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The first and second ionization energies of \(\mathrm{K}\) are \(419 \mathrm{~kJ} / \mathrm{mol}\) and \(3052 \mathrm{~kJ} / \mathrm{mol}\), and those of \(\mathrm{Ca}\) are \(590 \mathrm{~kJ} / \mathrm{mol}\) and \(1145 \mathrm{~kJ} / \mathrm{mol}\), respectively. Compare their values and comment on the differences.

Short Answer

Expert verified
Ca has a higher first ionization energy than K because of its greater nuclear charge. K has a higher second ionization energy due to the removal of a much more tightly held electron from the lower energy level after the first ionization.

Step by step solution

01

Comparing First Ionization Energies

The first ionization energy of K is 419 kJ/mol, and that of Ca is 590 kJ/mol. Thus, Ca has a higher first ionization energy than K.
02

Comparing Second Ionization Energies

The second ionization energy of K is 3052 kJ/mol, while that of Ca is 1145 kJ/mol. Thus, K has a higher second ionization energy than Ca.
03

Discussion on Differences

The differences in these values can be explained in relation to the atomic structure of these elements. Ca has a larger first ionization energy than K because Ca has a greater nuclear charge, which affects the attraction between the nucleus and the outermost electron. The second ionization energy of K is especially high because after the first ionization, K loses its sole electron in the outermost energy level, revealing a much more tightly held electron from the lower energy level. For Ca, losing a second electron is relatively easier because it still has two electrons in its outermost energy level after the first ionization, causing the second ionization energy to be lower.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First Ionization Energy
The first ionization energy is defined as the amount of energy required to remove the most loosely bound electron from a neutral atom in its gaseous state. It's a fundamental property that reflects the interaction between the electron being removed and the nucleus. The first ionization energy of an element like potassium (K) is lower than that of calcium (Ca), indicating that it's easier to remove the outermost electron from a potassium atom than from a calcium atom.

Several factors affect the magnitude of the first ionization energy. These include the atomic number, which is directly related to the nuclear charge, and the distance of the valence electron from the nucleus. Generally, first ionization energy increases across a period on the periodic table because the nuclear charge increases, pulling the electrons in closer and making them harder to remove. Conversely, it decreases down a group as the added electron shells reduce the pull from the nucleus due to increased electron shielding.
Second Ionization Energy
Second ionization energy refers to the energy required to remove a second electron after the first has been removed. This energy is typically higher than the first ionization energy because the electron is being removed from a positively charged ion, which holds onto the remaining electrons more tightly. In the comparison of K to Ca, potassium's second ionization energy is significantly higher than its first, due to the electron being removed from a smaller, more tightly bound energy level after the loss of the first electron.

For calcium, the drop in second ionization energy compared to potassium is explained by the electron configuration. After losing its first electron, calcium still has another electron in the same energy level, which feels a similar level of attraction to the nucleus and therefore requires less additional energy to remove than in the case of potassium, which exposes an electron from a closer orbit.
Atomic Structure
Atomic structure pertains to the organization of protons, neutrons, and electrons within an atom. Protons and neutrons form the nucleus at the center of the atom, while electrons orbit around the nucleus in various energy levels or 'shells.' The differences in ionization energies between K and Ca can be largely attributed to their atomic structures. Potassium has one valence electron in its outermost shell, which is easier to remove, contributing to a lower first ionization energy.

In contrast, the higher first ionization energy of calcium is because it has two valence electrons in its outer shell and a larger nuclear charge. The increase in the number of inner electrons, which shield the valence electrons from the nucleus, can affect ionization energies. The atomic structure directly correlates with how tightly an electron is held by the atom, illustrating why removing electrons from different elements requires varying amounts of energy.
Nuclear Charge
Nuclear charge, often denoted as 'Z,' is the total charge of the nucleus equal to the number of protons in the atom's nucleus. It has a significant influence on an atom's ionization energy. A higher nuclear charge typically results in a greater attraction between the nucleus and electrons, hence a higher ionization energy. Because calcium (Ca) has more protons than potassium (K), it has a higher nuclear charge and thus a higher first ionization energy.

It's important to note that the effects of nuclear charge are partially offset by electron shielding or screening, where inner-shell electrons reduce the effective nuclear charge felt by the outer-shell electrons. However, as electrons are removed through ionization, this electron shielding diminishes, leading to a more substantial increase in ionization energy, which is especially evident in the increased second ionization energy.

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Most popular questions from this chapter

In the late 1800 s the British physicist Lord Rayleigh accurately determined the atomic masses of a number of elements, but he obtained a puzzling result with nitrogen. One of his methods of preparing nitrogen was by the thermal decomposition of ammonia: \( 2 \mathrm{NH}_{3}(g) \longrightarrow \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \) Another method was to start with air and remove oxygen, carbon dioxide, and water vapor from it. Invariably, the nitrogen from air was a little denser (by about 0.5 percent) than the nitrogen from ammonia. Later the English chemist Sir William Ramsay carried out an experiment in which he passed nitrogen, which he had obtained from air by Raleigh's procedure, over red-hot magnesium to convert it to magnesium nitride: \(3 \mathrm{Mg}(s)+\mathrm{N}_{2}(g) \longrightarrow \mathrm{Mg}_{3} \mathrm{~N}_{2}(s)= \)= After all of the nitrogen had reacted with magnesium, Ramsay was left with an unknown gas that would not combine with anything. The atomic mass of this gas was determined to be 39.95 amu. Ramsay called the gas argon, which means "the lazy one" in Greek. (a) Later Rayleigh and Ramsay, with the help of Sir William Crookes, the inventor of the discharge tube, showed that argon was a new element. Describe the type of experiment performed that led them to the conclusion. (b) Why did it take so long to discover argon? (c) Once argon had been discovered, why did it take relatively little time to discover the rest of the noble gases? (d) Why was helium the last noble gas to be discovered on Earth? (e) The only confirmed compound of radon is radon fluoride, \(\mathrm{RnF}\). Give two reasons why there are so few known radon compounds.

Indicate whether these elements exist as atomic species, molecular species, or extensive three dimensional structures in their most stable state at \(25^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm},\) and write the molecular or empirical formula for the elements: phosphorus, iodine, magnesium, neon, arsenic, sulfur, carbon, selenium, and oxygen.

Use the alkali metals and alkaline earth metals as examples to show how we can predict the chemical properties of elements simply from their electron configurations.

For each pair of elements listed here, give three properties that show their chemical similarity: (a) sodium and potassium and (b) chlorine and bromine.

With reference to the periodic table, name (a) a halogen element in the fourth period, (b) an element \(\operatorname{sim}\) ilar to phosphorus in chemical properties, (c) the most reactive metal in the fifth period, \((\) d) an element that has an atomic number smaller than 20 and is similar to strontium.

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