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Chapter 4: Problem 11

The passage of electricity through an electrolyte solution is caused by the movement of (a) electrons only, (b) cations only, (c) anions only, (d) both cations and anions.

Short Answer

Expert verified
The passage of electricity through an electrolyte solution is caused by the movement of both cations and anions

Step by step solution

01

Understanding electrolyte solution

An electrolyte solution is a solution that conducts electricity. It contains dissolved ions. These ions are cations (positively charged ions) and anions (negatively charged ions). Electrolyte solutions can conduct electricity because of the movement of these ions.
02

Identifying key concepts

In the process of electrolysis, an electric current is passed through the electrolyte solution. This causes the cations and anions to move towards the electrodes of opposite charge. The cations move towards the cathode (negative electrode) and the anions move towards the anode (positive electrode). Thus, it is the movement of both cations and anions that allows for the passage of electricity through an electrolyte solution.
03

Answering the question

Given this information, it can be concluded that the statement (d) 'both cations and anions' is correct. That is, the passage of electricity through an electrolyte solution is caused by the movement of both cations and anions.

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Most popular questions from this chapter

Describe how to prepare \(1.00 \mathrm{~L}\) of \(0.646 \mathrm{M} \mathrm{HCl}\) solution, starting with a \(2.00 \mathrm{M} \mathrm{HCl}\) solution.

Classify these reactions according to the types discussed in the chapter: (a) \(\mathrm{Cl}_{2}+2 \mathrm{OH}^{-} \longrightarrow \mathrm{Cl}^{-}+\mathrm{ClO}^{-}+\mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{Ca}^{2+}+\mathrm{CO}_{3}^{2-} \longrightarrow \mathrm{CaCO}_{3}\) (c) \(\mathrm{NH}_{3}+\mathrm{H}^{+} \longrightarrow \mathrm{NH}_{4}^{+}\) (d) \(2 \mathrm{CCl}_{4}+\mathrm{CrO}_{4}^{2-} \longrightarrow\) \(2 \mathrm{COCl}_{2}+\mathrm{CrO}_{2} \mathrm{Cl}_{2}+2 \mathrm{Cl}^{-}\) (e) \(\mathrm{Ca}+\mathrm{F}_{2} \longrightarrow \mathrm{CaF}_{2}\) (f) \(2 \mathrm{Li}+\mathrm{H}_{2} \longrightarrow 2 \mathrm{LiH}\) (g) \(\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}+\mathrm{Na}_{2} \mathrm{SO}_{4} \longrightarrow 2 \mathrm{NaNO}_{3}+\mathrm{BaSO}_{4}\) (h) \(\mathrm{CuO}+\mathrm{H}_{2} \longrightarrow \mathrm{Cu}+\mathrm{H}_{2} \mathrm{O}\) (i) \(\mathrm{Zn}+2 \mathrm{HCl} \longrightarrow \mathrm{ZnCl}_{2}+\mathrm{H}_{2}\) (j) \(2 \mathrm{FeCl}_{2}+\mathrm{Cl}_{2} \longrightarrow 2 \mathrm{FeCl}_{3}\)

Give an example of a monoprotic acid, a diprotic acid, and a triprotic acid.

You have \(505 \mathrm{~mL}\) of a \(0.125 \mathrm{M} \mathrm{HCl}\) solution and you want to dilute it to exactly \(0.100 M\). How much water should you add?

Write the equation that enables us to calculate the concentration of a diluted solution. Give units for all the terms.
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