/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 A gas-filled balloon having a vo... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A gas-filled balloon having a volume of \(2.50 \mathrm{~L}\) at \(1.2 \mathrm{~atm}\) and \(25^{\circ} \mathrm{C}\) is allowed to rise to the stratosphere (about \(30 \mathrm{~km}\) above the surface of Earth), where the temperature and pressure are \(-23^{\circ} \mathrm{C}\) and \(3.00 \times 10^{-3}\) atm, respectively. Calculate the final volume of the balloon.

Short Answer

Expert verified
The final volume of the balloon when it reaches the stratosphere is 250 L.

Step by step solution

01

Convert Celsius temperatures to Kelvin

Temperatures must be in Kelvin for the ideal gas law to be applicable. Convert the initial and final temperatures from Celsius to Kelvin using the formula \(K = ^\circ C + 273.15\). So the initial temperature T1 is \(25^\circ C + 273.15 = 298.15 K\) and the final temperature, T2, is \(-23^\circ C + 273.15 = 250.15 K\).
02

Input values into the combined gas law

Rearrange the formula \(P_1V_1/T_1 = P_2V_2/T_2\) to solve for the final volume, \(V_2\). This gives you \(V_2 = P_1V_1T_2/(T_1P_2)\). Substitute in the given values of \(P_1 = 1.2 atm\), \(V_1 = 2.5 L\), \(T_1 = 298.15 K\), \(P_2 = 3.00 × 10^{-3} atm\) and \(T_2 = 250.15 K\).
03

Calculate the final volume

Now, calculate the final volume, \(V_2\), by multiplying and dividing the inserted values: \(V_2 = (1.2 atm × 2.5 L × 250.15 K) / (298.15 K × 3.00 × 10^{-3} atm) = 250 L\). Therefore, the final volume of the balloon when it reaches the stratosphere is 250 L.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The Ideal Gas Law is a fundamental equation in chemistry and physics that relates the pressure, volume, temperature, and quantity of an ideal gas. It is expressed in the form \( PV = nRT \), where:
  • \(P\) represents the pressure of the gas.
  • \(V\) is the volume the gas occupies.
  • \(n\) denotes the amount of gas in moles.
  • \(R\) is the ideal gas constant, with a typical value of 0.0821 \(L \, atm \, mol^{-1} \, K^{-1}\).
  • \(T\) is the temperature in Kelvin.
When dealing with gas problems, conversions to Kelvin are necessary because the gas laws only apply when temperature is measured on an absolute scale. The Ideal Gas Law forms the basis for understanding how gases behave under varying conditions and is also pivotal for deriving other gas laws, including the combined gas law used in the balloon problem.
Thermodynamic Equations
Thermodynamic equations help describe the behavior of gases as they undergo changes in temperature, pressure, and volume. These equations are rooted in the laws of thermodynamics, which govern the principles of energy transfer and equilibrium. In the context of the Combined Gas Law, one key thermodynamic perspective is the relationship between energy changes and state variables like pressure and volume. The balloon's volume changes as it rises, due to reduced pressure and temperature, reflecting the interplay of these variables described by thermodynamic equations. Another important concept is the understanding of how temperature influences molecular motion within the balloon. As the balloon ascends, the lower temperature slows molecular motion, causing the gas to occupy a greater volume to maintain equilibrium.
Gas Laws
Gas Laws are a collection of laws describing how gases behave, relating to volume, pressure, and temperature. The primary gas laws include Boyle's Law, which states that pressure and volume are inversely related at constant temperature, Charles's Law, which states that volume and temperature are directly related at constant pressure, and Avogadro's Law, which addresses the direct relationship between volume and amount of gas at constant temperature and pressure.In situations where a gas undergoes simultaneous changes, the Combined Gas Law, expressed as \( \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2} \), is used. It integrates Boyle's, Charles's, and Gay-Lussac's laws to account for changes in all three variables. While solving the balloon problem, using the Combined Gas Law allowed us to compute the change in volume as pressure and temperature simultaneously shifted, showcasing the versatile nature of gas laws in explaining real-world phenomena.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Dissolving \(3.00 \mathrm{~g}\) of an impure sample of calcium carbonate in hydrochloric acid produced \(0.656 \mathrm{~L}\) of carbon dioxide (measured at \(20.0^{\circ} \mathrm{C}\) and \(792 \mathrm{mmHg}\) ). Calculate the percent by mass of calcium carbonate in the sample. State any assumptions.

Dry air near sea level has the following composition by volume: \(\mathrm{N}_{2}, 78.08\) percent; \(\mathrm{O}_{2}, 20.94\) percent; \(\mathrm{Ar},\) 0.93 percent; \(\mathrm{CO}_{2}, 0.05\) percent. The atmospheric pressure is \(1.00 \mathrm{~atm} .\) Calculate (a) the partial pressure of each gas in atm and (b) the concentration of each gas in moles per liter at \(0^{\circ} \mathrm{C}\).

Propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)\) burns in oxygen to produce carbon dioxide gas and water vapor. (a) Write a balanced equation for this reaction. (b) Calculate the number of liters of carbon dioxide measured at STP that could be produced from \(7.45 \mathrm{~g}\) of propane.

One way to gain a physical understanding of \(b\) in the van der Waals equation is to calculate the "excluded volume." Assume that the distance of closest approach between two similar atoms is the sum of their radii \((2 r) .\) (a) Calculate the volume around each atom into which the center of another atom cannot penetrate. (b) From your result in (a), calculate the excluded volume for 1 mole of the atoms, which is the constant \(b\). How does this volume compare with the sum of the volumes of 1 mole of the atoms?

Why is the density of a gas much lower than that of a liquid or solid under atmospheric conditions? What units are normally used to express the density of gases?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.