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Chapter 4: Problem 55

How many moles of \(\mathrm{MgCl}_{2}\) are present in \(60.0 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{MgCl}_{2}\) solution?

Short Answer

Expert verified
The number of moles of \( \mathrm{MgCl}_{2} \) in the solution is 0.0060 moles.

Step by step solution

01

Convert volume to Liters

Since molar concentration is usually given in moles/Liter, it's necessary to convert the volume from milliliters to liters. This is achieved by dividing the given volume by 1000, because 1 Liter is equivalent to 1000 milliliters. Thus, \(60.0 \mathrm{mL} = \frac{60.0}{1000} = 0.060 \mathrm{L}\).
02

Determine the number of moles

Apply the formula of molar concentration defined as \( \mathrm{M} = \frac{moles}{volume} \). From the equation, we can determine the number of moles as \( \mathrm{Moles} = \mathrm{M} * \mathrm{volume} \). Thus, the number of moles of \( \mathrm{MgCl}_{2} \) is \( 0.100 \mathrm{M} * 0.060 \mathrm{L} = 0.0060 \mathrm{moles} \).

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