/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 What is the difference between t... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Problem 4

What is the difference between the following symbols in chemical equations: \(\longrightarrow\) and \(\rightleftharpoons ?\)

Short Answer

Expert verified
In chemistry, the symbol \(\longrightarrow\) is used to denote a complete or irreversible reaction where reactants convert entirely into the products with no reverse reaction. On the other hand, the symbol \(\rightleftharpoons\) represents equilibrium reactions, where reactants and products convert into each other at the same rate, resulting in unchanging concentrations.

Step by step solution

01

Explaining the meaning of the symbol \(\longrightarrow\)

In chemical equations, the symbol \(\longrightarrow\) is used to denote a complete or irreversible reaction. These reactions are ones where reactants convert entirely into products, and there's no reverse reaction.
02

Explaining the meaning of the symbol \(\rightleftharpoons\)

The symbol \(\rightleftharpoons\) thoughtfully represents equilibrium reactions. These are reactions in which the conversion from reactants to products and products to reactants occur simultaneously. Thus, an equilibrium state is defined as a dynamic state where the concentrations of reactants and products are unchanging.
03

Contrasting the two symbols

These two symbols - \(\longrightarrow\) and \(\rightleftharpoons\) - represent significantly different scenarios in chemical reactions. The first one, \(\longrightarrow\), depicts a one-way, complete transformation of reactants into products. In contrast, the second symbol, \(\rightleftharpoons\), illustrates a dynamic state of balance between reactants and products.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Arrange the following species in order of increasing oxidation number of the sulfur atom: (a) \(\mathrm{H}_{2} \mathrm{~S}\) (b) \(\mathrm{S}_{8}\) (c) \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (d) \(\mathrm{S}^{2-},(\mathrm{e}) \mathrm{HS}^{-},(\mathrm{f}) \mathrm{SO}_{2},(\mathrm{~g}) \mathrm{SO}_{3}\)

Give Arrhenius's and Bronsted's definitions of an acid and a base. Why are Bronsted's definitions more useful in describing acid-base properties?

A \(60.0-\mathrm{mL} 0.513 \mathrm{M}\) glucose \(\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)\) solution is mixed with \(120.0 \mathrm{~mL}\) of \(2.33 \mathrm{M}\) glucose solution. What is the concentration of the final solution? Assume the volumes are additive.

Water is an extremely weak electrolyte and therefore cannot conduct electricity. Why are we often cautioned not to operate electrical appliances when our hands are wet?

Calculate the molarity of each of the following solutions: (a) \(29.0 \mathrm{~g}\) of ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) in \(545 \mathrm{~mL}\) of solution, (b) \(15.4 \mathrm{~g}\) of sucrose \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)\) in \(74.0 \mathrm{~mL}\) of solution, (c) \(9.00 \mathrm{~g}\) of sodium chloride \((\mathrm{NaCl})\) in \(86.4 \mathrm{~mL}\) of solution.
See all solutions

Recommended explanations on Chemistry Textbooks

Chemical Analysis

Read Explanation

Organic Chemistry

Read Explanation

Inorganic Chemistry

Read Explanation

Chemistry Branches

Read Explanation

Making Measurements

Read Explanation

Ionic and Molecular Compounds

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.