 mL\), Initial Pressure \(P1 = 91.0 kPa\), Final Pressure \(P2 = 101 kPa\). The unknown variable is the Final Volume (V2), which is what we are trying to find.
02

Insert the known values into Boyle's Law

By inserting the known values into Boyle's Law, it becomes: \(91.0 kPa * 125 mL = 101 kPa * V2\)
03

Solve for the unknown variable V2

To solve for V2, simply divide both sides of the equation by 101 kPa, so: \(V2 = (91.0 kPa * 125 mL) / 101 kPa\)

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